Một vận động viên xe đạp đua đi ba chặng đường hết tất cả 8h40ph trạng một hết 2h40p trạng hai mất ít hơn chạm bốn 1,45ph hỏi trạm ba đi mất bao nhiêu phút ?

Ai giúp mk với 

\(\left(\frac{1}{1.2.3}+\frac{1}{2.3.4}+...+\frac{1}{8.9.10}\right).x=\frac{23}{45}\)

\(\left(\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+...+\frac{1}{8.9}-\frac{1}{9.10}\right).x=\frac{23}{45}\)

\(\left(\frac{1}{1.2}-\frac{1}{9.10}\right).x=\frac{23}{45}\)

\(\frac{22}{45}.x=\frac{23}{45}\)

\(x=\frac{23}{45}:\frac{22}{45}\)

\(x=\frac{23}{22}\)

\(\left(\frac{1}{1.2.3}+\frac{1}{2.3.4}+...+\frac{1}{8.9.10}\right)x=\frac{23}{45}\)

\(\Rightarrow\left(\frac{2}{1.2.3}+\frac{2}{2.3.4}+...+\frac{2}{8.9.10}\right).\frac{x}{2}=\frac{23}{45}\)

\(\Rightarrow\left(\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+...+\frac{1}{8.9}-\frac{1}{9.10}\right)x=\frac{46}{45}\)

\(\Rightarrow\left(\frac{1}{1.2}-\frac{1}{9.10}\right)x=\frac{46}{45}\)

\(\Rightarrow\frac{22}{45}.x=\frac{46}{45}\Rightarrow x=\frac{46}{22}=\frac{23}{11}\)

1: \(\dfrac{x-3}{x+1}=\dfrac{x^2}{x^2-1}\)

=>(x-3)(x-1)=x^2

=>x^2=x^2-4x+3

=>-4x+3=0

=>x=3/4

2: \(\dfrac{5}{3x+2}=2x-1\)

=>(2x-1)(3x+2)=5

=>6x^2+4x-3x-2-5=0

=>6x^2+x-7=0

=>6x^2+7x-6x-7=0

=>(6x+7)(x-1)=0

=>x=1hoặc x=-7/6

bn ghi dấu ra nha!!Chứ mik nhìn mik ko hỉu j lun

\(17\times109-17\times53+56\times96-13\times56\)

\(=17\times\left(109-53\right)+56\times\left(96-13\right)\)

\(=17\times56+56\times83\)

\(=56\times\left(17+83\right)\)

\(=56\times100\)

\(=5600\)

\(8\times27\times3+2\times31\times12+6\times12\times4\)

\(=24\times27+24\times31+24\times12\)

\(=24\times\left(27+31+12\right)\)

\(=24\times70\)

\(=1680\)

\(15\times47+15\times33+60\times39+60\times41\)

\(=15\times\left(47+33\right)+60\times\left(39+41\right)\)

\(=15\times80+60\times80\)

\(=80\times\left(15+60\right)\)

\(=80\times75\)

\(=6000\)

\(97\times59-59\times31-66\times49\)

\(=59\times\left(97-31\right)-66\times49\)

\(=59\times66-66\times49\)

\(=66\times\left(59-49\right)\)

\(=66\times10\)

\(=660\)

Học tốt

bạn viết đề thì ghi rõ ràng dấu ra nha, mình đọc không hiểu j 

\(S=\frac{3}{5.7}+\frac{3}{7.9}+.....+\frac{3}{59.61}\)

\(=\frac{3}{2}.\left(\frac{2}{5.7}+\frac{2}{7.9}+......+\frac{2}{59.61}\right)\)

=\(\frac{3}{2}.\left(\frac{7-5}{5.7}+\frac{9-7}{7.9}+......+\frac{61-59}{59.61}\right)\)

=\(\frac{3}{2}.\left(\frac{7}{5.7}-\frac{5}{5.7}+\frac{9}{7.9}-\frac{7}{7.9}+.....+\frac{61}{59.61}-\frac{59}{59.61}\right)\)

=\(\frac{3}{2}.\left(\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+.....+\frac{1}{59}-\frac{1}{61}\right)\)

=\(\frac{3}{2}.\left(\frac{1}{5}-\frac{1}{61}\right)\)

=\(\frac{3}{2}.\frac{56}{305}\)

=\(\frac{84}{305}\)

bn viết phép tính ra đi, viết thế này khó đọc lắm

Đặt A=\(\frac{1}{3}.5+\frac{1}{5}.7+...+\frac{1}{97}.99\)

=>A=\(\frac{1}{3.5}+\frac{1}{5.7}+...+\frac{1}{97.99}\)

=>2A=\(\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{97.99}\)

=>2A=\(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{97}-\frac{1}{99}\)

=>2A=\(\frac{1}{3}-\frac{1}{99}=\frac{33}{99}-\frac{1}{99}=\frac{32}{99}\)

=>A=\(\frac{32}{99}:2=\frac{32}{99}.\frac{1}{2}=\frac{32}{198}=\frac{16}{99}\)