tim cac so nguyen duong x;y;z thoa man \(3x^2-18y^2+2z^2+3y^2z^2-18x=27\)
tim cac cap so nguyen duong nguyen to cung nhau sao cho: (x+y)/(x^2+y^2)=7/25
tim cac so nguyen duong x,y thoa man 2x+3y=14
Vì 14 ⋮ 2 => 2x + 3y ⋮ 2
Mà 2x ⋮ 2 => 3y ⋮ 2
Mà ( 2; 3) = 1 => y ⋮ 2
2x + 3y = 14 => 3y ≤ 14
=> y ≤ 14 / 3 => y ≤ 4 => y = 2 ; 4
Với y = 2 <=> 2x + 6 = 14 => 2x = 8 => x = 4
Với y = 4 <=> 2x + 12 = 14 => 2x = 2 => x = 1
Vậy ( x;y ) = { ( 4;2 ) ; ( 1 ; 4 ) }
tim cac so xy nguyen duong biet /x-2y+1/*/x+4y+3/=20
Tim cac so nguyen duong x;y biet: |x-2y+1|.|x+4y+3|=20
de ma suy ra 1 trong 2 ve la uoc cua 20
chi la uoc duong thoi vi cogia tri tuyet doi ma
tim cac so nguyen duong x;y biet |x-2y +1|.|x+4y+3| =20
Tim cac so nguyen duong x,y biet |x-2y+1|.|x+4y+3| = 20
tim cac so nguyen duong x,y biet |x-2y+1| |x+4y+3|=20
a, Tim cac so nguyen duong x,y nho hon 10 sao cho 3x - 4y = -21
b, tim cac so nguen x,y sao cho xy -2x + 5y -12 = 0
Tim cac so nguyen duong x;y;z thoa man x!+y!=10.z+9
cho x, y la cac so nguyen duong sao cho A = x^4 + y^4 / 15 cung la so nguyen duong . cmr : x va y deu chia het cho 3 va 5 , tu do tim gtnn cua A