\(\dfrac{-22}{45}=-\dfrac{2266}{45.103}>-\dfrac{2295}{45.103}=-\dfrac{51}{103}\)

Ta có: \(\dfrac{-22}{45}=\dfrac{-22\cdot103}{45\cdot103}=\dfrac{-2266}{4635}\)

\(\dfrac{-51}{103}=\dfrac{-51\cdot45}{103\cdot45}=\dfrac{-2295}{4635}\)

mà -2266>-2295

nên \(\dfrac{-22}{45}>\dfrac{-51}{103}\)

Đồng tiên bạn quy đồng, rồi so sánh nhé

\(\frac{22}{45}< \frac{22}{44}=\frac{1}{2}=\frac{51}{102}< \frac{51}{101}.\)

22/45 < 51/101

\(\frac{-22}{45}>-\frac{51}{103}\)

K nha

kb nha

-22/45 >-51/103

\(-\frac{22}{45}>-\frac{51}{103}\)

−2245>−51103

a) Ta có \(\dfrac{23}{27}>\dfrac{23}{29};\dfrac{23}{29}>\dfrac{22}{29}\)

Vậy \(\dfrac{23}{27}>\dfrac{22}{29}\)

b) Ta có \(\dfrac{15}{25}=1-\dfrac{2}{5}\)

\(\dfrac{25}{49}=1-\dfrac{24}{49}\)

Vì \(\dfrac{2}{5}=\dfrac{24}{60}< \dfrac{24}{49}\)

Vậy \(\dfrac{15}{25}>\dfrac{25}{49}\)

23/27 lớn hơn 22/29

15/25 lớn hơn 25/49

mik tick hết cho những ai trả lời đc nhé!

\(\dfrac{6}{10}>\dfrac{45}{100};\dfrac{3}{10}< \dfrac{84}{100}\)

>,<

Ta có -22/45 = -0.4(8)

            -51/103= -0.3923...

Mà -0.4(8) < -03923....

Vậy -22/45 < -51/103

-22/45>-51/103

dấu > nha bn

~~ tk mk đi ~

Ai tk mk mk tk lại ~~

Kb vs mk nha m.n, ai kb mk tk 3 cái lun ~~

n_n

A<B

a<b

Ta có: Phân số trung gian của -\(\frac{-22}{45}\)và \(\frac{-51}{103}\)là\(\frac{-22}{103}\)

=>\(\frac{-22}{103}\)<\(\frac{-22}{45}\);\(\frac{-22}{103}\)>\(\frac{-51}{103}\)

=>\(\frac{-22}{45}\)>\(\frac{-51}{103}\)

\(\frac{-22}{45}\)<\(\frac{-22}{103}\)

k mik nha bạn