\(4x^4-16-4x^2-16x\)

\(=4x^2\left(x^2-1\right)-16\left(1+x\right)\)

\(=4x^2\left(x+1\right)\left(x-1\right)-16\left(x+1\right)\)

\(=\left(x+1\right)\left[4x^2\left(x-1\right)-16\right]\)

\(=\left(x+1\right)4\left[x^2\left(x-1\right)-4\right]\)

Nguyễn Văn Tuấn AnhNs r, không biết thì not làm

\(4x^4-16-4x^2-16x\)

\(=4x^2\left(x^2-1\right)-16\left(x+1\right)\)

\(=4x^2\left(x-1\right)\left(x+1\right)-16\left(x+1\right)\)

\(=\left(x+1\right)\left[4x^2\left(x-1\right)-16\right]\)

\(=4\left(x+1\right)\left[x^2\left(x-1\right)-4\right]\)

\(=4\left(x+1\right)\left[x^3-x^2-4\right]\)

\(=4\left(x+1\right)\left[x^3+x^2+2x-2x^2-2x-4\right]\)

\(=4\left(x+1\right)\left[x\left(x^2+x+2\right)-2\left(x^2+x+2\right)\right]\)

\(=4\left(x+1\right)\left(x-2\right)\left(x^2+x+2\right)\)

๖ۣۜMαɾαƙαĭ ⁹⁀ᶦᵈᵒᶫ  bạn đừng ns thế người ta không biết làm nhưng vẫn cố gắng giúp 

nếu bạn ấy làm sai thì vẫn có những người như bạn sửa

\(x^4-4x^3+8x^2-16x+16 \)

\(=x^3\left(x-2\right)-2x^2\left(x-2\right)+4x\left(x-2\right)-8\left(x-2\right)\)

\(=\left(x-2\right)\left(x^3-2x^2+4x-8\right)\)

\(=\left(x-2\right)\left[x^2\left(x-2\right)+4\left(x-2\right)\right]\)

\(=\left(x-2\right)^2\left(x^2+4\right)\)

a,x⁴-4x³+8x²-16x+16

=x⁴-4x³+4x²+4x²-16x+16

=x².(x-2)²+4.(x-2)²

=(x-2)²(x²+4)

x^4 - 4x^3 - 8x^2 - 16x + 16 
= x^4-8x^2+16-4x^3-16x 
= ( x^2+4)^2 - 4x(x^2+4 ) 
= ( x^2 + 4 )(x^2 + 4 - 4x) 
= (x^2 + 4 )( x - 2 )^2

\(x^4-4x^3+8x^2-16x+16\)

=\(x^4-4x^3+4x^2-16x+16\)

=\(x^2\left(x-2\right)^2+4\left(x-2\right)^2\)

=\(\left(x-2\right)^2\left(x^2+4\right)\)

x⁴ - 4x³ +  8x²  - 16x + 16 = x⁴ - 4x³ +  4x²+4x²  - 16x + 16= ( x⁴ - 4x³ +  4x²)+(4x²  - 16x + 16)

=x²(x²-4x+4) + 4( x²-4x+4) = (x²+4)(x²-4x+4)=(x²+4)(x-2)²

https://h7.net/hoi-dap/toan-8/phan-h-da-thuc-x-4-16-thanh-nhan-tu-faq324398.html

\(x^4+16x-12\)

\(=x^4+2x^3-2x^2-2x^3-4x^2+4x+6x^2+12x-12\)

\(=x^2.\left(x^2+2x-2\right)-2x.\left(x^2+2x-2\right)+6.\left(x^2+2x-2\right)\)

\(=\left(x^2+2x-2\right)\left(x^2-2x+6\right)\)

Làm

x⁴  + 16x - 12 

= x⁴  + 2x³ - 2x² - 2x³ - 4x² + 4x + 6x ² + 12x - 12

= x² ( x² + 2x - 2 ) - 2x ( x²  + 2x - 2 ) + 6( x²  + 2x - 2 )

=( x²  + 2x - 2 )( x² - 2x + 6 )

_{HỌC TỐT @}

a,x⁴-4x³+8x²-16x+16

=(x⁴-4x³+4x²⁾+(4x²-16x+16)

=(x^2-2x)^2+(2x-4)^2

=x^2(x-2)^2+4(x-2)^2

=(x-2)^2(x^2+4)

a) \(4x^4+4x^3-x^2-x=4x^3\left(x+1\right)-x\left(x+1\right)\)

\(=\left(4x^3-x\right)\left(x+1\right)=x\left(4x^2-1\right)\left(x+1\right)\)

\(=x\left\{\left(2x\right)^2-1\right\}\left(x+1\right)=x\left(2x-1\right)\left(2x+1\right) \left(x+1\right)\)

c) \(x^4-4x^3+8x^2-16x+16=x^4+8x^2+16-\left(4x^3+16x\right)\)

\(=\left(x^2+4\right)^2-4x\left(x^2+4\right)=\left(x^2-4x+4\right)\left(x^2+4\right)=\left(x-2\right)^2\left(x^2+4\right)\)

b) \(x^6-x^4-9x^3+9x^2=x^4\left(x^2-1\right)-\left(9x^3-9x^2\right)\)

\(=x^4\left(x-1\right)\left(x+1\right)-9x^2\left(x-1\right)\)

\(=\left(x^5+x^4-9x^2\right)\left(x-1\right)=\left(x-1\right)x^2\left(x^3+x^2-9\right)\)