\(\dfrac{-1}{39}+\dfrac{-1}{52}=\dfrac{-7}{156}\)

\(\dfrac{-6}{9}+\dfrac{-12}{16}=\dfrac{-17}{12}\)

\(\dfrac{-2}{5}-\dfrac{-3}{11}=\dfrac{-7}{55}\)

\(\dfrac{-34}{37}.\dfrac{74}{-85}=\dfrac{4}{5}\)

\(\dfrac{-5}{9}:\dfrac{-7}{18}=\dfrac{10}{7}\)

Chúc bạn học tốt!!!

a) \(\left(-\dfrac{1}{39}\right)+\left(-\dfrac{1}{52}\right)=\dfrac{-4-3}{156}=-\dfrac{7}{156}\)

b) \(\left(-\dfrac{6}{9}\right)+\left(-\dfrac{12}{16}\right)=-\dfrac{6}{9}-\dfrac{12}{16}=-\dfrac{17}{12}\)

c) \(-\dfrac{2}{5}-\left(-\dfrac{3}{11}\right)=-\dfrac{2}{5}+\dfrac{3}{11}=-\dfrac{7}{55}\)

d) \(\left(-\dfrac{34}{37}\right)\cdot\left(-\dfrac{74}{85}\right)=2\cdot\dfrac{2}{5}=\dfrac{4}{5}\)

e) \(\left(-\dfrac{5}{9}\right):\left(-\dfrac{7}{18}\right)=\dfrac{5}{9}\cdot\dfrac{18}{7}=5\cdot\dfrac{2}{7}=\dfrac{10}{7}\)

Giải:

\(\left(\dfrac{1}{4}+\dfrac{11}{9}\right):\dfrac{34}{5}+\left(\dfrac{-2}{9}+\dfrac{29}{4}\right):\dfrac{34}{5}\)

\(=\left(\dfrac{1}{4}+\dfrac{11}{9}\right).\dfrac{5}{34}+\left(\dfrac{-2}{9}+\dfrac{29}{4}\right).\dfrac{5}{34}\)

\(=\left[\left(\dfrac{1}{4}+\dfrac{11}{9}\right)+\left(\dfrac{-2}{9}+\dfrac{29}{4}\right)\right].\dfrac{5}{34}\)

\(=\left[\dfrac{1}{4}+\dfrac{11}{9}-\dfrac{2}{9}+\dfrac{29}{4}\right].\dfrac{5}{34}\)

\(=\left[\dfrac{9}{9}+\dfrac{30}{4}\right].\dfrac{5}{34}\)

\(=\left[1+\dfrac{15}{2}\right].\dfrac{5}{34}\)

\(=\dfrac{17}{2}.\dfrac{5}{34}\)

\(=\dfrac{5}{4}\)

Vậy ...

a)9.x + 1=73

 9x=73-1

9x=72

  x=72:9

  x=8

b)2.x - 5 = -17 - 12

2x-5=-29

2x=-29+5

2x=-24

  x=-24:2

  x=-12

c)10 - x - 5 = - 5 - 7 -11

10-x-5=-12-11

10-x-5=-23

 10-x=-23+5 

  10-x=18

       x=10-18

       x=-8

d)(-9) . x + 3 = (-2) . (-7) +16

-9x+3=14+16

-9x+3=30

-9x=30-3

-9x=27

   x=27:(-9)

   x=-3

(-12) . x - 34 =2

-12x=2+34

-12x=36

     x=36:(-12)

     x=-3

(-11).x + 9 =130

-11x=130-9

-11x=121

     x=121:(-11)

     x=11 

(-5) .x + 5 = (-15) .(-4) -12

-5x+5=60-12

-5x+5=48

-5x=48-5

-5x=43

   x=43:(-5)

  x=-8,6

IxI -3=0

|x|=3

=>x=+3

(7 - IxI).(2.x - 4) =0

*7-|x|=0            * 2x-4=0

|x|=7                   2x=4

=>x=+7                 x=4:2

                             x=2

280-(x-140):35 =270

(x-140):35=280-270

(x-140):35=10

x-140=10.35

x-140=350

       x=350+140

       x=490

(1900 - 2.x ) : 35- 32 =16

1900-2x=(16+32).35

1900-2x=1680

         2x=1900-1680

         2x=220

           x=220:2

           x=110

720 :[41-(2x -5 )] =2³ .5

720:[41-(2x-5)]=40

41-(2x-5)=720:40

41-(2x-5)=18

2x-5=41-18

2x-5=23

2x=23+5

2x=28

  x=28:2

  x=14

(x - 5).(x² - 4 ) =0

* x-5=0           * x²-4=0

      x=0+5         x²=4

      x=5             x²=2²

                    => x=+2

\(c,\dfrac{-3}{8}.\dfrac{2}{5}+\dfrac{-3}{8}.\dfrac{14}{5}\\ =\dfrac{-3}{8}.\left(\dfrac{2}{5}+\dfrac{14}{5}\right)\\ =\dfrac{-3}{8}.\dfrac{16}{5}\\ =\dfrac{-6}{5}\\ d,\left(\dfrac{1}{4}+\dfrac{11}{9}\right):\dfrac{34}{5}+\left(\dfrac{-2}{9}+\dfrac{29}{4}\right):\dfrac{34}{5}\\ =\left(\dfrac{1}{4}+\dfrac{11}{9}\right).\dfrac{5}{34}+\left(\dfrac{-2}{9}+\dfrac{29}{4}\right).\dfrac{5}{34}\\ =\left(\dfrac{1}{4}+\dfrac{11}{9}+\dfrac{-2}{9}+\dfrac{29}{4}\right).\dfrac{5}{34}\\ =\left[\left(\dfrac{1}{4}+\dfrac{29}{4}\right)+\left(\dfrac{11}{9}+\dfrac{-2}{9}\right)\right].\dfrac{5}{34}\\ =\left(\dfrac{15}{2}+1\right).\dfrac{5}{34}\\ =\dfrac{17}{2}.\dfrac{5}{34}\\ =\dfrac{5}{4}\)

c) \(\dfrac{-3}{8}.\dfrac{2}{5}+\dfrac{-3}{8}.\dfrac{14}{5}\)

\(=\dfrac{-3}{8}.\left(\dfrac{2}{5}+\dfrac{14}{5}\right)\)

\(=\dfrac{-3}{8}.\dfrac{16}{5}\)

\(=\dfrac{-6}{5}\)

Giải thích rút gọn 16 cho 8 được 2

câu cuối nè 7/9-2/9:x=1/6

5/9:x=1/6

x=5/9:1/6

x=10/3

(-13/31 + -18/31) : 5/17 . 25/34 = -1 . 17/5 . 25/34

                                             = -17/5 . 25/34

                                             = -425/170

                                             = -5/2

=91827281817272119382371

đoạn cuối thiếu dấu"+"

\(A=\dfrac{\sqrt{4}-\sqrt{5}}{4-5}+\dfrac{\sqrt{5}-\sqrt{6}}{5-6}+....+\dfrac{\sqrt{34}-\sqrt{35}}{34-35}+\dfrac{\sqrt{35}-\sqrt{36}}{335-36}\)

\(A=\dfrac{\sqrt{4}-\sqrt{5}+\sqrt{5}-\sqrt{6}+....+\sqrt{35}-\sqrt{36}}{-1}=\dfrac{\sqrt{4}-\sqrt{36}}{-1}\)

\(A=\sqrt{36}-\sqrt{4}=6-2=4\)

\(\dfrac{1}{\sqrt{4}+\sqrt{5}}+\dfrac{1}{\sqrt{5}+\sqrt{6}}+\dfrac{1}{\sqrt{6}+\sqrt{7}}+...+\dfrac{1}{\sqrt{34}+\sqrt{35}}+\dfrac{1}{\sqrt{35}+\sqrt{36}}\)

\(=-\sqrt{4}+\sqrt{5}-\sqrt{5}+\sqrt{6}-...-\sqrt{35}+\sqrt{36}\)

\(=6-2=4\)