16y^2-4x^2-12x-9
phan tich da thuc thanh nhan tu chung
8x^3-12x^2+6x-1
phan tich da thuc thanh nhan tu chung
cái này dễ mà
= (2x)^3-3(2x)^2*1+2*3x*1^2-1^3
= (2x-1)^3
4x^2-4x+1
phan tich da thuc thanh nhan tu chung
\(4x^2-4x+1\)\(=\) \((2x^2)-2.2x.1+1^2\)
\(=\left(2x-1\right)^2\)
Học tốt!
phan tich da thuc sau thanh nhan tu
x3-4x2+12x-27
\(x^3-4x^2+12x-27\)
\(=x^3-3x^2-x^2+3x+9x-27\)
\(=x^2\left(x-3\right)-x\left(x-3\right)+9\left(x-3\right)\)
\(=\left(x-3\right)\left(x^2-x+9\right)\)
phan tich da thuc thanh nhan tu
3x^3 +12x^2 +12x
tu de bai suy ra: 3x(x^3+4x+4)=3x(x+2)^2
phan tich da thuc sau thanh nhan tu (bang cach dat nhan tu chung)
(4x-y)(a+b)(4x-y)(c-1)
\((4x-y)(a+b)(4x-y)(c-1)\)
\(=\left(4x-y\right)\left(4x-y\right)=\left(4x-y\right)^{1+1}=\left(4y-2\right)^2\)
\(=\left(a+b\right)\left(4x-y\right)^2\left(c-1\right)\)
(4x-y)(a+b)(4x-y)(c-1)
= ( 4x - y ) ( 4x - y ) = ( 4x - y ) 1 + 1 = ( 4y - 2 ) 2
= (a + b ) ( 4x - y )2 ( c - 1 )
Bài giải :
(4x-y)(a+b)(4x-y)(c-1)
= ( 4x - y ) ( 4x - y ) = ( 4x - y ) 1 + 1
= ( 4y - 2 ) 2
= (a + b ) ( 4x - y )2 ( c - 1 )
4x^2-36x+56 phan tich da thuc thanh nhan tu
4x2 - 36x + 56
= 4x2 - 28x - 8x + 56
= ( 4x2 - 28x ) - ( 8x - 56 )
= 4x( x - 7 ) - 8( x - 7 )
= ( x - 7 )( 4x - 8 )
= 4( x - 7 )( x - 2 )
(x^2+x)^2+4x^2+4x-12 phan tich da thuc thanh nhan tu
phan tich da thuc thanh nhan tu: 4x^4-32x^2+1
4x^4 - 32x^2 +1 = 4x^4 + 4x^2 +1 - 36x^2 = (2x^2 + 1)^2 - 36x^2 = (2x^2 - 6x + 1)(2x^2 + 6x + 1)
4 x4 - 32 x2 + 1
= ( 2 x2 )2 - 2 . 2x2. 8 + 64 - 63
= ( 2 x2 - 8 )2 - 63
= ( 2x2 - 8 + √63 ) ( 2x2 - 8 - √63 )
Xong
phan tich da thuc thanh nhan tu 4x^2-y^2+8(y-2)
=4x2-y2+8y-16
=4x2-(y2 - 8y+16)
=4x2-(y-4)2
=(2x+y-4)(2x-y+4)
4x2-y2+8(y-2)
=4x2-y2+8.y-8.2
=4x2-y2+8y-16