= 25 nha bạn 

các bạn tick mình cho tròn 220 điểm hỏi đáp với

\(=\frac{5^3.\left(2^3+2+1\right)}{55}=\frac{5^2.5.11}{5.11}=5^2=25\)

Lần sau bạn nên viết đề rõ hơn nhé!

Đề: Tính nhanh: \(\frac{10^3+2\cdot5^3+5^3}{55}\)

ta có: \(\frac{10^3+2\cdot5^3+5^3}{55}=\frac{5^3\left(2^3+2+1\right)}{5\cdot11}=\frac{5^3\cdot11}{5\cdot11}=5^2=25\)

Học tốt nhé ^3^

Ta có : \(\frac{10^3+2.5^3+5^3}{55}=\frac{2^3.5^3+2.5^3+5^3}{5.11}=\frac{5^3\left(2^3+2+1\right)}{5.11}=\)\(\frac{5^3.11}{5.11}=5^2=25\)

Vậy \(\frac{10^3+2.5^3+5^3}{5.11}\)=25.

\(\frac{10^3+2\times5^3+5^3}{55}\)= \(\frac{1000+2\times125+125}{55}\)= \(\frac{1000+250+125}{55}\)= \(\frac{1250+125}{55}\)= \(\frac{1375}{55}\)= 25.

\(\frac{10^3+2.5^3+5^3}{55}=\frac{1000+2.125+125}{55}=\frac{1375}{55}=25\)

chìu mk lm nha

Giờ mk có việc rồi

Nhớ tick cho mk nha !!!!!

\(=\frac{5^3\cdot2^3+2+5^3}{55}=\frac{5^3\left(8+2+1\right)}{55}=\frac{125\cdot11}{11\cdot5}=\frac{25\cdot1}{1\cdot1}=25\)

25

AI TICK GIÙM MÌNH MỘT CÁI ĐI MÀ!!!!!!!!!!!!!!!!!!!!!

\(\frac{10^3+2\cdot5^3+5^3}{55}\)

\(=\frac{\left(5.2\right)^3+5^3\cdot\left(2+1\right)}{55}\)

\(=\frac{5^3\cdot2^3+5^3\cdot3}{55}\)

\(=\frac{5^3\cdot8+5^3\cdot3}{55}\)

\(=\frac{5^3\cdot\left(8+3\right)}{55}\)

\(=\frac{5^3\cdot11}{55}=\frac{5^3}{5}=5^2=25\)

Tick nha

\(\frac{10^3+2.5^3+5^3}{55}-\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)\(=\frac{2^3.5^3+2.5^3+5^3}{5.11}-\frac{2^{12}.3^{10}+2^9.3^9.2^3.3.5}{2^{12}.3^{12}-2^{11}.3^{11}}\)

\(=\frac{5^3\left(2^3+2+1\right)}{5.11}-\frac{2^{12}.3^{10}.\left(1+5\right)}{2^{11}.3^{11}.\left(2.3-1\right)}=\frac{5^2.11}{11}-\frac{2.6}{3.5}=25-\frac{4}{5}=\frac{121}{5}\)