Tính hợp lí :
A = 1+2+3+...+20
Tính bằng cách hợp lí : 1+1/2.(1+2)+1/3.(1+2+3)+.........+1/20.(1+2+3+...+20)
1) Thực hiện phép tính một cchs hợp lí:
S= 1+1/2.(1+2)+1/3.(1+2+3)+...+1/20.(1+2+3+..+20)
1+1/2.2.3/2+1/3.3.4/2+...........+1/20.20.21/2
=1+24.19/2=229
Tính hợp lí
a/1+2+3+4+...+20
b2+4+6+8+...+2014
c/5+10+15+20+...+2015
Thực hiện phép tính hợp lí nhất
1 +1/2 (1+2) +1/3 ( 1+ 2 +3 ) + 1/4 (1+2+3+4) + ....+ 1/20 (1+2+3+....+20)
=1+1/2.(3.2/2)+1/3.(4.3/2)+1/4.(5.4/2)+...+1/20.(21.20/2)
=1+3/2+2+5/2+...+21/2 ( rút gọn)
=2/2+3/2+4/2+5/2+...+21/2
=(2+3+4+5+...+21)/2=(20.23)/2.2=(20.23)/4
=23.5=115
Ko bt mk lm dung ko nx?
1.Tính hợp lí
a) 1/2 + 1/6 + 1/12 + 1/20 + 1/30
b)3/10 + 3/40 + 3/88 + 3/154
a)\(=\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+\frac{1}{5\cdot6}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}\)
\(=\left(1-\frac{1}{6}\right)+\left(\frac{1}{2}-\frac{1}{2}\right)+...+\left(\frac{1}{5}-\frac{1}{5}\right)\)
\(=\left(1-\frac{1}{6}\right)+0+...+0=1-\frac{1}{6}=\frac{6}{6}-\frac{1}{6}=\frac{5}{6}\)
b)\(\frac{3}{2\cdot5}+\frac{3}{5\cdot8}+\frac{3}{8\cdot11}+\frac{3}{11\cdot14}=\frac{1}{2}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+\frac{1}{11}-\frac{1}{14}\)
\(=\left(\frac{1}{2}-\frac{1}{14}\right)+\left(\frac{1}{5}-\frac{1}{5}\right)+\left(\frac{1}{8}-\frac{1}{8}\right)+\left(\frac{1}{11}-\frac{1}{11}\right)\)
\(=\left(\frac{1}{2}-\frac{1}{14}\right)+0+...+0=\frac{1}{2}-\frac{1}{14}=\frac{7}{14}-\frac{1}{14}=\frac{6}{14}\)
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Tính hợp lí:
A=\(\frac{4^{20}-2^{20}+6^{20}}{6^{20}-3^{20}+9^{20}}\)
\(A=\frac{4^{20}-2^{20}+6^{20}}{6^{20}-3^{20}+9^{20}}\)
\(A=\frac{2^{20}.2^{20}-2^{20}+3^{20}.2^{20}}{2^{20}.3^{20}-3^{20}+3^{20}.3^{20}}\)
\(A=\frac{\left(2^{20}-1+3^{20}\right).2^{20}}{\left(2^{20}-1+3^{20}\right).3^{20}}\)
\(\Rightarrow A=\frac{2^{20}}{3^{20}}\)
Tính tổng theo cách hợp lí:
S=12+22+32+....+202-(1+2+3+....+20)
Tính hợp lí nếu có thể
b) \(\dfrac{6^3+3.6^2+3^3}{-13}\)
a) \(\dfrac{20^5.5^{10}}{100^5}\)
b:\(=\dfrac{3^3\cdot2^3+3\cdot2^2\cdot3^2+3^3}{-13}=\dfrac{3^3\left(2^3+2^2+1\right)}{-13}=-3^3=-27\)
a: \(=\dfrac{5^5\cdot4^5\cdot5^{10}}{10^{20}}=\dfrac{5^{15}\cdot2^{10}}{5^{20}\cdot2^{20}}=\dfrac{1}{5^5\cdot2^{10}}\)
b) \(\dfrac{6^3+3.6^2+3^3}{-13}=\dfrac{2^3.3^3+3.3^2.2^2+3^3}{-13}=\dfrac{3^3\left(2^3+2^2+1\right)}{-13}\)
\(=\dfrac{3^3.\left(8+4+1\right)}{-13}=\dfrac{3^3.13}{-13}=\dfrac{27}{-1}=-27\)
a)\(\dfrac{20^5.5^{10}}{100^5}=\dfrac{20^5.5^{10}}{20^5.5^5}=\dfrac{5^5}{1}=3125\)
Tính nhanh các tổng sau một cách hợp lí
A=1+2+3+...+20
B=1+3+5+...+21
C=2+4+6+...+22
a.SSH : ( 20 - 1 ) : 1 + 1 = 20
tổng : (20 + 1 ) x 20 :2 = 210
b . SSH : (21 - 1) :2 +1 = 11
tổng ; (21 + 1 ) x 11 : 2 = 121
c. SSH : ( 22 - 2 ) : 2 + 1 = 11
tổng : ( 22 + 2) x 11 : 2 = 132
A=1+2+3+...+20
=(20-1) : 1+1
=20
Tổng là (20+1)x20:2=210
B=1+3+5+...+21
=(21-1) : 2+1
=11
Tổng là (21+1)x11:2=121
C=2+4+6+...+22
=(22-2) :2+1
=11
Tổng là : (22+2) x11:2=132