Find the value of x such that:\(\frac{3}{2x+7}=\frac{5}{3x+9}\)
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Find the value of x such that: \(\frac{5}{7-2x}=\frac{3}{x-3}\)
Find the value of x such that \(\frac{x-7}{6}+\frac{x-11}{10}=\frac{x-8}{7}+\frac{x-10}{9}\)
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Answer: .x=..
Ta có
\(\frac{x-7}{6}+1+\frac{x-11}{10}+1=\frac{x-8}{7}+1+\frac{x-10}{9}+1\)
\(\frac{x-1}{6}+\frac{x-1}{10}-\frac{x-1}{7}-\frac{x-1}{9}=0\)
<=>\(\left(x-1\right)\left(\frac{1}{6}+\frac{1}{10}-\frac{1}{7}-\frac{1}{11}\right)=0\)
=>x-1=0
<=>x=1
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find the value of n such that the polynomial 2x^5 - 3x^3 + x^2 +n is divisible by the polynomial x+2
tìm giá trị của n sao cho đa thức 2x ^ 5 - 3x ^ 3 + x ^ 2 + n chia hết cho đa thức x + 2
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Find the value of x such that: \(\frac{3\left(x+2\right)}{2x+3}=\frac{7}{8},\left(x\ne-\frac{3}{2}\right)\) . Answer: x = ...
( write your answer by decimal in simplest form )
Find the value of x such that A=\(\frac{5x^2-8x+8}{2x^2}\) reaches the minimun value.
Find the value of x, such that:
\(\frac{x-7}{6}+\frac{x-11}{10}=\frac{x-8}{7}+\frac{x-10}{9}\)
Help cái koi, Nhọ Nồi ôg onl thì lm giúp cái !
\(\frac{x-7}{6}+\frac{x-11}{10}=\frac{x-8}{7}+\frac{x-10}{9}\)
\(\Rightarrow\left(\frac{x-7}{6}+1\right)+\left(\frac{x-11}{10}+1\right)=\left(\frac{x-8}{7}+1\right)+\left(\frac{x-10}{9}+1\right)\)
\(\Rightarrow\frac{x-1}{6}+\frac{x-1}{10}-\frac{x-1}{7}-\frac{x-1}{9}=0\)
\(\left(x-1\right).\left(\frac{1}{6}+\frac{1}{10}-\frac{1}{7}-\frac{1}{9}\right)=0\)
\(\Rightarrow x-1=0\Rightarrow x=1\)
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Find the value of x such that\(\frac{3}{x-2}=\frac{2}{x-3}\)
\(3\cdot\left(x-3\right)=2\cdot\left(x-2\right)\)
\(3x-9=2x-4\)
\(3x-2x=4+9\)
\(x=13\)
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Find the smallest value of x such that: 2x+3>5
Find the value of x such that .\(\frac{x+3}{7}=\frac{2-x}{3}\)
Answer: .x=.....
(write your answer by decimal in simplest form)
=>3(x+3)=7.(2-x)
=>3x+9=14-2x
=>3x+2x=14-9
=>5x=5=>x=1
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