1.

a) \(2^x=128\)

\(2^x=2^7\)

\(=>x=7\)

b) \(8^{x-1}=64\)

\(8^{x-1}=8^2\)

\(=>x-1=2\)

\(x=2+1\)

\(=>x=3\)

c) \(3+3^x=30\)

\(3^x=30-3\)

\(3^x=27=3^3\)

\(=>x=3\)

d) \(\left(x+2\right)=64\) -> đề có thiếu không vậy?

e) \(3^2.x=3^5\)

\(x=3^5:3^2\)

\(=>x=3^3=27\)

f) \(\left(2x-1\right)^3=343\)

\(\left(2x-1\right)^3=7^3\)

\(=>2x-1=7\)

\(2x=7+1\)

\(2x=8\)

\(x=8:2\)

\(=>x=4\)

\(#Wendy.Dang\) 

a,\(2^x\)=128           b,\(8^{x-1}\)=64              c,3+\(3^x\)=30           d,x+2=64

\(2^7\)=128               \(8^{x-1}\)=\(8^2\)                 \(3^x\)=30-3                  x=64-2

=>x=7              =>x-1=2                  \(3^x\)=27                      x=62

                         x=2+1=3                \(3^x\)=\(3^3\)

                                                     =>x=3

e,\(3^2\).x=\(3^5\)                             f,(2x-\(1^3\))=343

x=\(3^5\):\(3^2\)                                 2x=1+343

x=27                                     2x=344

                                               x=344:2

                                               x=172

a, | x - 3/4 | = 1/2

=>\(\orbr{\begin{cases}x-\frac{3}{4}=\frac{1}{2}\\x-\frac{3}{4}=-\frac{1}{2}\end{cases}}\)

=>\(\orbr{\begin{cases}x=\frac{1}{2}+\frac{3}{4}\\x=-\frac{1}{2}+\frac{3}{4}\end{cases}}\)

=>\(\orbr{\begin{cases}x=\frac{2}{4}+\frac{3}{4}\\x=-\frac{2}{4}+\frac{3}{4}\end{cases}}\)

=>\(\orbr{\begin{cases}x=\frac{5}{4}\\x=\frac{1}{4}\end{cases}}\)

Vậy....

a) \(|x-\frac{3}{4}|=\frac{1}{2}\)

\(< =>\orbr{\begin{cases}x-\frac{3}{4}=\frac{1}{2}\\x-\frac{3}{4}=-\frac{1}{2}\end{cases}}\)

\(< =>\orbr{\begin{cases}x=\frac{1}{2}+\frac{3}{4}\\x=-\frac{1}{2}+\frac{3}{4}\end{cases}}\)

\(< =>\orbr{\begin{cases}x=\frac{5}{4}\\x=\frac{1}{4}\end{cases}}\)

Vay : x = 5/4 hoặc x =  1/4

b)\(saide\)

Sai de ban oi

\(\frac{\frac{4}{17}-\frac{4}{45}+\frac{4}{156}}{\frac{3}{17}-\frac{3}{45}+\frac{3}{156}}=\frac{4.\left(\frac{1}{17}-\frac{1}{45}+\frac{1}{156}\right)}{3.\left(\frac{1}{17}-\frac{1}{45}+\frac{1}{156}\right)}=\frac{4}{3}\)

thanks Le Tai Bao Chau nha

\(\frac{\frac{4}{17}-\frac{4}{45}+\frac{1}{39}}{\frac{3}{17}-\frac{1}{15}+\frac{1}{52}}\)

\(=\frac{\frac{4}{17}-\frac{4}{45}+\frac{4}{156}}{\frac{3}{17}-\frac{3}{45}+\frac{3}{156}}\)

\(=\frac{\frac{1}{17}.4-\frac{1}{45}.4+\frac{1}{156}.4}{\frac{1}{17}.3-\frac{1}{45}.3+\frac{1}{156}.3}\)

\(=\frac{4\left(\frac{1}{17}-\frac{1}{45}+\frac{1}{156}\right)}{3\left(\frac{1}{17}-\frac{1}{45}+\frac{1}{156}\right)}\)

\(=\frac{4}{3}\)

X = 1 hoặc X = -1

|x|=7 suy ra x=7 hoặc x=-7

2/5 + x = 15/20

2/5 + x = 3/4

x = 3/4 - 2/5 

x = 7/20

8/9 - 2/9 : x = 2/3

2/9 : x = 8/9 - 2/3 

2/9 : x = 2/9

x = 2/9 : 2/9

x = 1

\(\frac{2}{5}+x=\frac{15}{20}\)

\(\frac{2}{5}+x=\frac{3}{4}\)

\(x=\frac{3}{4}-\frac{2}{5}\)

\(x=\frac{7}{20}\)

\(\frac{8}{9}-\frac{2}{9}:x=\frac{2}{3}\)

\(\frac{2}{9}:x=\frac{8}{9}-\frac{2}{3}\)

\(\frac{2}{9}:x=\frac{2}{9}\)

\(x=\frac{2}{9}:\frac{2}{9}\)

\(x=1\)

Mik làm chi tiết nhé, bạn có thể lược 1 số phần nếu thích

\(\frac{2}{5}+x=\frac{15}{20}\)

=>\(\frac{2}{5}+x=\frac{3}{5}\)

=>\(x=\frac{3}{5}-\frac{2}{5}\)

=> \(x=\frac{1}{5}\)

\(\frac{8}{9}-\frac{2}{9}:x=\frac{2}{3}\)

=> \(\frac{8}{9}-\frac{2}{9}:x=\frac{6}{9}\)

=> \(\frac{2}{9}:x=\frac{8}{9}-\frac{6}{9}\)

=>\(\frac{2}{9}:x=\frac{2}{9}\)

=> \(x=\frac{2}{9}:\frac{2}{9}\)

=> \(x=1\)

\(4\left(x-1\right)-3\left(x-2\right)=-5\)

\(\Leftrightarrow4x-4-3x+6=-5\)

\(\Leftrightarrow x=-5+4-6\)

\(\Leftrightarrow x=-7\)

Vậy x=-7

Ta có: 4(x-1) - 3(x-2) = -5

          (4x-4) - (3x-6) = -5

          4x - 4 - 3x + 6 = -5 

     (4x - 3x) + (-4+6) = -5

                       x + 2  = -5

                             x  = -5 - 2

                              x = -7

                         Vậy x = -7

( x + 1 )⁵ = - 32

( x + 1 )⁵ = - 2⁵

=> x + 1 = - 2

=> x = -3 

Study well 

\(\left(x+1\right)^5=-2^5\)

\(\Rightarrow x+1=-2\)

\(\Rightarrow x=-2-1\)

\(\Rightarrow x=-3\)

\(\left(x+1\right)^5=-32\)

\(\Leftrightarrow\left(x+1\right)^5=\left(-2\right)^5\)

\(\Leftrightarrow x+1=-2\)

\(\Leftrightarrow x=-2-1=-3\)