1) \(\frac{24}{-12}=\frac{x}{5}=\frac{-y}{3}\)Tìm x và y

2) \(\frac{1}{3}+\frac{-2}{5}+\frac{1}{6}+\frac{-5}{25}\le\frac{x}{10}< \frac{-3}{4}+\frac{4}{14}+\frac{-2}{8}+\frac{-3}{5}+\frac{5}{7}\)Tìm x

3) \(\frac{8.x+18}{2.x+6}\)Tìm x

Tìm x

a)\(5\frac{8}{17}:x+\left(-\frac{4}{17}\right):x+3\frac{1}{7}:17\frac{1}{3}=\frac{4}{11}\)

b)\(\left(x+\frac{1}{5}\right)^2+\frac{17}{25}=\frac{26}{25}\)

Tìm x, biết 

A.\(\left(-1\frac{1}{5}+x\right):\left(-3\frac{3}{5}\right)=-\frac{7}{4}+\frac{1}{4}:\frac{11}{8}\)

B.\(7,5x:\left(5\frac{195}{315}-8\right)=2\frac{13}{15}\)

C.\(60\%x+\frac{2}{3}x+x=688\)

D.\(1-\left(5\frac{3}{8}-x-7\frac{5}{24}\right):16\frac{2}{3}=0\)

a) \(1-\left(5\frac{3}{8}+x-7\frac{5}{24}\right):\left(-16\frac{2}{3}\right)=0\)

b) \(\left(\frac{x}{3}-5\frac{1}{4}\right)^2-\frac{-2}{5}=1\frac{1}{25}\)

c) \(\frac{17-x}{12}=\frac{3}{17-x}\)

d) \(1\frac{1}{3}-25\%\left(x-\frac{8}{3}\right)+2x=1,6:\frac{3}{5}\)

a) \(1-\left(5\frac{3}{8}+x-7\frac{5}{24}\right):\left(-16\frac{2}{3}\right)=0\)0

b) \(\left(\frac{x}{3}-5\frac{1}{4}\right)^2-\frac{-2}{5}=1\frac{1}{25}\)

c) \(1\frac{1}{3}-25\%\left(x-\frac{8}{3}\right)+2x=1,6:\frac{3}{5}\)

Tìm x:

\(5\frac{8}{17}:x+\left(-\frac{4}{17}\right):x+3\frac{1}{7}:17\frac{1}{3}=\frac{4}{11}\)

\(\left(x+\frac{1}{5}\right)^2+\frac{17}{25}=\frac{26}{25}\)

\(-1\frac{5}{27}-\left(3x-\frac{7}{9}\right)^3=\frac{-24}{27}\)

tìm x biết 

1, \(x-\frac{3}{5}=\frac{3}{35}-\frac{-7}{6}\)

2, \(\frac{x}{120}=\frac{3}{8}\cdot\frac{-4}{25}\)

3, \(\frac{11}{13}\cdot x=1\)

4, \(-\frac{9}{8}+\frac{-3}{8}\cdot x=\frac{-1}{8}\)

5, \(\frac{-2}{5}\cdot x+\frac{4}{3}=\frac{7}{3}\)