Câu 1: 

a:=17+5=22

b: =40-25=15

lỗi ảnh , up lại câu  hỏi

lỗi

Lỗi bạn nhé :)

a)=315,57

b)=61,72

\(a,=315,57\\ b,=7,7+54,02=61,72\)

giảng giải ra giúp mk nha

\(a,=12x^2+18x-12x^2+x+1=19x+1\)

\(a,=12x^2+18x-12x^2+x+1=19x+1\\ b,=4x^3y^4-3xy^2-\dfrac{3}{2}x\)

a: Ta có: \(x\left(2-3x\right)+\left(3x^3-x^2\right):x\)

\(=2x-3x^2+3x^2-x\)

=x

b: Ta có: \(2x\left(x-3y\right)-\left(8x^3y-12x^2y^2\right):2xy\)

\(=2x^2-6xy-4x^2+6xy\)

\(=-2x^2\)

Bài 2

A =  (x + 2)^ 2 - x - 3 x (x + 1) = x² + 4x + 4 - x² + 2x + 3 = 6x + 7

B = x^3 - 2x² + 5x - 10 = x² x (x - 2) + 5 x (x - 2) = (x - 2) x (x² + 5)

Vậy x^3 - 2x² + 5x - 10 : (x - 2) = x² + 5

a, 25/12

b,  25/72

a) = 3/4 + 4/3 = 25/12

b) = 3/8 - 16/9 = -101/72 * hình như hơi sai sai:"> *

a: \(\dfrac{7}{4}-\dfrac{11}{8}+\dfrac{1}{2}\)

\(=\dfrac{14-11+4}{8}\)

\(=\dfrac{7}{8}\)

b: \(\dfrac{3}{16}+\dfrac{7}{30}\cdot\dfrac{40}{36}\)

\(=\dfrac{3}{16}+\dfrac{7}{36}\cdot\dfrac{40}{30}\)

\(=\dfrac{3}{16}+\dfrac{7}{36}\cdot\dfrac{4}{3}\)

\(=\dfrac{3}{16}+\dfrac{7}{27}=\dfrac{81+112}{432}=\dfrac{193}{432}\)

c: \(\left(\dfrac{9}{2}-\dfrac{15}{4}\right):\dfrac{21}{12}\)

\(=\left(\dfrac{18}{4}-\dfrac{15}{4}\right):\dfrac{7}{4}\)

\(=\dfrac{3}{4}\cdot\dfrac{4}{7}=\dfrac{3}{7}\)