Bài 1:

2^\(x\) = 4

2\(^x\) = 2²

 \(x=2\)

Vậy \(x=2\)

Bài 2:

2\(^x\) = 8

2\(^x\) = 2³

\(x=3\)

Vậy \(x=3\)

Bài 3

2\(^x\) = 16

2\(^x\) = 2⁴

  \(x=4\)

Vậy \(x=4\)

 Bài 1:

1; 5\(x\) + \(x\) = 39 - 3¹¹ : 3⁹

    \(x\).(5 + 1) = 39 - 3²

    \(x.6\)        = 39 - 9

   \(x.6\)         = 30

   \(x\)           = 30 : 6

   \(x\)          = 5

Vậy \(x\) = 5

2; 5\(x\) + \(x\) = 150 : 2 + 3

    \(x\).(5 + 1) = 75 + 3

    \(x.6\)          = 78

    \(x\)             = 78 : 6

     \(x\)            = 13

Vậy \(x=13\) 

3;      7\(x\) - \(x\) = 5²¹ : 5¹⁹ + 3.2² - 1

    \(x.\left(7-1\right)\) = 5² + 6 - 1

    \(x\).6 = 25 + 6 - 1

    \(x.6\) = 31 - 1

   \(x.6\) = 30

   \(x\)    = 30 : 6

    \(x=5\)

Vậy \(x=5\)

a, ( 2x - 3 )²- (2x + 1)² = -3

4x²-12x+9-4x²+4x-1=-3

-8x-1=-3

-8x=-2

x=\(\frac{1}{4}\)

b, (5x - 1) ² - (5x + 4)(5x - 4) = 7

25x²-10x+1-25x²+16=7

-10x+17=7

-10x=-10

x=1

c, ( x- 5)² + (x-3)(x+3) - 2(x + 1)²=0

x²-10x+25+x²-9-2x²-4x-2=0

-14x+14=0

-14(x-1)=0

=>x-1=0

x=1

a) \(\left(2x-3\right)^2-\left(2x+1\right)^2=-3\)

\(\Leftrightarrow4x^2-12x+9-4x^2-4x-1=-3\)

\(\Leftrightarrow-16x+8=-3\)

\(\Leftrightarrow-16x=-11\)

\(\Leftrightarrow x=\frac{11}{16}\)

b)\(\left(5x-1\right)^2-\left(5x+4\right)\left(5x-4\right)=7\)

\(\Leftrightarrow25x^2-10x+1-25x^2+16=7\)

\(\Leftrightarrow-10x+17=7\)

\(\Leftrightarrow-10x=-10\)

\(\Leftrightarrow x=1\)

c)\(\left(x-5\right)^2+\left(x-3\right)\left(x+3\right)-2\left(x+1\right)^2=0\)

\(\Leftrightarrow x^2-10x+25+x^2-9-2\left(x^2+2x+1\right)=0\)

\(\Leftrightarrow2x^2-10x-16-2x^2-4x-2=0\)

\(\Leftrightarrow-14x-18=0\)

\(\Leftrightarrow-14x=18\)

\(\Leftrightarrow x=-\frac{9}{7}\)

#H

a)x+15=-7

x=(-7)-15

x=-22

b)\(\left(5x-2\right).8^3=8^4\)

(5x-2).512=4096

(5x-2)=4096:512

(5x-2)=8

5x=8+2

5x=10

x=10:5

x=2

c)|x-1|=2

=>x-1=2      hoac   x-1=-2

x=2+1                    x=-2+1

x=3                          x=-1

a/ => x = (-7) - 15 = -22

Vậy x = -22

b/ (5x - 2) . 8³ = 8⁴

=> 5x - 2 = 8

=> 5x = 10

=> x = 2

Vậy x = 2

c/ => x - 1 = 2 => x = 3

hoặc x - 1 = -2 => x = -1

Vậy x = 3 ; x = -1

may cai bai day ma cung khong biet oc cho

a) 89-(73-x)=20

=>73-x=89-20

=>73-x=69

=>x=73-69

=>x=4

Dài quá bn ơi, vs lại mấy cái này cx ko khó lắm đâu (nếu ko lm đc đăng mỗi lần một ít thui chứ dài quá mk đọc cn lười chứ đừng ns là làm)

a)100-7.[x-5]=58

          7.[x-5]=100-58=42

               x-5=42:7=6

                  x=6+5

                  x=11

b)12.[x-1]:3=4³+2³

   12 [x-1]:3=64+8

   12.[x-1]:3=72

        [x-1]:3=72:12=6

           [x-1]=6.3=18

                x=18-1

                x=17

tao koooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooo biếtttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttt