311 : 39 – 147 : 72
a) 311 : 39 – 147 : 72
b) 295 – (31 – 22.5)2
c) 718 : 716 +22.33
a)3\(^{11}\):3\(^9\)−147:7\(^2\)
=3\(^{11}\)\(^{-9}\)−147:49
=3\(^2\)−147:49
=9−3
=6
b)295−(31−22×5)w)295-(31-22×5)
=295−(31−2\(^2\).5)\(^2\)
=295−11\(^2\)
=295−121
=174
a) 29 – [16 + 3.(51 – 49)]
b) 5.22 + 98:72
c) 311 : 39 – 147 : 72
d) 295 – (31 – 22.5)2
718 : 716 +22.33
b: =20+98:49
=20+2
=22
c: =9-147:49
=9-3
=6
a) 513 : 510 – 25.22
b) 20 : 22 + 59 : 58
c) 100 : 52 + 7.32
d) 84 : 4 + 39 : 37 + 50
e) 29 – [16 + 3.(51 – 49)]
f) 5.22 + 98:72
g) 311 : 39 – 147 : 72
h) 295 – (31 – 22.5)2
718 : 716 +22.33
\(a)\) \(5^{13}:5^{10}-25.2^2=5^3-25.4=125-100=25\)
\(b)\) \(20:2^2+5^9:5^8=20:4+5^1=5+5=10\)
\(c)\) \(100:5^2+7.3^2=100:25+7.9=4+36=40\)
\(d)\) \(84:4+3^9:3^7+5^0=84:4+3^2+1=21+9+1=31\)
\(e)\)
\(29-\left[16+3.\left(51-49\right)\right]=29-\left[16+3.2\right]=29-\left[16+6\right]=29-22=7\)
\(f)\) \(5.2^2+98:7^2=5.4+98:49=20+2=22\)
\(g)\) \(3^{11}:3^9-147:7^2=3^2-147:49=9-3=6\)
\(295-\left(31-2^2.5\right)^2=295-\left(31-4.5\right)^2=295-\left(31-20\right)^2=295-11^2=295-121=174\)
\(7^{18}:7^{16}+2^2.3^2=7^2+4.9=49+36=85\)
a: \(5^{13}:5^{10}-25\cdot2^2\)
\(=5^3-25\cdot4\)
=125-100
=25
b: \(20:2^2+5^9:5^8\)
\(=20:4+5\)
=5+5
=10
Bài2:Thựchiệnphéptính:
a. (519 : 517 + 3) : 7 b. 79 : 77 – 32 + 23.52 c. 1200 : 2 + 62.21 + 18 d. 59 : 57 + 70 : 14 – 20
| e. 32.5 – 22.7 + 83 f. 59 : 57 + 12.3 + 70 g. 5.22 + 98:72 h. 311 : 39 – 147 : 72 | i. 295 – (31 – 22.5)2 j. 151 – 291 : 288 + 12.3 k. 238 : 236 + 51.32 - 72 l. 791 : 789 + 5.52 – 124 m. 4.15 + 28:7 – 620:618 |
a: \(\left(5^{19}:5^{17}+3\right):7=\left(5^2+3\right):7=4\)
b: \(7^9:7^7-3^2+2^3\cdot5^2\)
\(=7^2-3^2+8\cdot25\)
=49-9+200
=240
c: \(1200:2+6^2\cdot2^1+18\)
\(=600+72+18\)
=690
Bài 1: Thực hiện phép tính: a) 3.52 + 15.22 – 26:2 b) 53.2 – 100 : 4 + 23.5 c) 62 : 9 + 50.2 – 33.3 d) 32.5 + 23.10 – 81:3 e) 513 : 510 – 25.22 f) 20 : 22 + 59 : 58 g) 100 : 52 + 7.32 h) 84 : 4 + 39 : 37 + 50 i) 29 – [16 + 3.(51 – 49)] j) (519 : 517 + 3) : 7 k) 79 : 77 – 32 + 23.52 l) 1200 : 2 + 62.21 + 18 m) 59 : 57 + 70 : 14 – 20 n) 32.5 – 22.7 + 83 o) 59 : 57 + 12.3 + 70 p) 5.22 + 98 : 72 q) 311 : 39 – 147 : 72 r) 295 – (31 – 22.5)2 s) 151 – 291 : 288 + 12.3 t) 238 : 236 + 51.32 - 72 u) 791 : 789 + 5.52 – 124 v) 4.15 + 28:7 – 620 : 618 w) (32 + 23.5) : 7 x) 1125 : 1123 – 35 : (110 + 23) – 60 y) 520 : (515.6 + 515.19) z) 718 : 716 +22.33 aa) 59.73 - 302 + 27.59
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Giải bài sau:
22/9 + 72/11 +70/9 + 147/11
\(\dfrac{22}{9}\) + \(\dfrac{72}{11}\) + \(\dfrac{70}{9}\) + \(\dfrac{147}{11}\)
= (\(\dfrac{22}{9}\) + \(\dfrac{70}{9}\)) + (\(\dfrac{72}{11}\) + \(\dfrac{147}{11}\))
= \(\dfrac{92}{9}\) + \(\dfrac{219}{11}\)
= \(\dfrac{2983}{99}\)
180:{(-30)+[42.5-(14+311:39)]}
\(180:\left\{\left(-30\right)+\left[4^2.5-\left(14+3^{11}:3^9\right)\right]\right\}\)
\(=180:\left\{\left(-30\right)+\left[16.5-\left(14+3^{11}.\dfrac{1}{3^9}\right)\right]\right\}\)
\(=180:\left\{\left(-30\right)+\left[80-\left(14+3^2\right)\right]\right\}\)
\(=180:\left\{\left(-30\right)+\left[80-\left(14+9\right)\right]\right\}\)
\(=180:\left[\left(-30\right)+80-23\right]\)
\(=180:27\\ =\dfrac{20}{3}\)
Tính hợp lí:
a ) 2 7 − 3 11 + 5 7 − 8 11 ; b ) 6 21 − 12 44 + 10 14 − 24 33 − 1 c ) − 7 2 + 11 9 − 1 4 + 7 9 ; d ) 1 − − 14 4 + 33 27 − 6 24 + 28 36
5x-1 + 311 : 39 = 34
43 . 4x-1 = 64
\(4^3\cdot4^{x-1}=64\)
\(\Leftrightarrow4^{x-1}=1\)
\(\Leftrightarrow x-1=0\)
hay x=1