tính:\(\frac{\left(-12\right)^5.27^4-32^2.81^4}{729^4:\left(-9\right)^4.16^5:\left(-8\right)^3}\)
NH
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tính:\(\frac{\left(-12\right)^5.27^4-32^2.81^4}{729^4:\left(-9\right)^4.16^5:\left(-8\right)^3}\)
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B = \(\frac{\left(-12\right)^5\times27^4-32^2\times81^4}{729^4\div\left(-9\right)^4\times16^5\div\left(-8\right)^3}\)
Tính giá trị của biểu thức sau:
B = \(\dfrac{\left(-12\right)^5\times27^4-32^2\times81^4}{729^4\div\left(-9\right)^4\times16^5\div\left(-8\right)^3}\)
Ta có:\(B=\dfrac{\left(-12\right)^5.27^4-32^2.81^4}{729^4:\left(-9\right)^4.16^5:\left(-8\right)^3}=\dfrac{\left(-3\right)^5.2^{10}.3^{12}-2^{10}.3^{16}}{3^{24}:3^8.2^{20}:\left(-2\right)^9}\\ =\dfrac{2^{10}.3^{16}.\left[-3-1\right]}{\left(-2\right)^{11}.3^{16}}=2\)
Vậy B = 2
Đúng 0
Bình luận (2)
Baif 1a)frac{1}{42}.16^x8^xb)3^{-3}.3^5.3^x3^8c)left(7x+2right)^{-1}3^{-2}Bài 2a)3^4.frac{1}{729}.81^3.frac{1}{9^2}b)left(8.2^5right):left(2^4.frac{1}{32}right)c)12^8.9^{12}d)left(1+frac{2}{3}-frac{1}{4}right).left(frac{4}{5}-frac{3}{4}right)^2Giups mik nha
Đọc tiếp
Baif 1
a)\(\frac{1}{42}.16^x=8^x\)
b)\(3^{-3}.3^5.3^x=3^8\)
c)\(\left(7x+2\right)^{-1}=3^{-2}\)
Bài 2
a)\(3^4.\frac{1}{729}.81^3.\frac{1}{9^2}\)
b)\(\left(8.2^5\right):\left(2^4.\frac{1}{32}\right)\)
c)\(12^8.9^{12}\)
d)\(\left(1+\frac{2}{3}-\frac{1}{4}\right).\left(\frac{4}{5}-\frac{3}{4}\right)^2\)
Giups mik nha
Câu a) số lớn lắm
b) \(3^{-3}\cdot3^5\cdot3^x=3^8\)
=> \(\frac{1}{27}\cdot3^5\cdot3^x=3^8\)
=> \(\frac{1}{27}\cdot3^x=3^3\)
=> \(3^x=3^3:\frac{1}{27}=3^3:\left(\frac{1}{3}\right)^3=3^3:\frac{1^3}{3^3}=3^3\cdot3^3=3^6\)
=> x = 6
b) \(\left(7x+2\right)^{-1}=3^{-2}\)
=> \(\frac{1}{7x+2}=\frac{1}{9}\)
=> 7x + 2 = 9
=> 7x = 7
=> x = 1
Bài 2:
a) \(3^4\cdot\frac{1}{729}\cdot81^3\cdot\frac{1}{9^2}\)
\(=3^4\cdot\left(\frac{1}{3}\right)^6\cdot\left(3^4\right)^3\cdot\left(\frac{1}{3}\right)^4\)
\(=3^4\cdot\left(\frac{1}{3}\right)^6\cdot3^{12}\cdot\left(\frac{1}{3}\right)^4=3^{16}\cdot\left(\frac{1}{3}\right)^{10}=\frac{3^{16}}{3^{10}}=3^6\)
b) \(\left(8\cdot2^5\right):\left(2^4\cdot\frac{1}{32}\right)=\left(2^3\cdot2^5\right):\left(2^4\cdot\left(\frac{1}{2}\right)^5\right)\)
\(=2^8:\left(2^4\cdot\frac{1^5}{2^5}\right)=2^8:\left(\frac{2^4}{2^5}\right)=2^8:2^{-1}=512\)
c) \(12^8\cdot9^{12}=\left(2^2\cdot3\right)^8\cdot\left(3^2\right)^{12}=2^{16}\cdot3^8\cdot3^{24}=2^{16}\cdot3^{32}\)
d) Tương tự
Trả lời rõ cho mik có đc k mn
PT
23 tháng 8 2016 lúc 10:43
Tính : \(\frac{\left(1^4+\frac{1}{4}\right)\left(3^4+\frac{1}{4}\right)\left(5^4+\frac{1}{4}\right)\left(7^4+\frac{1}{4}\right)\left(9^4+\frac{1}{4}\right)\left(11^4+\frac{1}{4}\right)}{\left(2^4+\frac{1}{4}\right)\left(4^4+\frac{1}{4}\right)\left(6^4+\frac{1}{4}\right)\left(8^4+\frac{1}{4}\right)\left(10^4+\frac{1}{4}\right)\left(12^4+\frac{1}{4}\right)}\)
Tính giá trị của các biểu thức sau
1)\(\left(3\frac{5}{12}-1\frac{8}{9}\right):\left(0,25-2\frac{1}{12}\right)\)
2)\(\left(1\frac{4}{7}-2\frac{2}{5}\right):\left(1\frac{1}{8}-4\frac{3}{4}\right)\)
Tính
\(\left(\frac{3}{4}\right)^4.\left(\frac{4}{3}\right)^5\)
\(\left(\frac{-13}{8}\right)^3\left(\frac{-32}{13}\right)^4\)
thực hiện phép tính : ( tính nhanh nếu có thể )a) left(frac{11}{12}:frac{33}{16}right).frac{3}{5}+frac{7}{23}.left[left(frac{-8}{6}+frac{-45}{18}right)right]b) left(frac{-2}{3}+frac{3}{7}right):frac{4}{5}+left(frac{-1}{3}+frac{4}{7}right):frac{4}{5}c) frac{5}{9}:left(frac{1}{11}-frac{5}{22}right)+frac{5}{9}:left(frac{1}{15}-frac{2}{3}right)d) frac{-3}{4}.frac{12}{-5}.frac{-25}{6}+left(-2right).frac{-38}{21}.frac{-7}{4}.frac{-3}{8}
Đọc tiếp
thực hiện phép tính : ( tính nhanh nếu có thể )
a) \(\left(\frac{11}{12}:\frac{33}{16}\right).\frac{3}{5}+\frac{7}{23}.\left[\left(\frac{-8}{6}+\frac{-45}{18}\right)\right]\)
b) \(\left(\frac{-2}{3}+\frac{3}{7}\right):\frac{4}{5}+\left(\frac{-1}{3}+\frac{4}{7}\right):\frac{4}{5}\)
c) \(\frac{5}{9}:\left(\frac{1}{11}-\frac{5}{22}\right)+\frac{5}{9}:\left(\frac{1}{15}-\frac{2}{3}\right)\)
d) \(\frac{-3}{4}.\frac{12}{-5}.\frac{-25}{6}+\left(-2\right).\frac{-38}{21}.\frac{-7}{4}.\frac{-3}{8}\)
Tính: \(A=\left(1+\frac{4}{5}\right)\left(1+\frac{4}{12}\right)\left(1+\frac{4}{21}\right)\left(1+\frac{4}{32}\right)...\left(1+\frac{4}{24021}\right)\)