`x/2+x+x/3+x+x+x/4=5 3/4`

`=>3x+x/2+x/3+x/4=23/4`

`=>49/12x=23/4`

`=>x=69/49`

Vậy `x=69/49`

giúp mik với xin các bạn đó mik đnag cần gấp

Soạn đề bằng thanh công cụ cho rõ nha bạn

5(x-1)=125-25

5(x-1)=100

x-1=100:5

x-1=20

x=20+1

x=21

12(x-1):3=64+8

12(x-1):3=72

12(x-1)=72.3

12(x-1)=216

x-1=216:12

x-1=18

x=18+1

x=19

(x-1)^3=5^3

=>x-1=5

x=5+1

x=6

`5/2 -3(1/3-x)=1/4-7x`

`=> 5/2 - 1 + 3x=1/4 -7x`

`=>3x+7x= 1/4 - 5/2 +1`

`=> 10x= 1/4 - 10/4 +4/4`

`=>10x= -5/4`

`=>x=-5/4 :10`

`=>x=-5/4 xx1/10`

`=>x= -5/40=-1/8`

=>5/2-3+3x=1/4-7x

=>10x=1/4-5/2+3=3/4

=>x=3/40

\(4^{x+3}+4^{x+2}+4^{x+1}+4^x=5440\)

\(\Rightarrow4^x.4^3+4^x.4^2+4^x.4+4^x=5440\)

\(\Rightarrow4^x\left(4^3+4^2+4+1\right)=5440\)

\(\Rightarrow4^x.\left(64+16+4+1\right)=5440\)

\(\Rightarrow4^x.85=5440\)

\(\Rightarrow4^x=5440:85\)

\(\Rightarrow4^x=64=4^3\)

\(\Rightarrow x=3\)

\(2\cdot11^x=\left(3^2+2\right)^3:\left(5^3-2^5:2^3\right)\)

\(\Leftrightarrow11^x\cdot2=1331:121\)

\(\Leftrightarrow11^x\cdot2=11\)

=> Phương trình vô nghiệm