TL

=-3545807085

nha bn chưa chưa chắc đã đúng

HT 

=6,953,656,803,105

TL:

\(=-3545807085\)

Phải dùng đến máy tính

_HT_

a )

2¹⁰⁰+2¹⁰⁰= 2¹⁰⁰(1+1) =2¹⁰⁰.2 = 2¹⁰⁰⁺¹= 2¹⁰¹

b)

3¹⁰⁰+3¹⁰⁰ = 3¹⁰⁰(1+1) = 2.3¹⁰⁰ 

3¹⁰¹= 3¹⁰⁰.3

ta thấy 3. 3¹⁰⁰ > 2.3¹⁰⁰  Vậy 3¹⁰¹ > 3¹⁰⁰+3¹⁰⁰

c)  2017⁷⁰¹²  > 2017^2337.3 >>> 8000²³³⁷

  7012²⁰¹⁷ < 8000²³³⁷

suy ra:  2017⁷⁰¹² >>> 7012²⁰¹⁷

\(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}\)

\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{8}+\frac{1}{8}-\frac{1}{16}+\frac{1}{16}-\frac{1}{32}+\frac{1}{32}-\frac{1}{64}\)

\(=1-\frac{1}{64}\)

\(=\frac{63}{64}\)

      \(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}\)

\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{8}+\frac{1}{8}-\frac{1}{16}+\frac{1}{16}-\frac{1}{32}+\frac{1}{32}-\frac{1}{64}+\frac{1}{64}\)

\(=1-\frac{1}{64}\)

\(=\frac{63}{64}\)

\(\frac{1}{2}+\frac{1}{4}+....+\frac{1}{64}\)

\(2.\left(\frac{1}{2}+\frac{1}{4}+...+\frac{1}{64}\right)\)

\(=>1+\frac{1}{2}+...+\frac{1}{32}\)

\(=>.....\)

5 + 2 + 6 + 3 + 8 + 4 + 1 + 0 + 9 + 7+ 10 = 55

Bằng 55

= 55 đúng không bạn

= nhau nha

\(2/3*4/5=8/15\)

\(4/5*2/3=8/15\)

\(=>2/3*4/5=4/5*2/3\) nhé

8/15=8/15

k cho minh nha

noichung ai k minh thi minh k cho

\(\left(1-\frac{1}{2}\right)\left(1-\frac{1}{3}\right)\left(1-\frac{1}{4}\right).....\left(1-\frac{1}{10}\right)\)

\(=\frac{1}{2}.\frac{2}{3}.\frac{3}{4}.......\frac{9}{10}=\frac{1.2.3......9}{2.3.4.....10}=\frac{1}{10}\)

Bài 1

\(2^{1995}=2^5\times2^{1990}=32\times2^{1990}\)

Mà \(32\div31\)dư \(1\)nên\(\left(32\times2^{1990}\right)\div31\)dư \(1\)

\(\Rightarrow\left(32\times2^{1900}-1\right)⋮31\)

hay 

\(\left(2^{1995}-1\right)⋮31\)

Bài 2

Làm tương tự

cảm ơn nhiều nhé