\(\frac{10}{3}\)    . x    \(+\)\(\frac{67}{4}\)     \(=\)-13,25

\(\frac{10}{3}\)  .  x     \(+\)\(\frac{67}{4}\)     \(=\)\(\frac{-53}{4}\)

\(\frac{10}{3}\)  . x                               \(=\)\(\frac{-53}{4}\)\(-\)\(\frac{67}{4}\)

\(\frac{10}{3}\) .  x                               \(=\)\(-\)30

               x                                \(=\)\(-\)30 \(\div\)\(\frac{10}{3}\)

               x                               \(=\)\(-\)9

\(3\frac{1}{3}x+16\frac{3}{4}=-13,25\)

<=> \(\frac{10}{3}x+\frac{67}{4}=-\frac{53}{4}\)\(\frac{10}{3}x=-\frac{53}{4}-\frac{67}{4}\)=> \(\frac{10}{3}x=-\frac{120}{4}=-30\)

<=> X=(-3)*3  => X=-9

Đáp số: x=-9

\(3\frac{1}{3}x+16\frac{3}{4}=-13,25\\ \frac{10}{3}x+\frac{67}{4}=\frac{-53}{4}\\ \frac{10}{3}x=\frac{-53}{4}-\frac{67}{4}\\ \frac{10}{3}x=-30\\ x=\left(-30\right):\frac{10}{3}\\ x=\left(-30\right)\cdot\frac{3}{10}\\ x=-9\)Vậy x = -9

\(3\frac{1}{3}.x+16\frac{3}{4}=-13,25\)     

 \(\frac{10}{3}x+16,75=-13,25\)

                   \(\frac{10}{3}x=-13,25-16,75\)

                    \(\frac{10}{3}x=-30\)

                            \(x=-9\)

Vậy \(x=-9\)

X =9 nha bn tk mk mk tk lai cho

a) Ta có: \(\frac{2}{3}x-\frac{1}{2}=\frac{1}{10}\)

\(\Leftrightarrow x\cdot\frac{2}{3}=\frac{1}{10}+\frac{1}{2}=\frac{6}{10}\)

hay \(x=\frac{6}{10}:\frac{2}{3}=\frac{6}{10}\cdot\frac{3}{2}=\frac{18}{20}=\frac{9}{10}\)

Vậy: \(x=\frac{9}{10}\)

b) Ta có: \(5\frac{4}{7}:x=13\)

\(\Leftrightarrow\frac{39}{7}:x=13\)

\(\Leftrightarrow x=\frac{39}{7}:13=\frac{39}{7}\cdot\frac{1}{13}=\frac{3}{7}\)

Vậy: \(x=\frac{3}{7}\)

c) Ta có: \(\left(2\frac{4}{5}x-50\right):\frac{2}{3}=51\)

\(\Leftrightarrow\frac{14}{5}x-50=51\cdot\frac{2}{3}=34\)

\(\Leftrightarrow x\cdot\frac{14}{5}=84\)

\(\Leftrightarrow x=84:\frac{14}{5}=84\cdot\frac{5}{14}=\frac{420}{14}=30\)

Vậy: x=30

d) Ta có: \(\frac{2}{3}+\frac{1}{3}:x=\frac{3}{5}\)

\(\Leftrightarrow\frac{1}{3}:x=\frac{3}{5}-\frac{2}{3}=\frac{-1}{15}\)

hay \(x=\frac{1}{3}:\frac{-1}{15}=\frac{1}{3}\cdot\left(-15\right)=\frac{-15}{3}=-5\)

Vậy: x=-5

e) Ta có: \(8\frac{2}{3}:x-10=-8\)

\(\Leftrightarrow\frac{26}{3}:x=2\)

hay \(x=\frac{26}{3}:2=\frac{26}{3}\cdot\frac{1}{2}=\frac{26}{6}=\frac{13}{3}\)

Vậy: \(x=\frac{13}{3}\)

g) Ta có: \(x+30\%=-1.3\)

\(\Leftrightarrow x+\frac{3}{10}=\frac{-13}{10}\)

hay \(x=\frac{-13}{10}-\frac{3}{10}=\frac{-16}{10}=\frac{-8}{5}\)

Vậy: \(x=\frac{-8}{5}\)

i) Ta có: \(3\frac{1}{3}x+16\frac{3}{4}=-13.25\)

\(\Leftrightarrow x\cdot\frac{10}{3}+\frac{67}{4}=-\frac{53}{4}\)

\(\Leftrightarrow x\cdot\frac{10}{3}=\frac{-53}{4}-\frac{67}{4}=-30\)

\(\Leftrightarrow x=-30:\frac{10}{3}=-30\cdot\frac{3}{10}=\frac{-90}{10}=-9\)

Vậy: x=-9

k) Ta có: \(\left(2\frac{4}{5}x-50\right):\frac{2}{3}=51\)

\(\Leftrightarrow x\cdot\frac{14}{5}-50=51\cdot\frac{2}{3}=34\)

\(\Leftrightarrow x\cdot\frac{14}{5}=34+50=84\)

hay \(x=84:\frac{14}{5}=84\cdot\frac{5}{14}=30\)

Vậy: x=30

m) Ta có: \(\left|2x-1\right|=\left(-4\right)^2\)

\(\Leftrightarrow\left|2x-1\right|=16\)

\(\Leftrightarrow\left[{}\begin{matrix}2x-1=16\\2x-1=-16\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=17\\2x=-15\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\frac{17}{2}\\x=\frac{-15}{2}\end{matrix}\right.\)

Vậy: \(x\in\left\{\frac{17}{2};\frac{-15}{2}\right\}\)

a. -3/16

b. -79/20

tìm x 

x=-9

1) a) \(\left(-0,75+\frac{1}{2}\right):\frac{4}{3}\)

\(=\left(-0,75+\frac{1}{2}\right)\cdot\frac{3}{4}\)

\(=\left(-0,75+0,5\right)\cdot0,75\)

\(=-0,25\cdot0,75\)

\(=-0,1875\)

Vậy: \(\left(-0,75+\frac{1}{2}\right):\frac{4}{3}=-0,1875\)

b) \(\frac{7}{5}\cdot\frac{7}{4}-\frac{32}{5}\)

\(=\frac{49}{20}-\frac{32}{5}\)

\(=\frac{49}{20}-\frac{128}{20}\)

\(=-\frac{79}{20}=-3\frac{19}{20}\)

Vậy: \(\frac{7}{5}\cdot\frac{7}{4}-\frac{32}{5}=-3\frac{19}{20}\)

2) \(\frac{10}{3}\cdot x+\frac{67}{4}=-13,25\)

<=> \(\frac{10}{3}\cdot x+\frac{67}{4}=-\frac{53}{4}\)

<=> \(\frac{10}{3}\cdot x=-\left(\frac{53}{4}+\frac{67}{4}\right)\)

<=> \(\frac{10}{3}\cdot x=-30\)

<=> \(x=-30:\frac{10}{3}\)

<=> \(x=-30\cdot\frac{3}{10}\)

<=> \(x=-9\)

Vậy: \(x=-9\)

\(3\frac{1}{3}x+16\frac{3}{4}=-13,25\)

\(\Leftrightarrow\frac{3\times3+1}{3}x+\frac{16\times4+3}{4}=-13,25\)

\(\Leftrightarrow\frac{9+1}{3}x+\frac{64+3}{4}=-13,25\)

\(\Leftrightarrow\frac{10}{3}x+\frac{67}{4}=-13,25\)

\(\Leftrightarrow\frac{10}{3}x+16,75=-13,25\)

\(\Leftrightarrow\frac{10}{3}x=-13,25-16,75\)

\(\Leftrightarrow\frac{10}{3}x=-30\)

\(\Leftrightarrow x=-30\div\frac{10}{3}\)

\(\Leftrightarrow x=\frac{-30}{1}\times\frac{3}{10}\)

\(\Leftrightarrow x=\frac{-90}{10}\)

\(\Leftrightarrow x=-9\)