a) 5x-18=72
b) (x-36)-32=0
c) 156 -(x+6)=82
d) 2 mủ x =16
Bài 2: Tìm x:
a) 156 – (x+ 61) = 82 b) (x-35) -120 = 0 c) 124 + (118 – x) = 217 d) 7x – 8 = 713 e) x- 36:18 = 12 f) (x- 36):18 = 12 g) (x-47) -115 = 0 |
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Bài 3: Tính nhanh
a) 58.75 + 58.50 – 58.25 b) 27.39 + 27.63 – 2.27 c) 128.46 + 128.32 + 128.22 d) 66.25 + 5.66 + 66.14 + 33.66 e) 12.35 + 35.182 – 35.94 | f) 48.19 + 48.115 + 134.52 g) 27.121 – 87.27 + 73.34 h) 125.98 – 125.46 – 52.25 i) 136.23 + 136.17 – 40.36 j) 17.93 + 116.83 + 17.23 | k) 35.23 + 35.41 + 64.65 l) 29.87 – 29.23 + 64.71 m) 19.27 + 47.81 + 19.20
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Bài 4: Tính giá trị của biểu thức sau:
a) 2763 + 152 b) (-7) + (-14) c) (-35) + (-9) d) (-5) + (-248) e) (-23) + 105 f) 78 + (-123) g) 23 + (-13) h) (-23) + 13 i) 26 + (-6) | j) 80 + (-220) k) (-23) + (-13) l) (-26) + (-6) | m) 12 – 34 n) -23 – 47 o) 31 – (-23) p) -9 – (-5) q) 6 – (8 – 17) r) 19 + (23 – 33) s) (-12 – 44) + (-3) t) 4 – (-15) u) -29 – 23 | v) 99 – [109 + (-9)] w) (-75) + 50 x) (-75) + (-50) y) (-23) + 13 + ( - 17) + 57 z) 14 + 6 + (-9) + (-14)
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a: =>x+61=74
hay x=13
b: =>x-35=120
hay x=155
d: =>7x=721
hay x=103
16.X (6 mủ 2 )- 36=0 6.X + 2.X= 7 mủ 8 : 7mủ 5 7.X -12 = 6mủ 3 : 6 mủ 2 Ghi chi tiết giúp em với ạ cảm ơn anh chị nhiều
Bạn nên viết đề bằng công thức toán (biểu tượng $\sum$ góc trái khung soạn thảo) để mọi người đọc đề của bạn dễ hiểu hơn nhé.
1) 168 - ( 18 - 2x ) x 12 = 120
2) [ 75 + ( 16 - x ) ] x 2 = 156
3) 124 - 24 x ( 3x - 16 ) = 76
4) [ ( 10 - x ) x 2 + 5 ] : 3 - 2 = 3
5) [ 80 + ( 62 - x ) ] : 17 - 7 = 1
6) 65 - ( 5x - 70 ) : 2 = 50
7) 504 : 9 136 - 2x ) + 4 = 32
8) ( 13x - 28 ) x 15 - 5 x 23 = 320
Mình cần gấp ạ !!!
a) x^2+9x=0
b)x^3+4x^2+4x=0
c)(x-5)^2-16=0
d)3(x+2)-x^2-2x=0
e)(x+2)^3-x^2(x+6)=4
g)x^2+5x+6=0
\(a,x\left(x+9\right)=0\Rightarrow\left[{}\begin{matrix}x=0\\x=-9\end{matrix}\right.\\ b,\Rightarrow x\left(x^2+4x+4\right)=0\\ \Rightarrow x\left(x+2\right)^2=0\Rightarrow\left[{}\begin{matrix}x=0\\x=-2\end{matrix}\right.\\ c,\Rightarrow\left(x-5-4\right)\left(x-5+4\right)=0\\ \Rightarrow\left(x-9\right)\left(x-1\right)=0\Rightarrow\left[{}\begin{matrix}x=1\\x=9\end{matrix}\right.\\ d,\Rightarrow3\left(x+2\right)-x\left(x+2\right)=0\\ \Rightarrow\left(x+2\right)\left(3-x\right)=0\Rightarrow\left[{}\begin{matrix}x=3\\x=-2\end{matrix}\right.\\ e,\Rightarrow x^3+6x^2+12x+8-x^3-6x^2=4\\ \Rightarrow12x=-4\Rightarrow x=-\dfrac{1}{3}\\ g,\Rightarrow\left(x+2\right)\left(x+3\right)=0\Rightarrow\left[{}\begin{matrix}x=-2\\x=-3\end{matrix}\right.\)
Tim x € N biet :
a / x + 16 = 25
b / 156 - 2x = 82
c / 150 -150 : ( 18 - x ) = 125
d / 62 : x = 23 - 4
e / x + 3x + 5x + ................. +99x = 75 × 102
a) x = 25 - 16
x = 9
b) 2x = 156-82
2x = 74
x = 74 : 2
x = 37
c) 150 : (18-x) = 150-125
150 : (18-x) = 25
18-x = 150 : 25
18-x = 6
x =18-6
x= 12
d) 6.6 :x = 8-4
36 : x = 4
x =36:4
x = 9
e)(99x-x) : 2+1= 50x
Ta có:
50x + (1+3+5+7+9+.....+99)=75.10.10
50x + (99+1).50:2 =7500
50x + 2500=7500
50x=7500-2500
50x=5000
x =5000:50
x = 100
Tim x € N biet :
a / x + 16 = 25
=> x = 25 - 16
=> x = 9
b / 156 - 2x = 82
=> 2x = 156 - 82
=> 2x = 74
=> x = 37
c / 150 -150 : ( 18 - x ) = 125
=> 150 : ( 18 - x ) = 125 -150
=> 150 : ( 18 - x ) = - 25
=> 18 - x = -6
=> x = 18 - ( -6 )
=> x = 24
d / 62 : x = 23 - 4
=> 36 : x = 8 - 4
=> 36 : x = 4
=> x = 36 : 4
=> x = 9
e / x + 3x + 5x + ................. +99x = 75 × 102
=> x + 3x + 5x +....+ 99x = 7500
=> x. ( 1 + 3 + 5 +....+ 99 ) = 7500
Số các số hạng là : ( 99 - 1 ) : 2 + 1 = 50
=> Số cặp là : 50 : 2 = 25
Ta có:
x. ( 1 + 3 + 5 +....+ 99 ) = 7500
=> x. [ ( 1 + 99 ) + ( 2 + 98 ) +.... ] = 7500
=> x. 100 .25 =7500
=> x. 2500 = 7500
=> x = 7500 : 2500
=> x = 3
a) x = 25 - 16
x = 9
b) 2x = 156-82
2x = 74
x = 74 : 2
x = 37
c) 150 : (18-x) = 150-125
150 : (18-x) = 25
18-x = 150 : 25
18-x = 6
x =18-6
x= 12
d) 6.6 :x = 8-4
36 : x = 4
x =36:4
x = 9
e)(99x-x) : 2+1= 50x
Ta có:
50x + (1+3+5+7+9+.....+99)=75.10.10
50x + (99+1).50:2 =7500
50x + 2500=7500
50x=7500-2500
50x=5000
x =5000:50
x = 100
a) 2x2 + 2x(5 - x)=12 d) 2(x + 5) - x2 - 5x = 0 g) (3x + 1)2 - (x+1) = 0
b) (5 - 2x)2 - 16 = 0 e) (2x - 1)2 - 4(x + 7)(x - 7) = 0 h) x2 + 7x - 8 = 0
c) 3x2 - 3x(x-2) = 36 f) (x + 4)2 - (x + 1)(x - 1) = 16 i) -2x2 +13x -15 = 0
mik cần gấp, cảm ơn mọi người.
\(a,\Leftrightarrow2x^2+10x-2x^2=12\Leftrightarrow x=\dfrac{12}{10}=\dfrac{6}{5}\\ b,\Leftrightarrow\left(5-2x-4\right)\left(5-2x+4\right)=0\\ \Leftrightarrow\left(1-2x\right)\left(9-2x\right)=0\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{2}\\x=\dfrac{9}{2}\end{matrix}\right.\\ c,\Leftrightarrow3x^2-3x^2+6x=36\Leftrightarrow x=6\\ d,\Leftrightarrow2\left(x+5\right)-x\left(x+5\right)=0\\ \Leftrightarrow\left(2-x\right)\left(x+5\right)=0\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-5\end{matrix}\right.\\ e,\Leftrightarrow4x^2-4x+1-4x^2+196=0\\ \Leftrightarrow-4x=-197\Leftrightarrow x=\dfrac{197}{4}\)
\(f,\Leftrightarrow x^2+8x+16-x^2+1=16\Leftrightarrow8x=-1\Leftrightarrow x=-\dfrac{1}{8}\\ g,Sửa:\left(3x+1\right)^2-\left(x+1\right)^2=0\\ \Leftrightarrow\left(3x+1-x-1\right)\left(3x+1+x+1\right)=0\\ \Leftrightarrow2x\left(4x+2\right)=0\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-\dfrac{1}{2}\end{matrix}\right.\\ h,\Leftrightarrow x^2+8x-x-8=0\\ \Leftrightarrow\left(x+8\right)\left(x-1\right)=0\Leftrightarrow\left[{}\begin{matrix}x=1\\x=-8\end{matrix}\right.\\ i,\Leftrightarrow2x^2-13x+15=0\\ \Leftrightarrow2x^2+2x-15x-15=0\\ \Leftrightarrow\left(x+1\right)\left(2x-15\right)=0\Leftrightarrow\left[{}\begin{matrix}x=-1\\x=\dfrac{15}{2}\end{matrix}\right.\)
bài 1 giải các bất phương trình sau
a, -x2 +5x-6 ≥ 0
b, x2-12x +36≤0
c, -2x2 +4x-2≤0
d, x2 -2|x-3| +3x ≥ 0
e, x-|x+3| -10 ≤0
bài 2 xét dấu các biểu thức sau
a,<-x2+x-1> <6x2 -5x+1>
b, x2-x-2/ -x2+3x+4
c, x2-5x +2
d, x-< x2-x+6 /-x2 +3x+4 >
Bài 1:
a: \(\Leftrightarrow x^2-5x+6< =0\)
=>(x-2)(x-3)<=0
=>2<=x<=3
b: \(\Leftrightarrow\left(x-6\right)^2< =0\)
=>x=6
c: \(\Leftrightarrow x^2-2x+1>=0\)
\(\Leftrightarrow\left(x-1\right)^2>=0\)
hay \(x\in R\)
Tìm x biết:
1,
a,3x(x+1) - 2x(x+2) = -x-1
b,2x(x-2020) - x+2020 = 0
c,(x-4)2 - 36 = 0
d,x2 + 8x - 16 = 0
e,x(x+6) - 7x - 42 = 0
f,25x2 - 16 = 0
2,
a,3x3 - 12x = 0
b,x2 + 3x - 10 = 0
Bài 1:
a) \(\Rightarrow3x^2+3x-2x^2-4x+x+1=0\)
\(\Rightarrow x^2=-1\left(VLý\right)\Rightarrow S=\varnothing\)
b) \(\Rightarrow\left(x-2020\right)\left(2x-1\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=2020\\x=\dfrac{1}{2}\end{matrix}\right.\)
c) \(\Rightarrow\left(x-10\right)\left(x+2\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=10\\x=-2\end{matrix}\right.\)
d) \(\Rightarrow\left(x+4\right)^2=0\Rightarrow x=-4\)
e) \(\Rightarrow\left(x+6\right)\left(x-7\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=-6\\x=7\end{matrix}\right.\)
f) \(\Rightarrow\left(5x-4\right)\left(5x+4\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{4}{5}\\x=-\dfrac{4}{5}\end{matrix}\right.\)
Bài 2:
a) \(\Rightarrow3x\left(x^2-4\right)=0\Rightarrow3x\left(x-2\right)\left(x+2\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=0\\x=2\\x=-2\end{matrix}\right.\)
b) \(\Rightarrow x\left(x-2\right)+5\left(x-2\right)=0\Rightarrow\left(x-2\right)\left(x+5\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=2\\x=-5\end{matrix}\right.\)
Tính nhanh các giá trị biểu thức dưới đây:
a) 576 + 678 + 780 – 475 - 577 - 679
b) (126 + 32) x (18 - 16 - 2)
c) 36 x 17 x 12 x 34 + 6 x 30
a) 576 + 678 + 780 - 475 - 577 - 679
= 780 - 475 + ( 576 - 577) - ( 678 - 679)
= 305 - 1 - 1
= 303
b) (126 + 32)\(\times\)(18 - 16 - 2)
= (126 + 32) \(\times\)0
= 0
c) 36 * 17 * 12 * 34 + 6 * 30
= 36 * 17 * 6 * 2 * 34 + 6 * 30
= 6 * (36 + 17 + 2 + 34 + 30)
= 6 * 119
= 714
\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
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