\(\frac{1313}{1717}=\frac{1313:101}{1717:101}=\frac{13}{17}\)

\(\frac{131313}{171717}=\frac{131313:10101}{171717:10101}=\frac{13}{17}\)

lấy máy tính , tính sẽ ra

1313/1717 = 13/17

102102/109109 = 102/109

424242/535353 = 42/53

103103103/109109109 = 103/109

Bài toán được giải như sau :

H = 4116-14/10290-35 = 4102/10255 = 2/5

K = 2/3 ( làm như trên nhưng mình làm vậy cho nó nhanh )

L = -4/3

M = -432/17

Oke xong rồi nhé

hi ko nhớ anh à

có đứa làm hộ rồi đó em

giup ik mà :((
 

1717/2121=17/21

232323/191919=23/19

Ta có : \(\frac{1717}{808}\)= \(\frac{17}{8}\)= \(\frac{119}{56}\)và \(\frac{1313}{707}\)=\(\frac{13}{7}\)=\(\frac{104}{56}\)

Vậy \(\frac{1717}{808}\)=\(\frac{1313}{707}\)

15/17

1515/1717=15.101/17.101=15/17

đáp án là 15/ 17 đó bạn

\(\dfrac{1313}{1717}=\dfrac{101x13}{101x17}=\dfrac{13}{17}\)

\(\dfrac{131313}{171717}=\dfrac{10101x13}{10101x17}=\dfrac{13}{17}\)

Vậy \(\dfrac{1313}{1717}=\dfrac{131317}{171717}\)

\(\dfrac{1313}{1717}và\dfrac{131313}{171717}\\ \dfrac{1313}{1717}=\dfrac{13}{17}\\ \dfrac{131313}{171717}=\dfrac{13}{17}\\ \Rightarrow\dfrac{1313}{1717}=\dfrac{131313}{171717}\)

1313/1717=131313/171717

\(H=\frac{4116-14}{10290-35}=\frac{14.294-14}{35.294-35}=\frac{14.\left(294-1\right)}{35.\left(294-1\right)}=\frac{14.293}{35.293}=\frac{2}{5}\)
\(K=\frac{29.101-101}{2.19.101+4.101}=\frac{101.\left(29-1\right)}{101.\left(38+4\right)}=\frac{28}{42}=\frac{2}{3}\)

\(I=\frac{1313-1717}{303}=\frac{13.101-17.101}{3.101}=\frac{101.\left(13-17\right)}{3.101}=\frac{-4}{3}\)

\(M=\frac{12-24.3}{1-35}=\frac{12-12.2.3}{-34}=\frac{12.\left(1-6\right)}{-34}=\frac{-60}{-34}=\frac{30}{17}\)

\(H\)\(=\) \(\frac{4116-14}{10290-35}\)

       \(=\) \(\frac{4102}{10255}\) 

       \(=\) \(\frac{4102:2051}{10255:2051}\) 

       \(=\) \(\frac{2}{5}\) 

\(K=\frac{2929-101}{2.1919+404}\)

   \(=\) \(\frac{2828}{4242}\) 

   \(=\) \(\frac{2828:1414}{4242:1414}\) 

   \(=\) \(\frac{2}{3}\)  

\(M=\frac{12-24.3}{1-35}\)

    \(=\) \(\frac{-60}{-34}\)

     \(=\) \(\frac{60}{34}\) 

      \(=\) \(\frac{30}{17}\)

:D

\(H=\frac{14\cdot294-14}{35\cdot294-35}=\frac{14\cdot\left(294-1\right)}{35\cdot\left(294-1\right)}=\frac{14}{35}=\frac{2}{5}\)

\(K=\frac{29\cdot101-101}{2\cdot19\cdot101+4\cdot101}=\frac{101\cdot\left(29-1\right)}{101\cdot\left(2\cdot19+4\right)}=\frac{28}{42}=\frac{2}{3}\)

\(I=\frac{13\cdot101-17\cdot101}{3\cdot101}=\frac{101\cdot\left(13-17\right)}{3\cdot101}=\frac{-4}{3}\)

\(M=\frac{12-72}{-34}=\frac{-60}{-34}=\frac{15}{17}\)