(5346-2808) : 54 + 51

=2538 : 54 + 51

= 47 + 51 = 98

187 . ( 38 + 62 ) - 87 . (62 + 38 )

=187 . 100 - 87 . 100

= 100 . ( 187 - 87 )

= 100 . 100

= 10000

25. { 32 : [12 -4 + 4 . ( 16 : 8 )]}

= 25. { 32 : [12 - 4 + 8]}

= 25 . { 32 : [8 + 8 ]}

= 25 . { 32 : 16 }

= 25 . 2 =50

A = 50 +51 + 52 + ......+ 99+100

A = ( 100 + 50 ) . 51 : 2

A = 150 .51 : 2

A = 7650 : 2

A = 3825

Chuc ban hoc tot

\(\left(5346-2808\right):54+51\)

\(=2538:54+51\)

\(=47+51=98\)

\(187\left(38+62\right)-87\left(62+38\right)\)

\(=187.100-87.100\)

\(=100\left(187-87\right)\)

\(=100.100=10000\)

\(25\left\{32:\left[12-4+4\left(16:8\right)\right]\right\}\)

\(=25\left\{32:\left[12-4+4.2\right]\right\}\)

\(=25\left\{32:\left[12-4+8\right]\right\}\)

\(=25\left\{32:16\right\}\)

\(=25.2=50\)

\(A=50+51+52+......+100\)

\(=\dfrac{\left[\left(100-50\right):1+1\right]\left(100+50\right)}{2}\)

\(=3825\)

(5346 - 2808) : 54 + 51

= 2538 : 54 + 51

= 47 + 51

= 98

187 . (38 + 62) - 87 . (62 + 38)

= 187 . 100 - 87 . 100

= (187 - 87) . 100

= 100 . 100

= 10000

25 . {32 : [12 - 4 + 4 . (16 : 8)] }

= 25 . (32 : 8 + 4 . 2)

= 25 . (4 + 8)

= 25 . 4 + 25 . 8

= 100 . 200

= 20000

A = 50 + 51 + 52 +.......+ 99 + 100

A có : (100 - 50) : 1 + 1= 51 (phần tử)

\(\Rightarrow\) A = (100 + 50) . 51 : 2 = 3825.

(5 + 6 + 11 - 41) x (1 + 2 + 3 + ... + 100)

= [(5 + 6)  - (11 - 41)] x (1 + 2 +...+ 100)

= [11 - 30 ] x (1 + 2 + ... + 100)

= - 19 x (1 + 2 +...+ 100)

Lớp 5 chưa học số âm.

        12 x 85 + 35 - 182 - 35 x 94

    =  1020 - 35 x (94 - 1) - 182

   = 1020 - 35 x 93 - 182

  = 1020 - 3255 - 182

  = - 2235 - 182

= - 2417

Lớp 5 chưa học số âm 

   2 x 31 x 12 + 4 x 6 + 42 + 8 x 27 x 3

= 24 x 31 + 24 + 42 + 24 x 27

= 24 x (31 + 1 + 27) + 42

= 24 x 59 + 42

= 1458

mai mình thi rồi, các bạn giúp mình với

Chờ tí

Câu 4: 

d) Ta có: \(\dfrac{-2}{17}+\dfrac{3}{19}+\dfrac{-15}{17}+\dfrac{16}{19}+\dfrac{5}{6}\)

\(=\left(-\dfrac{2}{17}-\dfrac{15}{17}\right)+\left(\dfrac{3}{19}+\dfrac{16}{19}\right)+\dfrac{5}{6}\)

\(=-1+1+\dfrac{5}{6}=\dfrac{5}{6}\)

Câu 3:

a) \(\dfrac{12}{36}=\dfrac{12:12}{36:12}=\dfrac{1}{3}\)

\(\dfrac{-16}{20}=\dfrac{-16:4}{20:4}=\dfrac{-4}{5}\)

b) \(\dfrac{21}{105}=\dfrac{21:21}{105:21}=\dfrac{1}{5}\)

\(\dfrac{35}{150}=\dfrac{35:5}{150:5}=\dfrac{7}{30}\)

Câu 4: 

a) \(\dfrac{3}{10}+\dfrac{5}{10}=\dfrac{3+5}{10}=\dfrac{8}{10}=\dfrac{4}{5}\)

b) Ta có: \(\left(-27\right)\cdot36+64\cdot\left(-27\right)+23\cdot\left(-100\right)\)

\(=\left(-27\right)\cdot\left(64+36\right)+23\cdot\left(-100\right)\)

\(=-27\cdot100-23\cdot100\)

\(=100\left(-27-23\right)\)

\(=-50\cdot100=-5000\)

c) \(\dfrac{5}{8}+\dfrac{3}{12}=\dfrac{15}{24}+\dfrac{6}{24}=\dfrac{21}{24}=\dfrac{7}{8}\)

d) Ta có: \(\dfrac{-2}{17}+\dfrac{3}{19}+\dfrac{-15}{17}+\dfrac{16}{19}+\dfrac{5}{6}\)

\(=\left(-\dfrac{2}{17}+\dfrac{-15}{17}\right)+\left(\dfrac{3}{19}+\dfrac{16}{19}\right)+\dfrac{5}{6}\)

\(=-1+1+\dfrac{5}{6}\)

\(=\dfrac{5}{6}\)

7)    \(\frac{x+25}{75}+\frac{x+30}{70}=\frac{x+35}{65}+\frac{x+40}{60}\)

\(\Leftrightarrow\)\(\frac{x+25}{75}+1+\frac{x+30}{70}+1=\frac{x+36}{65}+1+\frac{x+40}{60}+1\)

\(\Leftrightarrow\)\(\frac{x+100}{75}+\frac{x+100}{70}=\frac{x+100}{65}+\frac{x+100}{60}\)

\(\Leftrightarrow\)\(\left(x+100\right)\left(\frac{1}{75}+\frac{1}{70}-\frac{1}{65}-\frac{1}{60}\right)=0\)

\(\Leftrightarrow\)\(x+100=0\)            (vì 1/75 + 1/70 - 1/65 - 1/60  \(\ne\)0)

\(\Leftrightarrow\)\(x=-100\)

Vậy.....

7)    \(\frac{x+25}{75}+\frac{x+30}{70}=\frac{x+35}{65}+\frac{x+40}{60}\)

\(\Leftrightarrow\)\(\frac{x+25}{75}+1+\frac{x+30}{70}+1=\frac{x+35}{65}+1+\frac{x+40}{60}+1\)

\(\Leftrightarrow\)\(\frac{x+100}{75}+\frac{x+100}{70}=\frac{x+100}{65}+\frac{x+100}{60}\)

\(\Leftrightarrow\)\(\left(x+100\right)\left(\frac{1}{75}+\frac{1}{70}-\frac{1}{65}-\frac{1}{60}\right)=0\)

\(\Leftrightarrow\)\(x+100=0\)    (1/75 + 1/70 - 1/65 - 1/60 \(\ne\)0)

\(\Leftrightarrow\)\(x=-100\)

Vậy...