1 acceptance

2 clockwise 

3 obligatory

4 society

5 commemoration 

6 invaders

7 joyful

8 cruelty

9 legendary

10 generously 

1:

Program baitap1;

Uses crt;

Var A:array[1..200] of integer;

      S,i:integer;

Begin

Clrscr;

S:=0;

For i:=1 to 10 do

     Begin

     Write('A[',i,']=');

     Readln(A[i]);

     If (A[i] mod 2=1) then S:=S+A[i];

     End;

Writeln('Tong cac phan tu co gia tri le:',S);

Readln

2:

Program baitap2;

Uses crt;

Var A:array[1..200] of integer;

      S,i:integer;

Begin

Clrscr;

S:=0;

For i:=1 to 15 do

     Begin

     Write('A[',i,']=');

     Readln(A[i]);

     If (A[i] mod 2=0) then S:=S+A[i];

     End;

Writeln('Tong cac phan tu co gia tri chan:',S);

Readln

End.

End.

Đề bài ??

Câu 5: 

a) \(\left|3-2x\right|=\dfrac{1}{2}\)

Khi \(x\ge0\), ta có

\(3-2x=\dfrac{1}{2}\)

\(2x=\dfrac{5}{2}\)

\(x=\dfrac{5}{4}\)

Khi \(x< 0\), ta có

\(-\left(3-2x\right)=\dfrac{1}{2}\)

\(-3+2x=\dfrac{1}{2}\)

\(2x=\dfrac{7}{2}\)

\(x=\dfrac{7}{4}\)

b) \(\dfrac{x-1}{4}=\dfrac{10}{8}\)

\(\dfrac{x-1}{4}=\dfrac{5}{4}\)

\(x-1=5\)

\(x=6\)

Câu 6: 

Áp dụng tính chất của dãy tỉ số bằng nhau, ta được:

\(\dfrac{a}{b}=\dfrac{c}{d}=\dfrac{a+c}{b+d}=\dfrac{a-c}{b-d}\)

hay \(\dfrac{a+c}{b+d}=\dfrac{a-c}{b-d}\)

Bài 6 đề sai nhé.

\(\widehat{ABz}\) hay \(\widehat{ABx}=42^o\)

1. is going to buy
2. is she going to ask
3. are you going to use
5. am not tidying up

1. Is going to buy
2. Is she going to ask
3. Are you going to use
5. Am not tidying up