\(\frac{5x^2-10xy+5y^2}{2x^2-2xy+2^2}:\frac{8y-8x}{x^2-xy+y^2}\)
HM
Những câu hỏi liên quan
\(\frac{5x^2-10xy+5^2}{2^2-2xy+2y^2}:\frac{8y-8x}{x^2-xy+y^2}\)
Rút gọn biểu thức :
a) \(\dfrac{x^4-xy^3}{2xy+y^2}:\dfrac{x^3+x^2y+xy^2}{2x+y}\)
b) \(\dfrac{5x^2-10xy+5y^2}{2x^2-2xy+2y^2}:\dfrac{8x-8y}{10x^3+10^3}\)
Tính :
a)\(\dfrac{6x-3}{5x^2+x}.\dfrac{25x^2+10x+1}{1-8x^3}\)
b)\(\dfrac{3x^2-x}{x^2-1}.\dfrac{1-x^4}{\left(1-3x\right)^3}\)
c)\(\dfrac{x^4-xy^3}{2xy+y^2}:\dfrac{x^3+x^2y+xy^2}{2x+y}\)
d) \(\dfrac{5x^2-10xy+5y^2}{2x^2-2xy+2y^2}:\dfrac{8x-8y}{x^3+10y^3}\)
1. Rút gọn biểu thức x(x-y)-y(x+y)+x^2+y^2
2. Phân tích đa thức thành nhân tử :
a) a^3-a^2x-ay^2+xy^2
b) 5x^2-4x+10xy
c) 12x-9--4x^2
d) 8x^3+12x^2y+6xy^2+y^3
e) 5x^2-4x+10xy-8y
3. Điền vào chỗ trống :
a) (1/2x-y)^2=1/4x^2-.....+y^2
bài 4 tính
a, frac{2x^2-10xy}{2xy}+frac{5y-x}{y}
b, frac{2}{x+y}+frac{1}{x-y}+frac{3x}{x^2-y^2}
c, x+y+frac{x^2+y^2}{x+y}
bài 2 .dùng quy tắc biến đổi dấu để tìm MTC rồi thực hiện phếp tính
1a, frac{4}{x+2}+frac{3x-2}{x-2}+frac{5x-6}{4-x^2}
b,frac{1-3x}{2x}+frac{3x-2}{2x-1}+frac{3x-2}{2x-4x^2}
c. frac{x^2+2}{x^3-1}+frac{2}{x^2+x+1}+frac{1}{1-x}
d, frac{2x+y}{2x^2-xy}+frac{16x}{y^2-4x^2}+frac{2x-y}{2x^2+xy}
e,frac{8}{left(x^2+3right)left(x^2-1right)}+frac{2}{x^2+3}+frac{1}{x+1}
Đọc tiếp
bài 4 tính
a, \(\frac{2x^2-10xy}{2xy}\)+\(\frac{5y-x}{y}\)
b, \(\frac{2}{x+y}+\frac{1}{x-y}+\frac{3x}{x^2-y^2}\)
c, x+y+\(\frac{x^2+y^2}{x+y}\)
bài 2 .dùng quy tắc biến đổi dấu để tìm MTC rồi thực hiện phếp tính
1a, \(\frac{4}{x+2}+\frac{3x-2}{x-2}+\frac{5x-6}{4-x^2}\)
b,\(\frac{1-3x}{2x}+\frac{3x-2}{2x-1}+\frac{3x-2}{2x-4x^2}\)
c. \(\frac{x^2+2}{x^3-1}+\frac{2}{x^2+x+1}+\frac{1}{1-x}\)
d, \(\frac{2x+y}{2x^2-xy}+\frac{16x}{y^2-4x^2}+\frac{2x-y}{2x^2+xy}\)
e,\(\frac{8}{\left(x^2+3\right)\left(x^2-1\right)}+\frac{2}{x^2+3}+\frac{1}{x+1}\)
Bài 4:
a) \(\frac{2x^2-10xy}{2xy}+\frac{5y-x}{y}\)
\(=\frac{y.\left(2x^2-10xy\right)}{2xy.y}+\frac{2xy.\left(5y-x\right)}{2xy.y}\)
\(=\frac{2x^2y-10xy^2}{2xy^2}+\frac{10xy^2-2x^2y}{2xy^2}\)
\(=\frac{2x^2y-10xy^2+10xy^2-2x^2y}{2xy^2}\)
\(=\frac{0}{2xy^2}\)
\(=0.\)
b) \(\frac{2}{x+y}+\frac{1}{x-y}+\frac{3x}{x^2-y^2}\)
\(=\frac{2}{x+y}+\frac{1}{x-y}+\frac{3x}{\left(x-y\right).\left(x+y\right)}\)
\(=\frac{2.\left(x-y\right)}{\left(x-y\right).\left(x+y\right)}+\frac{1.\left(x+y\right)}{\left(x-y\right).\left(x+y\right)}+\frac{3x}{\left(x-y\right).\left(x+y\right)}\)
\(=\frac{2x-2y}{\left(x-y\right).\left(x+y\right)}+\frac{x+y}{\left(x-y\right).\left(x+y\right)}+\frac{3x}{\left(x-y\right).\left(x+y\right)}\)
\(=\frac{2x-2y+x+y+3x}{\left(x-y\right).\left(x+y\right)}\)
\(=\frac{6x-y}{\left(x-y\right).\left(x+y\right)}\)
c) \(x+y+\frac{x^2+y^2}{x+y}\)
\(=\frac{x+y}{1}+\frac{x^2+y^2}{x+y}\)
\(=\frac{\left(x+y\right).\left(x+y\right)}{x+y}+\frac{x^2+y^2}{x+y}\)
\(=\frac{\left(x+y\right)^2}{x+y}+\frac{x^2+y^2}{x+y}\)
\(=\frac{x^2+2xy+y^2}{x+y}+\frac{x^2+y^2}{x+y}\)
\(=\frac{x^2+2xy+y^2+x^2+y^2}{x+y}\)
\(=\frac{2x^2+2xy+2y^2}{x+y}.\)
Chúc bạn học tốt!
Tìm các cặp số nguyên (x;y)thỏa mãn
\(a,xy-4x=35-5y\)
\(b,2x^2-2xy+3x-y=59\)
\(c,3x^2+10xy+8y^2=96\)
giải hệ phương trình:
1, \(\left\{{}\begin{matrix}\left(x+y-3\right)^3=4y^3\left(x^2y^2+xy+\frac{45}{4}\right)\\x+4y-3=2xy^2\end{matrix}\right.\)
2, \(\left\{{}\begin{matrix}x^3+7y=\left(x+y\right)^2+x^2y+7x+4\\3x^2+y^2+8y+4=8x\end{matrix}\right.\)
3, \(\left\{{}\begin{matrix}2x+5y=xy+2\\x^2+4y+21=y^2+10x\end{matrix}\right.\)
Phân tích đa thức sau thành nhân tử :
a, -x - y^2 + x^2 - y
b, x( x + y ) - 5x - 5y
c,x^2 - 5x + 5y - y^2
d, 5x^3 - 5x^2 y - 10x^2 + 10xy
e,27x^3 - 8y^3
f, x^2 - y^2 - x - y
g, x^2 - y^2 - 2xy + y^2
h, x^2 - y^2 + 4 - 4x
i, x^6 - y^6
P = x^2 +2y^2 - 2xy + 8x + 8y + 2017
Q = - x^2 - 2y^2 - 2xy + 8x + 6y + 13
E = -x^2 - 4y^2 + 2xy + 2x + 10xy - 3
tìm giá trị lớn nhất
P=\(X^2+2Y^2-2XY+8X+8Y+2017\)
P=\(\dfrac{4X^2+8Y^2-8XY+32Y+32X+8068}{4}\)
P=\(\dfrac{(\sqrt{3}X)^2-2.\sqrt{3}X.\dfrac{4}{\sqrt{3}}Y+\left(\dfrac{4}{\sqrt{3}}Y\right)^2-\left(\dfrac{4}{\sqrt{3}}Y\right)^2+8Y^2+X^2+32X+32Y+8068}{4}\)
P=\(\dfrac{\left(\sqrt{3}X-\dfrac{4}{\sqrt{3}}Y\right)^2+X^2+\dfrac{8}{3}Y^2+32X+32Y+8068}{4}\)
P=\(\dfrac{\left(\sqrt{3}X-\dfrac{4}{\sqrt{3}}Y\right)^2+X^2+2.X.16+16^2+(\dfrac{2\sqrt{2}}{\sqrt{3}}Y)^2+2.\dfrac{2\sqrt{2}}{\sqrt{3}}Y.4\sqrt{6}+\left(4\sqrt{6}\right)^2+7716}{4}\)
P=\(\dfrac{\left(\sqrt{3}X-\dfrac{4}{\sqrt{3}}Y\right)^2+\left(X+16\right)^2+\left(\dfrac{2\sqrt{2}}{\sqrt{3}}Y+4\sqrt{6}\right)^2}{4}+1929\ge1929\forall X\in R\)
DẤU = XẢY RA \(\Leftrightarrow\left\{{}\begin{matrix}\sqrt{3}X-\dfrac{4}{\sqrt{3}}Y=0\\X+16=0\\\dfrac{2\sqrt{2}}{\sqrt{3}}Y+4\sqrt{6}=0\end{matrix}\right.\)
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