tính :
\(\frac{45^3.20^4.18^2}{180^5}\)
45^3.20^4.18^2/180^5
45^3.20^4.18^2/180^5
Tính giá trị biểu thức :
C = \(\frac{21^2.14.125}{35^3.6}\)
D = \(\frac{45^3.20^4.18^2}{180^5}\)
\(C=\frac{21^2.14.125}{35^3.6}\)
\(C=\frac{\left(3.7\right)^2.2.7.5^3}{\left(5.7\right)^3.2.3}\)
\(C=\frac{3^2.7^2.2.7.5^3}{5^3.7^3.2.3}\)
\(C=\frac{3^2.7^3.2.5^3}{5^3.7^3.2.3}=3\)
\(D=\frac{45^3.20^4.18^2}{180^5}\)
\(D=\frac{\left(5.3^2\right)^3.\left(2^2.5\right)^4.\left(2.3^2\right)^2}{\left(2^2.3^2.5\right)^5}\)
\(D=\frac{5^3.3^6.2^8.5^4.2^2.3^4}{2^{10}.3^{10}.5^5}\)
\(D=\frac{5^7.3^{10}.2^{10}}{2^{10}.3^{10}.5^5}=5^2=25\)
Tính giá trị của các biểu thức:
G=21^2.14.125/35^5.6
H= 45^3.20^4.18^2/180^5
HELP ME
G=(212.14.125):355.6
=\(\frac{\left(3.7\right)^2.7.2.5^{^3}}{\left(7.5\right)^5.2.3}\)=\(\frac{3^2.7^2.7.5^3}{7^5.5^5.3}\)=\(\frac{3}{7^2.5^2}\)=\(\frac{3}{49.25}\)=\(\frac{3}{1225}\)
\(G=\frac{21^2.14.125}{35^5.6}\)
\(G=\frac{\left(3.7\right)^2.7.2.5^3}{\left(7.5\right)^5.2.3}=\frac{3}{7^2.5^2}=\frac{3}{49.25}=\frac{3}{1225}\)
1)\(\frac{21^2.14.125}{35^2.6}\)
2)\(\frac{45^3.20^4.18^2}{180^5}\)
AI TRA LOI DUOC MK TICK CHO !!! CAM ON !!!
\(\frac{21^2\cdot14\cdot125}{35^2\cdot6}=\frac{3^2\cdot7^2\cdot2\cdot25\cdot3}{5^2\cdot7^2\cdot2\cdot3}=\frac{3^4\cdot7^2\cdot2\cdot5^2}{5^2\cdot7^2\cdot2\cdot3}=3^3=27..\)
\(\frac{45^3\cdot20^4\cdot18^2}{180^5}=\frac{5^3\cdot9^3\cdot4^4\cdot5^4\cdot2^2\cdot9^2}{2^{10}\cdot3^{10}\cdot5^5}=\frac{5^7\cdot9^5\cdot4^4}{4^5\cdot9^5\cdot5^5}=\frac{1}{4}=0.25\)
1) = 7*3*2*7*5*5*5/7*5*7*5*2*3
câu 2 tt
Tìm x
a, 32x+1 . 11 + 2673
b, \(\frac{45^3.20^4.18^2}{180^5}\)
c. \(\frac{2^{13}+2^5}{2^{10}+2^2}\)
rút gọn phân số
a)\(\dfrac{4^6.3^4.9^5}{6^{12}}\)
b)\(\dfrac{21^2.14.125}{35^2.6}\)
c)\(\dfrac{45^3.20^4.18^2}{180^5}\)
d)\(\dfrac{2^{13}+2^5}{2^{10}+2^2}\)
a: \(=\dfrac{2^{12}\cdot3^{14}}{3^{12}\cdot2^{12}}=3^2=9\)
b: \(=\dfrac{7^3\cdot2\cdot5^3}{5^2\cdot7^2\cdot6}=7\cdot5\cdot\dfrac{1}{3}=\dfrac{35}{3}\)
d: =2^5(2^8+1)/2^2(2^8+1)=2^3=8
c: \(=\dfrac{5^3\cdot3^6\cdot2^8\cdot5^4\cdot3^4\cdot2^2}{2^{10}\cdot3^{10}\cdot5^5}=5^2\)
tính nhẩm : 45^3.20^4.18^2:16^4.100
\(\frac{45^3.20^4.18^2}{16^4.100}\)
\(=\frac{5^3.3^6.5^4.4^4.2^2.3^4}{2^{16}.2^2.5^2}\)
\(=\frac{5^7.3^{10}.2^{10}}{2^{18}.5^2}\)
\(=\frac{5^2.3^{10}}{2^8}\)
\(=\frac{25.59049}{256}\)
\(=\frac{1476225}{256}\)
453 .204.182: 164.100
=(32.5)3.(5.22)4.(32.2)2:(24)4 .22.52
=36.53.54.28.34.22:216.22.52
= 36+4.53+4+2.28+2- 16+2
= 310. 59 . 2-4
Cho mk hỏi thêm D=\(\dfrac{21^2.14.125}{35^3.6}\); E= \(\dfrac{45^3.20^4.18^2}{180^5}\)và F= \(\dfrac{2^{13}+2^5}{2^{10}+2^2}\)nhé. Cảm ơn mọi người rất nhiều. Tại mk học thêm mà mk thấy khó quá nên hỏi:))
d) Ta có: \(D=\dfrac{21^2\cdot14\cdot125}{35^3\cdot6}\)
\(=\dfrac{7^2\cdot3^2\cdot7\cdot2\cdot5^3}{5^3\cdot7^3\cdot6}\)
\(=\dfrac{3^2\cdot2}{6}=\dfrac{6\cdot3}{6}=3\)
e) Ta có: \(E=\dfrac{45^3\cdot20^4\cdot18^2}{180^5}\)
\(=\dfrac{3^6\cdot5^3\cdot2^8\cdot5^4\cdot3^4\cdot2^2}{2^{10}\cdot3^{10}\cdot5^5}\)
\(=\dfrac{3^{10}\cdot5^7\cdot2^{10}}{2^{10}\cdot3^{10}\cdot5^5}=25\)
f) Ta có: \(F=\dfrac{2^{13}+2^5}{2^{10}+2^2}\)
\(=\dfrac{2^5\left(2^8+1\right)}{2^2\left(2^8+1\right)}=\dfrac{2^5}{2^2}=\dfrac{32}{4}=8\)
Giải:
\(D=\dfrac{21^2.14.125}{35^3.6}\)
\(D=\dfrac{\left(3.7\right)^2.\left(2.7\right).5^3}{\left(5.7\right)^3.\left(2.3\right)}\)
\(D=\dfrac{3^2.7^2.2.7.5^3}{5^3.7^3.2.3}\)
\(D=\dfrac{3^2.7^3.2.5^3}{5^3.7^3.2.3}\)
\(D=3\)
\(E=\dfrac{45^3.20^4.18^2}{180^5}\)
\(E=\dfrac{\left(3^2.5\right)^3.\left(2^2.5\right)^4.\left(2.3^2\right)^2}{\left(2^2.3^2.5\right)^5}\)
\(E=\dfrac{\left(3^2\right)^3.5^3.\left(2^2\right)^4.5^4.2^2.\left(3^2\right)^2}{\left(2^2\right)^5.\left(3^2\right)^5.5^5}\)
\(E=\dfrac{3^6.5^7.2^8.2^2.3^4}{2^{10}.3^{10}.5^5}\)
\(E=\dfrac{3^{10}.5^7.2^{10}}{2^{10}.3^{10}.5^5}\)
\(E=5^2=25\)
\(F=\dfrac{2^{13}+2^5}{2^{10}+2^2}\)
\(F=\dfrac{2^2.2^3.2^8+2^2.2^3}{2^2.2^8+2^2}\)
\(F=\dfrac{2^2.2^3\left(2^8+1\right)}{2^2.\left(2^8+1\right)}\)
\(F=2^3=8\)
Bài này lúc đầu mk cx ko thành thạo về bài này nên mk thấy khó nhưng sau đó mk luyện bài này nên đã lm quên vs bài này rồi!
Mk gợi ý lm bài này nha:
Nếu là nhân hay chia mk phải phân tích ra thừa số
Nếu là cộng hay trừ mk phải tách ra sao cho nó có thể tính nhanh
Đấy là cách lm của mk!