***c,4(x-5)-3(x+7)=-19

Suy ra (4x-20)-(3x+21)=-19

Suy ra (4x-3x)-(20+21)=-19

Suy ra x-41=-19

suy ra x=-19+41

Suy ra x=22

Vậy x=22

Bài 1:

a: \(x=\dfrac{2}{3}:\dfrac{3}{5}=\dfrac{2}{3}\cdot\dfrac{5}{3}=\dfrac{10}{9}\)

b: \(x=\dfrac{17}{8}:\dfrac{7}{17}=\dfrac{17}{8}\cdot\dfrac{17}{7}=\dfrac{289}{56}\)

c: \(x=-\dfrac{3}{4}:\dfrac{7}{12}=\dfrac{-3}{4}\cdot\dfrac{12}{7}=\dfrac{-63}{28}=-\dfrac{9}{4}\)

d: \(\Leftrightarrow x\cdot\dfrac{1}{6}=\dfrac{3}{8}-\dfrac{1}{4}=\dfrac{1}{4}\)

hay \(x=\dfrac{1}{4}:\dfrac{1}{6}=\dfrac{3}{2}\)

e: \(\Leftrightarrow\dfrac{1}{2}:x=-4-\dfrac{1}{3}=-\dfrac{17}{3}\)

hay \(x=-\dfrac{1}{2}:\dfrac{17}{3}=\dfrac{-3}{34}\)

dad

a, 3/4 ÷ x/6 = 0,75

x/6 = 0,75 ÷ 0,75

x/6 = 1

=> x = 6

Vậy x = 6

b, 2,5 . 45/ x = 5/6

45/x = 5/6  ÷ 2,5

45/x = 1/3

=> x = 45 × 3

=> x = 135

Vậy x = 135

c, x/12 + 121,5 = 121,5

x/12 = 121,5 - 121,5

x/12 = 0

=> x = 0

Vậy x = 0

e, 6/8 = 15/x

3/4 = 15/x

=> x = 20

Vậy x = 20

có đúng ko

Tìm số nguyên x, biết:

a, (-4).|x+2|= -8

|x+2| = -8 : (-4)

|x+2| = 2

\(\Rightarrow\left[{}\begin{matrix}x+2=2\\x+2=-2\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=0\\x=-4\end{matrix}\right.\)

Vậy x = 0 ; x = -4

b, 4.|x+1|= 8.(-2)-8.(-5)

4.|x+1|= 8. [ (-2) - (-5) ]

4.|x+1|= 8. 3

4.|x+1|= 24

|x+1| = 6

\(\Rightarrow\left[{}\begin{matrix}x+1=6\\x+1=-6\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=6\\x=-7\end{matrix}\right.\)

Vậy x = 6; x = -7

c, (2.x-4).(x+6)=0

\(\Rightarrow\) 2.x-4 = x + 6

\(\Rightarrow\) 2x : x = 6 + 4

\(\Rightarrow\) x = 10

d,4.(x-5)-3(x+7)= -19

\(\Rightarrow\) 4x - 20 - 3x - 21 = -19

\(\Rightarrow\) ( 4x - 3x ) - ( 20 - 21 ) = -19

\(\Rightarrow\) x - (-1) = -19

\(\Rightarrow\) x + 1 = -19

\(\Rightarrow\) x = -19 - 1 = -20

e, 3.(x-4)-(8-x)=12

\(\Rightarrow\) 3x - 12 - 8 + x = 12

\(\Rightarrow\) 4x - ( 12 + 8 ) = 12

\(\Rightarrow\) 4x - 20 = 12

\(\Rightarrow\) 4x = 32

\(\Rightarrow\) x = 8

f, 7.(x-3)-5.(3-x)=11.x-5

\(\Rightarrow\) 7x - 21 - 5x - 15 = 11x - 5

\(\Rightarrow\) 12x - 36 = 11x - 5

\(\Rightarrow\) 12x - 11x = -5 + 36

\(\Rightarrow\) x = 31

Tập xác định của phương trình

Biến đổi vế trái của phương trình

Phương trình thu được sau khi biến đổi

Lời giải thu được

a) 5 - 4x = 3x - 9

\(\Leftrightarrow5-4x-3x+9=0\)

\(\Leftrightarrow14-7x=0\)

\(\Leftrightarrow7x=14\Leftrightarrow x=2\)

Vậy \(S=\left\{2\right\}\)

b) \(\left(x-4\right)\left(3x+9\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-4=0\\3x+9=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=4\\x=-3\end{matrix}\right.\)

Vậy \(S=\left\{-3;4\right\}\)

c) \(\dfrac{x}{x+4}+\dfrac{12}{x-4}=\dfrac{4x+48}{x\cdot x-16}\)(1)

ĐKXĐ: \(x\ne\pm4\)

\(\left(1\right)\Leftrightarrow\dfrac{x\left(x-4\right)+12\left(x+4\right)-4x-48}{\left(x+4\right)\left(x-4\right)}=0\)

\(\Leftrightarrow x^2-4x+12x+48-4x-48=0\)

\(\Leftrightarrow x^2+4x=0\)

\(\Leftrightarrow x\left(x+4\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x+4=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\left(TM\right)\\x=-4\left(KTM\right)\end{matrix}\right.\)

Vậy \(S=\left\{0\right\}\)

d) \(4-2x=7-x\)

\(\Leftrightarrow4-2x-7+x=0\)

\(\Leftrightarrow-x-3=0\)

\(\Leftrightarrow-x=3\Leftrightarrow x=-3\)

Vậy \(S=\left\{-3\right\}\)

e) \(\left(x+4\right) \left(8-4x\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x+4=0\\8-4x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-4\\x=2\end{matrix}\right.\)

Vậy \(S=\left\{-4;2\right\}\)

f) \(\dfrac{x}{x+5}+\dfrac{11}{x-5}=\dfrac{x+55}{x\cdot x-25}\left(2\right)\)

ĐKXĐ: \(x\ne\pm5\)

\(\left(2\right)\Leftrightarrow\dfrac{x\left(x-5\right)+11\left(x+5\right)-x-55}{\left(x+5\right)\left(x-5\right)}=0\)

\(\Leftrightarrow x^2-5x+11x+55-x-55=0\)

\(\Leftrightarrow x^2+5x=0\)

\(\Leftrightarrow x\left(x+5\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x+5=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\left(TM\right)\\x=-5\left(KTM\right)\end{matrix}\right.\)

Vậy \(S=\left\{0\right\}\)

g) \(\dfrac{3x+2}{2}-\dfrac{3x+1}{6}=\dfrac{5}{3}+2x\)

\(\Leftrightarrow\dfrac{3\left(3x+2\right)-3x-1-10-12x}{6}=0\)

\(\Leftrightarrow9x+6-3x-1-10-12x=0\)

\(\Leftrightarrow-6x-5=0\)

\(\Leftrightarrow-6x=5\)

\(\Leftrightarrow x=-\dfrac{5}{6}\)

Vậy \(S=\left\{-\dfrac{5}{6}\right\}\)

h) \(2x-\left(3-5x\right)=4\left(x+3\right)\)

\(\Leftrightarrow2x-3+5x-4x-12=0\)

\(\Leftrightarrow3x-15=0\)

\(\Leftrightarrow x=5\)

Vậy \(S=\left\{5\right\}\)

i) \(3x-6+x=9-x\)

\(\Leftrightarrow3x-6+x-9+x=0\)

\(\Leftrightarrow5x-15=0\)

\(\Leftrightarrow x=3\)

Vậy \(S=\left\{3\right\}\)

k)\(2t-3+5t=4t+12\)

\(\Leftrightarrow2t-3+5t-4t-12=0\)

\(\Leftrightarrow3t-15=0\)

\(\Leftrightarrow t=5\)

Vậy \(S=\left\{5\right\}\)

Noob ơi, bạn phải đưa vào máy tính ý solve cái là ra x luôn, chỉ tội là đợi hơi lâu

a, 4.(18 - 5x) - 12(3x - 7) = 15(2x - 16) - 6(x + 14) 

=> 72 - 20x - 36x + 84 = 30x - 240 - 6x - 84

=> (72 + 84) + (-20x - 36x) = (30x - 6x) + (-240 - 84) 

=> 156 -  56x = 24x - 324 

=>  24x + 56x = 324 + 156 

=> 80x = 480 

=> x = 480 : 80 =  6 

Vậy x = 6 

b, 5(3x + 5) - 4(2x - 3) = 5x + 3(2x + 12) + 1 

=> 15x + 25 - 8x + 12 = 5x + 6x + 36 + 1 

=> (15x - 8x) + (25 + 12) = 11x + 37 

=> 7x + 37 = 11x + 37 

=> 11x - 7x = 0 

=>  x = 0 

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