\(2^{x-2}-3.2^x=-88\)

\(\Rightarrow2^x:2^2-3.2^x=-88\)

\(\Rightarrow2^x.\left(\dfrac{1}{4}-3\right)=-88\)

\(\Rightarrow\)\(2^x.\left(-2\dfrac{3}{4}\right)=-88\)

\(\Rightarrow\)\(2^x=\)32

=> x=5

\(2^{x-2}-3.2^x=-88\)

\(2^x.2^{-2}-3.2x=-88\)

\(2^x.\left(2^{-2}-3\right)\) =-88

\(2^x.\left(\dfrac{1}{4}-3\right)\) =-88

\(2^x.\left(\dfrac{-11}{4}\right)\) =-88

\(2^x\) =\(-88:\left(\dfrac{-11}{4}\right)\)

\(2^x\) =32

\(2^x=2^5\)

\(\Rightarrow\) x=5

5,555*10¹²

3

2^x+3+3.2^x=88

=>2^x.2^3+3.2^x=88

=>2^x.(8+3)=88

=>2^x.11=88

2^x=8

2^x=2^3

vậy x=3

\(2^{x-2}-3.2^x=-88\)

\(2^x:2^2-2^x:\frac{1}{3}=-88\)

\(2^x:\left(2^2-\frac{1}{3}\right)=-88\)

\(2^x:\frac{11}{3}=-88\)

\(2^x=-88.\frac{11}{3}\)

\(2^x=\frac{-968}{3}\)

\(2^{x-2}-\)\(3.2^x=-88\)

\(2^x:2^2-2^x.3=-88\)

\(2^x.\frac{1}{4}-\)\(2^x.3=-88\)

\(2^x.\left(\frac{1}{4}-3\right)=-88\)

\(2^x.\frac{-11}{4}=-88\)

\(2^x=-88:\frac{-11}{4}\)

\(2^x=32\)

\(2^x=2^5\)

\(\Rightarrow x=5\)

a)\(2^{x-2}\)-\(3\times2^x\)=(-88)

=>\(2^x\times\frac{1}{2^2}-3\times2^x=\left(-88\right)\)

\(\Rightarrow2^x\times\left(\frac{1}{4}-3\right)=\left(-88\right)\)

\(\Rightarrow2^x\times\left(\frac{-11}{4}\right)=\left(-88\right)\)

\(\Rightarrow2^x=32=2^5\)

\(\Rightarrow x=5\)

\(10+2\cdot x=4^5:4^3\)

\(\Rightarrow10+2\cdot x=4^{5-3}\)

\(\Rightarrow10+2\cdot x=4^2\)

\(\Rightarrow10+2\cdot x=16\)

\(\Rightarrow2\cdot x=16-10\)

\(\Rightarrow2\cdot x=6\)

\(\Rightarrow x=\dfrac{6}{2}=3\)

__________________

\(2\cdot x-6^2:18=3\cdot2^2\)

\(\Rightarrow2\cdot x-36:18=12\)

\(\Rightarrow2\cdot x-2=12\)

\(\Rightarrow2\cdot x=12+2\)

\(\Rightarrow2\cdot x=14\)

\(\Rightarrow x=\dfrac{14}{2}=7\)

_________________

\(70-5\cdot\left(x-3\right)=3\cdot2\)

\(\Rightarrow70-5\cdot\left(x-3\right)=6\)

\(\Rightarrow70-5x+15=6\)

\(\Rightarrow-5x+15=6-70\)

\(\Rightarrow-5x+15=64\)

\(\Rightarrow-5x=64-15\)

\(\Rightarrow-5x=49\)

\(\Rightarrow x=-\dfrac{49}{5}\)

\(x\)(\(x\) - 2) = 16

\(x^2\) - 2\(x\) - 16 = 0

(\(x^2\) - \(x\)) - (\(x\) - 1) - 17 = 0

\(x\)(\(x\) - 1) - (\(x-1\)) = 17

(\(x\) - 1)(\(x\) - 1) = 17

(\(x-1\))² = 17

\(\left[{}\begin{matrix}x-1=\sqrt{17}\\x-1=-\sqrt{17}\end{matrix}\right.\)

\(\left[{}\begin{matrix}x=1+\sqrt{17}\\x=1-\sqrt{17}\end{matrix}\right.\)

Vậy: \(\in\) {1 - \(\sqrt{17}\); 1 + \(\sqrt{17}\)}

Bài 2:

2^\(x\) + 3.2^\(x\) = 144

2^\(x\).(1 + 3) = 144

2^\(x\).4 = 144

2^\(x\) = 144 : 4

2^\(x\) = 36

2\(^x\) = 36

Nếu \(x\) = 6 ⇒ 2\(^x\) = 64 > 36 (loại)

Nếu \(x\) ≤ 5 ⇒2\(^x\) ≤ 2⁵ = 32 < 36 (loại)

Vậy \(x\in\) \(\varnothing\) 

`=40`

\(=\dfrac{3\cdot2^{x+1}}{2^{x+3}}=\dfrac{3}{2^2}=\dfrac{3}{4}\)

\(2^{x-3}-3.2^x=-92\)

\(\Rightarrow2^x\left(2^{-3}-3\right)=-92\)

\(\Rightarrow2^x.\dfrac{-23}{8}=-92\Rightarrow2^x=32\)

\(\Rightarrow2^x=2^5\Rightarrow x=5\)