\(=\dfrac{2^{11}\cdot3^6}{3^5\cdot2^8}=2^3\cdot3=24\)

`(27^5 . 16^3)/(18^5 . 8^2)`

\(\frac{2^{11}\cdot9^2}{3^5\cdot16^2}\)

\(=\frac{2^{11}\cdot3^4}{3^5\cdot2^8}\)

\(=\frac{2^3}{3}\)

\(=\frac{8}{3}\)

\(\frac{2^{11}\cdot9^2}{3^5\cdot16^2}=\frac{2^{11}\cdot\left(3^2\right)^2}{3^5\cdot\left(2^4\right)^2}=\frac{2^{11}\cdot3^4}{3^5\cdot2^8}=\frac{2^3}{3}=\frac{8}{3}\)

\(\dfrac{2^{11}.9^2}{3^5.16^2}\)

= \(\dfrac{2^{11}.3^4}{3^5.2^8}\)

= \(\dfrac{2^3}{3}\)= \(\dfrac{8}{3}\)= 2, (6)

khya r mà đăng à bn

\(\left(-2\right)^x=\left(2^2\right)^2.\left(2^4\right)^2\)

\(\left(-2\right)^x=2^4.2^8=2^{12}\)

\(=>x=12\)

\(\left(-2\right)^x=\left(2^2\right)^5.\left(2^4\right)^2\)

\(\left(-2\right)^x=2^{10}.2^8\)

\(\left(-2\right)^x=2^{18}\)

\(=>x=18\)

(-2)^x = 4⁵.16²

(-2)^x = 2¹⁰ . 2⁸

(-2)^x = 2¹⁸ = (-2)¹⁸

=> x = 18

2772

58.42+32.8+5.16

=58.42+16.16+5.16

=58.42+16.(16+5)

=58.42+16.21

=58.42+8.42

=42.(58+8)

=42.66

=2772

\(58.42+32.8+5.16 \)

\(= 58.42+32.8+5.2.8\)

\(= 58.42+32.8+10.8\)

\(= 58.42+(32+10).8\)

\(= 58.42+42.8\)

\(= 42(58+8) \)

\(= 42.66\)

\(= 2772\)