A=\(\frac{72^3.54^2}{108^4}=\frac{\left(2^3.3^2\right)^3.\left(2.3^3\right)^2}{\left(2^2.3^3\right)^4}=\frac{2^9.3^6.2^2.3^6}{2^8.3^{12}}=\frac{2^{11}.3^{12}}{2^8.3^{12}}=2^3=8\)

B= \(\frac{4^6.3^4.9^5}{6^{12}}=\frac{2^{12}.3^4.3^{10}}{2^{12}.3^{12}}=\frac{2^{12}.3^{14}}{2^{12}.3^{12}}=3^2=9\)

c) \(\frac{2^{13}+2^5}{2^{10}+2^2}=\frac{2^5\left(2^8+1\right)}{2^2\left(2^8+1\right)}=2^3=8\)

1.

\(\frac{72^3\times54^2}{108^4}=\frac{\left(8\times9\right)^3\times\left(27\times2\right)^2}{\left(27\times4\right)^4}=\frac{\left(2^3\times3^2\right)^3\times\left(3^3\times2\right)^2}{\left(3^3\times2^2\right)^4}=\frac{\left(2^3\right)^3\times\left(3^2\right)^3\times\left(3^3\right)^2\times2^2}{\left(3^3\right)^4\times\left(2^2\right)^4}=\frac{2^9\times3^6\times3^6\times2^2}{3^{12}\times2^8}=2^3=8\)

2.

\(\frac{4^6\times3^4\times9^5}{6^{12}}=\frac{\left(2^2\right)^6\times3^4\times\left(3^2\right)^5}{\left(2\times3\right)^{12}}=\frac{2^{12}\times3^4\times3^{10}}{2^{12}\times3^{12}}=3^2=9\)

3.

\(\frac{2^{13}+2^5}{2^{10}+2^2}=\frac{2^5\times\left(2^8+1\right)}{2^2\times\left(2^8+1\right)}=2^3=8\)

bn ơi, cho mjk cách lm với 

Giải: (^ là mũ)

a) 3^8 : 3^4 + 2^2 . 2^3

= 6561 : 81 + 4 . 8

= 81 + 32

= 113

Mấy câu sau bn làm tương tự nhé!

b: \(=2^{12}\cdot3^4\cdot\dfrac{3^{10}}{3^{12}\cdot2^{12}}=3^2=9\)

c: \(=\dfrac{7^2\cdot3^2\cdot7\cdot2\cdot5^3}{5^3\cdot7^3\cdot2\cdot3}=\dfrac{3^2}{3}=3\)

d: \(=\dfrac{5^3\cdot3^6\cdot5^4\cdot2^8\cdot3^{16}\cdot2^2}{\left(2^2\cdot3^2\cdot5\right)^5}=\dfrac{5^{10}\cdot3^{22}\cdot2^{10}}{2^{10}\cdot3^{10}\cdot5^5}=3^{12}\cdot5^5\)

a, \(\dfrac{3^8}{3^4}+2^2.2^3\)
= 3⁴ + 2⁵
= 113
b, 3.4² - 2.3²
= 3.(4² - 2.3)
= 3.(16 - 6)
= 3.10
= 30
c, \(\dfrac{4^6.3^4.9^5}{6^{12}}\)

= \(\dfrac{\left(2^2\right)^6.3^4.\left(3^2\right)^5}{\left(2.3\right)^{12}}\)

= \(\dfrac{2^{12}.3^4.3^{10}}{2^{12}.3^{12}}\)

= \(\dfrac{3^{14}}{3^{12}}\)

= 3²
@Dương Tuyết Mai

a.3^8:3^4+2^2.2^3

=3^4+2^5

=81+32

=113

b.2^8+4.135+175:25

=256+540+7

=256+547

=803

mấy bài kia bn cứ làm như thế nha!

mik biết nhưng ko thể trả lời hết

\(A=\frac{4157-19}{12471-57}\)\(=\frac{4138}{12414}\)\(=\frac{4138:4138}{12414:4138}\)\(=\frac{1}{3}\)

\(B=\frac{7}{10^2+8.10^2}\)\(=\frac{7}{100+8.100}\)\(=\frac{7}{100+800}\)\(=\frac{7}{900}\)

\(C=\frac{31995}{42660-108}\)\(=\frac{31995}{42552}\)\(=\frac{31995:27}{42552:27}\)\(=\frac{1185}{1576}\)

\(D=\frac{2^{45}.5^3.2^6.3}{8.2^{18}.81.5}=\frac{2^{51}.5^3.3}{2^3.2^{18}.3^4.5}=\frac{2^{51}.5^3.3}{2^{21}.3^4.5}=\frac{2^{30}.5^2}{3^3}\)

k mình nhé.

A=4138/12414=1/3

B=7/900

C=31995/42552=1185/1576

Phần D tui chịu, ahihi

\(\frac{4^6.3^4.9^5}{6^{12}}=\frac{\left(2^2\right)^6.3^4.\left(3^2\right)^5}{2^{12}.3^{12}}=\frac{2^{12}.3^4.3^{10}}{2^{12}.3^{12}}=\frac{2^{12}.3^{14}}{2^{12}.3^{12}}=3^2=9\)

\(\frac{4^6\cdot3^4\cdot9^5}{6^{12}}\)

\(=\frac{2^{12}\cdot3^4\cdot3^{10}}{2^{12}\cdot3^{12}}\)

\(=\frac{1\cdot3^{14}}{1\cdot3^{12}}\)

\(=\frac{3^{14}}{3^{12}}\)

\(=3^2\)

\(=9\)