147 - ( 2x - 53 ) = 32
2x+3x=57:5
7.(42- x) = 53+134
X+18÷32=5×42
Trong các hàm số dưới đây, hàm số bậc nhất là:
A . y = 3 - 2 x + x 2 B . y = 4 x + 3 - 2 5 C . y = 3 2 . x + 5 D . y = 2 x + 5 3
Bài 1: tính hợp lý
a/ [3.(-2)-(-8)] . (-7) -(-2).(-5)
b/32.(132-247)-132.(32-247)
c/12+(-47).12-6.(-12)
d/ 135.(-12+147)-147.(135-12)
e/(-45).(-16).(-125).(-1)1000
Bài 2: Tìm x
a/ 3.(x+2)-6(x-5)=2(5-2x)
b/(-2x).(-4x)+28=100
Làm nhanh mình cho 2 tck
d) 135(-12 + 247) - 147(135 - 12)= -12.135 + 135.147 - 147.135 + 12.147 = (-12.135 + 12.147) + (135.147 - 147.135) = 12(-135 + 147) + 0 = -12.12 = -144
Bài 1:
a) [3.(-2) - (-8)].(-7) - (-2).(-5) = -7(-6 + 8) - 2.5= -7.2 - 2.5 = -2(7 + 5) = -2.12 = -24
c) 12 + (-47).12 - 6.(-12) = 12 - 47.12 + 6.12 = 12(1 - 47 + 6) = 12.(-40) = -480
Thực hiện phép tính :
a) (629 +437 )-437 -19
b )47.86 -47.76 + 2.13.5 -30 +4 .19 .25
c) 2928 + (-53) -(-149) + (-247) -2598
d) (-25) .(35+147) +35.(25+147)
a)(629 +437 )-437 -19
=1066-437-19
=629-19
=610
b)47.86 -47.76 + 2.13.5 -30 +4 .19 .25
=47.(86-76)+(2.5).13-30+(4.25).19
=47.10+10.13-30+100.19
=470+130-30+1900
=600-30+1900
=570+1900
=2470
c) 2928 + (-53) -(-149) + (-247) -2598
=2875+149-247-2598
=3024-247-2598
=2777-2598
=179
không tính kết quả ,hảy so sánh
32 . 53 - 31 và 53 . 31 + 32 .
32 . 53 - 31 = 53.(31 + 1) - 31 = 53.31 < 53.31 + 32
1: thực hiện phép tính
a)53-76-[-76-(-53)]
b)-87-12-(-48)+(-512)0
c)2+22+23+.....+2100
2 tìm xϵz,biết
a) (x-1)2=1
b)(x+1)3=-1
c)105-(135-7x):9=97
d)(x+7).(3-x)>0
e)3x-3-32=2.32
g)(2x2+1).(4-2x)=0
giúp nhoa
Bài 2:
a: =>x-1=1 hoặc x-1=-1
=>x=2 hoặc x=0
b: =>x+1=-1
hay x=-2
c: =>(135-7x):9=8
=>135-7x=72
=>7x=63
hay x=9
d: =>(x+7)(x-3)<0
=>-7<x<3
e: \(\Leftrightarrow3^{x-3}=18+9=27\)
=>x-3=3
hay x=6
f: =>4-2x=0
hay x=2
Tìm số nguyên x biết:
1, -x +(-53) =(-42) - 41
2. -12 - x= -32 +19
3.453+x = -443+(-199)
4. -12-x = -32 +19
5. 32.(-2) +x = -120 -5.(-85)
6. -2x + 15.(-4) = 21.(-8) -12
98+65+32+147=......
98 + 65 + 32 + 147
= (98 + 32) + 65 + 147
= 130 + 65 + 147
= 195 + 147
= 342
98 + 65 + 32 + 147
=( 98 + 32) + 65 + 147
= 130 + 65 + 147
= 195 + 147
= 342.
bài 7
4x3 + 12 = 120
b, ( x - 4 )2 = 64
c, ( x + 1 )3 - 2 = 52
d, 136 - ( x + 5)2 = 100
e, 4x = 16
f, 7x. 3 - 147 = 0
g, 2x+3 - 15 = 17
h, 52x-4. 4 = 102
i, (32 - 4x)(7 - x) = 0
k, ( 8 - x)(10 - 2x) = 0
m, 3x + 3x+1 = 108
n, 5x+2 + 5x+1 = 750
a: \(4x^3+12=120\)
=>\(4x^3=108\)
=>\(x^3=27=3^3\)
=>x=3
b: \(\left(x-4\right)^2=64\)
=>\(\left[{}\begin{matrix}x-4=8\\x-4=-8\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=12\\x=-4\end{matrix}\right.\)
c: (x+1)^3-2=5^2
=>\(\left(x+1\right)^3=25+2=27\)
=>x+1=3
=>x=2
d: 136-(x+5)^2=100
=>(x+5)^2=36
=>\(\left[{}\begin{matrix}x+5=6\\x+5=-6\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=1\\x=-11\end{matrix}\right.\)
e: \(4^x=16\)
=>\(4^x=4^2\)
=>x=2
f: \(7^x\cdot3-147=0\)
=>\(3\cdot7^x=147\)
=>\(7^x=49\)
=>x=2
g: \(2^{x+3}-15=17\)
=>\(2^{x+3}=32\)
=>x+3=5
=>x=2
h: \(5^{2x-4}\cdot4=10^2\)
=>\(5^{2x-4}=\dfrac{100}{4}=25\)
=>2x-4=2
=>2x=6
=>x=3
i: (32-4x)(7-x)=0
=>(4x-32)(x-7)=0
=>4(x-8)*(x-7)=0
=>(x-8)(x-7)=0
=>\(\left[{}\begin{matrix}x-8=0\\x-7=0\end{matrix}\right.\)
=>\(\left[{}\begin{matrix}x=8\\x=7\end{matrix}\right.\)
k: (8-x)(10-2x)=0
=>(x-8)(x-5)=0
=>\(\left[{}\begin{matrix}x-8=0\\x-5=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=8\\x=5\end{matrix}\right.\)
m: \(3^x+3^{x+1}=108\)
=>\(3^x+3^x\cdot3=108\)
=>\(4\cdot3^x=108\)
=>\(3^x=27\)
=>x=3
n: \(5^{x+2}+5^{x+1}=750\)
=>\(5^x\cdot25+5^x\cdot5=750\)
=>\(5^x\cdot30=750\)
=>\(5^x=25\)
=>x=2