phan tich thanh hang dang thuc x^2+y^2+z^2
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phan tich da thuc thanh nhan tu
x^2-x-y^2-y
x^2-2xy+y^2-z^2
bai 32 va 33 sbt
lop 8 bai phan tich da thuc thanh nhan tu bang cach nhom hang tu
Ta có
a, x2-x-y2-y
=x2-y2-(x+y)
=(x-y)(x+y) - (x+y)
=(x+y)(x-y-1)
b, x2-2xy+y2-z2
=(x-y)2-z2
=(x-y-z)(x-y+z)
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con bai 32, 33 neu ban tra loi duoc minh h them
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phan tich da thuc thanh nhan tu bang pp dung hang dang thuc:
a) 16x^2 - (x^2 + 4)^2
b) 27x^3 - 54x^2 + 36x - 8
c) (x+y)^3 - (x-y)^3
help me
a) 16x2-(x2+4)2= (4x)2-(x2+4)2
= (4x-x2-4)(4x+x2+4)
\(\text{b) 27x^3-54x^2+36x-8=[(3x)^3-3.(3x)^2.2+3.3x.2^2-2^3}]\)
= (3x-2)3
\(\text{c) (x+y)^3 - (x-y)^3= (x+y-x+y)[(x+y)^2+(x+y)(x-y)+(x-y)^2]}\)
=2y(x2+2xy+y2+x2-y2+x2-2xy+y2)
= 2y(3x2+y2)
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3.7: Su dung cac hang dang thuc de phan tich cac da thuc sau thanh nhan tu:
a) -y2 + 1/9
b) x4 - 256
c) 9 (x - 3)2 - 4 (x + 1)2
d) 25x2 - 1/81 x2y2
a) \(-y^2+\dfrac{1}{9}\)
\(=-\left(y^2-\left(\dfrac{1}{3}\right)^2\right)\)
\(=-\left(y+\dfrac{1}{3}\right)\left(y-\dfrac{1}{3}\right)\)
b) \(4^4-256\)
\(=4^4-4^4\)
\(=0\)
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c) \(9\left(x-3\right)^2-4\left(x+1\right)^2\)
\(=\left(3x-9\right)^2-\left(2x+2\right)^2\)
\(=\left(3x-9+2x+2\right)\left(3x-9-2x-2\right)\)
\(=\left(5x-7\right)\left(x-11\right)\)
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\(a,=\left(\dfrac{1}{3}-y\right)\left(\dfrac{1}{3}+y\right)\\ b,=\left(x^2-16\right)\left(x^2+16\right)\\ =\left(x-4\right)\left(x+4\right)\left(x^2+16\right)\\ c,=\left[3\left(x-3\right)-2\left(x+1\right)\right]\left[3\left(x-3\right)+2\left(x+1\right)\right]\\ =\left(3x-9-2x-2\right)\left(3x-9+2x+2\right)\\ =\left(x-11\right)\left(5x-7\right)\\ d,=\left(5x-\dfrac{1}{9}xy\right)\left(5x+\dfrac{1}{9}xy\right)=x^2\left(5-\dfrac{1}{9}y\right)\left(5+\dfrac{1}{9}y\right)\)
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Phan tich thanh nhan tu bang ki thuat no sung hang dang thuc.
3x^2+8xy-3y^2
x^2 - x - xy - 2y^2+2y
x^2+2y^2-3xy + x -2y
x^2+x-xy-2y^2+y
Phan tich thanh nhan tu bang ki thuat no sung hang dang thuc.
3x^2+8xy-3y^2
x^2 - x - xy - 2y^2+2y
x^2+2y^2-3xy + x -2y
x^2+x-xy-2y^2+y
Phan tich thanh nhan tu ( bang ki thuat no sung hang dang thuc)
6x^2-xy-y^2
2x^2+5xy+y^2
6x^2+2xy-4y^2
2x^2+2xy-4y^2
Phan tich thanh nhan tu ( bang ki thuat no sung hang dang thuc)
6x^2-xy-y^2
2x^2+5xy+y^2
6x^2+2xy-4y^2
2x^2+2xy-4y^2
a/ \(=2xy+6x^2-y^2-3xy=2x\left(y+3x\right)-y\left(y+3x\right)=\left(2x-y\right)\left(y+3x\right)\)
b/ \(=2x^2+5xy+y^2\)
c/ \(=-4y^2+6xy-4xy+6x^2=-2y\left(2y-3x\right)-2x\left(2y-3x\right)=\left(-2y-2x\right)\left(2y-3x\right)=-2\left(y+x\right)\left(2y-3x\right)\)
d/ \(=-4y^2-2xy+4xy+2x^2=-2y\left(2y+x\right)+2x\left(2y+x\right)=\left(-2y+2x\right)\left(2y+x\right)=-2\left(y-x\right)\left(2y+x\right)\)
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Phan tich thanh nhan tu ( bang ki thuat bo sung hang dang thuc)
x^2+xy-2y^2
x^2-3xy-2y^2
x^2-xy-6y^2
2x^2 - 3xy -2y^2
a/ \(=2xy+x^2-2y^2-xy=x\left(2y+x\right)-y\left(2y+x\right)=\left(x-y\right)\left(2y+x\right)\)
b/ \(=x^2-3xy-2y^2\)
c/ \(=2xy-6y^2+x^2-3xy=2y\left(x-3y\right)+x\left(x-3y\right)=\left(2y+x\right)\left(x-3y\right)\)
d/ \(=xy-2y^2+2x^2-4xy=y\left(x-2y\right)+2x\left(x-2y\right)=\left(y+2x\right)\left(x-2y\right)\)
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a)(x-y)(x+2y)
b) nghiệm lẻ>mìh nghĩ là sai đề
c)(x-3y)(x+2y)
d)(x-2y)(2x+y)
____________________________
li-ke cho mk nha bnLe Ngoc Bao Chau
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Phan tich thanh nhan tu ( bang ki thuat bo sung hang dang thuc)
x^2+xy-2y^2
x^2-3xy-2y^2
x^2-xy-6y^2
2x^2 - 3xy -2y^2
x^2 + xy - 2y^2 = ( x^2 - 2xy + y^2 ) + 3xy - 3y^2 = ( x - y )^2 + 3y.( x - y ) = ( x - y )(x + 2y)
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