C= pⁿ⁺²q - pⁿ⁺¹q³ - p²qⁿ⁺¹ + pqⁿ⁺³

= pⁿ⁺¹.pq-pⁿ⁺¹q³- p²qⁿ⁺¹ + pqⁿ⁺¹.q²

=pⁿ⁺¹q(p-q²)-pqⁿ⁺¹(p-q²)

=(p-q²)(pⁿ⁺¹q-pqⁿ⁺¹)

mình không biết bạn ơi. Mình học lớp 2

\(n^3+\left(n+2\right)^3=2\left(n+1\right)\left(n^2+n\left(n+2\right)+\left(n+2\right)^2\right)\)

\(\Rightarrow A=\left(n+1\right)\left(2n^2+2n\left(n+1\right)+2\left(n+2\right)^2+\left(n+1\right)^2\right)\)

Bạn tự pt tiếp nhé

n³ -n² -7n +1=n²(n-1) - 7(n-1)-6=0 <=>(n-1).(n²-7)=6

=(x-1) + xⁿ.(x³-1)

=(x-1) + xⁿ . (x-1)(x²+x+1)

=(x-1)[1+xⁿ(x²+x+1)]

=(x-1)(1+xⁿ⁺²+xⁿ⁺¹+xⁿ)

x=x+11+22+33+..+112233445566778899+x thuộc n

k nha

Bài 1: 

e: Ta có: \(x\left(y-x\right)^2-x^2+2xy-y^2\)

\(=x\left(x-y\right)^2-\left(x-y\right)^2\)

\(=\left(x-y\right)^2\cdot\left(x-1\right)\)

Bài 2: 

a: Ta có: \(M=m^2\left(m+n\right)-n^2m-n^3\)

\(=m^2\left(m+n\right)-n^2\left(m+n\right)\)

\(=\left(m+n\right)^2\cdot\left(m-n\right)\)

\(=\left(-2017+2017\right)^2\cdot\left(-2017-2017\right)\)

=0

a: \(M=m^2\left(m+n\right)-n^2m-n^3\)

\(=m^2\left(m+n\right)-n^2\left(m+n\right)\)

\(=\left(m+n\right)^2\left(m-n\right)\)

\(=\left(-2017+2017\right)^2\cdot\left(-2017-2017\right)\)

=0

b: \(N=n^3-3n^2-n\left(3-n\right)\)

\(=n^2\left(n-3\right)+n\left(n-3\right)\)

\(=n\left(n-3\right)\left(n+1\right)\)

\(=13\cdot10\cdot14=1820\)