phan tich da thuc thanh nhan tu (x^2+xy)^2-(y^2+xy)^2
Ai giup minh voi a
phan tich da thuc thanh nhan tu (xy+1)^2 -(x-y)^2 ai giup minh voi
\(\left(xy+1\right)^2-\left(x-y\right)^2=\left(xy+1+x-y\right)\left(xy+1-x+y\right)\)
\(=x^2y^2+xy-x^2y+xy^2+xy+1-x+y+x^2y+x-x^2+xy-xy^2-y+xy-y^2\)
\(=x^2y^2+2xy-x^2-y^2+1\)
phan tich da thuc sau thanh nhan tu ab(x^2+y^2)-xy(a^2+b^2)
\(ab\left(x^2+y^2\right)-xy\left(a^2+b^2\right)\)
\(=abx^2+aby^2-a^2xy-b^2xy\)
\(=ax\left(bx-ay\right)+by\left(ay-bx\right)\)
\(=ax\left(bx-ay\right)-by\left(bx-ay\right)\)
\(\left(bx-ay\right)\left(ax-by\right)\)
hãy k nếu bạn thấy đây là câu tl đúng :)
Phan tich da thuc thanh nhan tu
(xy-1)^2 -x^2-y^2
phan tich da thuc thanh nhan tu:
x^2-xy-2y^2
x2-xy-2y2
= x2-2xy+xy-2y2
=x(x-2y)+y(x-2y)
=(x-2y)(x+y)
phan tich da thuc thanh nhan tu a, (3x+1)^2-(x+1)^2
b, 6x-6y-x^2+xy
\(a,\left(3x+1\right)^2-\left(x+1\right)^2\)
\(=\left(3x+1-x-1\right)\left(3x+1+x+1\right)\)
\(=2x\left(4x+2\right)\)
\(=4x\left(2x+1\right)\)
\(b,6x-6y-x^2+xy\)
\(=\left(6x-6y\right)-\left(x^2-xy\right)\)
\(=6\left(x-y\right)-x\left(x-y\right)\)
\(=\left(x-y\right)\left(6-x\right)\)
phan tich da thuc sau thanh nhan tu
2x^2-xy-y^2
Ta có
\(2x^2-xy-y^2=x^2-xy+x^2-y^2\) \(=x\left(x-y\right)+\left(x+y\right)\left(x-y\right)\)
\(=\left(x+x+y\right)\left(x-y\right)\)
\(=\left(2x+y\right)\left(x-y\right)\)
phan tich da thuc thanh nhan tu
5x+ 7$\sqrt xy $ -6y+$\sqrt x $ - 2$\sqrt y $
phan tich da thuc thanh nhan tu
a) xy-y2+2x-2y
b) x2+2xy+y2-9
a, = (xy-y^2) + (2x-2y) = y(x-y) + 2.(x-y) = (x-y).(y+2)
b, = (x+y)^2 - 9 = (x+y-3).(x+y+3)
\(xy-y^2-2x-2y\)
=(xy-y).(2x-2y)
=y(x-y).2(x-y)
=(x-y).(y-2)
phan tich da thuc thanh nhan tu :xy(x-y)-xz(x+z)+yz(2x+z-y)