tìm x biết :
a,5x=125
b,(19x+2.5):14=(13-8)2-42
tìm x biết : ( 19x + 2.5^2 ) : 14 = ( 13 - 8 ) ^ 2 - 4 ^2
( 19x + 2.52 ) : 14 = ( 13 - 8 )2- 4 2
( 19x + 2.52 ) : 14 = 52- 4 2
( 19x + 2.52 ) : 14 = 25- 16
( 19x + 2.52 ) : 14 =9
( 19x + 50 ) : 14 =9
19x + 50=9 . 14
19x + 50=126
19x=126-50
19x=76
x=76:19
x=4
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gan gon hon nha
(19x+2*5^2)/14=(13-8)^2-4^
(19x+2*25)/14=(13-8)^2-16
(19x+2.25)/14=5^-16
(19x+2.25)/14=25-16
(19+2.25)=9*14
19X=126+50
x=76/19
x=4
tìm x:
a. (19x+2.52):14=(13-8)2-42
b) 2.3x=10.312+8.274
Tìm x biết:\(\left(19x+2.5^2\right):14=\left(13-8\right)^2-4^2\)
\(\left(19x+2.5^2\right):14=\left(13-8\right)^2-4^2\)
\(\Rightarrow\left(19x+50\right):14=25-16\)
\(\Rightarrow19x+50=9.14=126\)
\(\Rightarrow19x=76\)
\(\Rightarrow x=76:19=4\)
(19x+2.5²):14 =(13-8)²-4²
(19x + 50):14 = 5²-4²
(19x + 50):14 = 9
19x + 50 = 9.14
19x+50 = 126
19x =76
x =76:19
x =4
Chúc các bn học tốt ah🥰🥰
tìm x biết
\(\frac{19x+2.5^2}{14}=\left[13-8\right]^2-4^2\)
Ta có :
\(\frac{19x+2.5^2}{14}=\left(13-8\right)^2-4^2\)
\(\Leftrightarrow\)\(\frac{19x+2.25}{14}=5^2-4^2\)
\(\Leftrightarrow\)\(\frac{19x+50}{14}=25-16\)
\(\Leftrightarrow\)\(\frac{19x+50}{14}=9\)
\(\Leftrightarrow\)\(19x+50=126\)
\(\Leftrightarrow\)\(19x=76\)
\(\Leftrightarrow\)\(x=\frac{76}{19}\)
\(\Leftrightarrow\)\(x=4\)
Vậy \(x=4\)
Tìm x
(19x+2.52) :14= (13-8)2 - 42
\(\left(19x+2.5^2\right):14=\left(13-8\right)^2-4^2\)
\(\Rightarrow\left(19x+50\right):14=5^2-4^2\)
\(\Rightarrow\left(19x+50\right):14=9\)
\(\Rightarrow19x+50=126\)
\(\Rightarrow19x=76\)
\(\Rightarrow x=4\)
Vậy x = 4
#Kễnh
tìm x
(19x+2.52):14-=(13-8)2-4
Ta có : \(\left(19x+2\cdot5^2\right):14=\left(13-8\right)^2-4\)
\(\Leftrightarrow\left(19x+2\cdot25\right):14=5^2-4\)
\(\Leftrightarrow\left(19x+50\right)=21\cdot14\)
\(\Leftrightarrow19x+50=294
\)
\(\Leftrightarrow19x=294-50\)
\(\Leftrightarrow x=\frac{244}{19}=12\frac{16}{19}\)
( 19x + 2 . 5\(^2\)) : 14 = ( 13 - 8 )\(^2\) - 4
( 19x + 2 . 25 ) : 14 = 5\(^2\)- 4
( 19x + 50 ) : 14 = 25 - 4
( 19x + 50 ) : 14 = 21
19x + 50 = 21 . 14
19x + 50 = 294
19x = 294 - 50
19x = \(\frac{244}{19}\)
Tìm x biết : ( 19x + 2.52 ) : 14 = ( 13 - 8 )2 - 42
( 19x + 2 . 52 ) : 14 = ( 13 - 8 )2 - 42
( 19x + 2 .25 ) : 14 = 52 - 42
( 19x + 100 ) : 14 = 25 - 16
( 19x + 100 ) : 14 = 9
( 19x + 100 ) = 76
19x = -24
x ko tìm đk
\(\text{Tìm x, biết:}\)
\(a\)) \(\left(19x+2.5^2\right):14=\left(13-8\right)^2-4^2\)
\(b\)) \(x+\left(x+1\right)+\left(x+2\right)+...+\left(x+30\right)=1240\)
\(c\)) \(11-\left(-53+x\right)=97\)
\(d\)) \(-\left(x+84\right)+213=-16\)
tìm x biết
a) (19x+2.52):14=(13-8)2-42 b) 2.3x=10.312+8.274
a) ( 19x + 2.52 ) : 14 = ( 13 - 8 )2 - 42
<=> ( 19x + 2 . 25 ) : 14 = 25 - 16
<=> ( 19x + 50 ) : 14 = 9
<=> 19x + 50 = 9 . 14
<=> 19x + 50 = 126
<=> 19x = 126 - 50
<=> 19x = 76
<=> x = 76 : 19
<=> x = 4
a) ( 19x + 2.52 ) : 14 = ( 13 - 8 )2 - 42
<=> ( 19x + 2 . 25 ) : 14 = 25 - 16
<=> ( 19x + 50 ) : 14 = 9
<=> 19x + 50 = 9 . 14
<=> 19x + 50 = 126
<=> 19x = 126 - 50
<=> 19x = 76
<=> x = 76 : 19
<=> x = 4
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