1+1=a
a+b=2
2+b=3
tim a,b
a, Cho F(x) = a x+b . Tim a,b biet f(0) = 3 va F(2) =-1
b, Cho F(x) =a x+ b. Tim a,b biet F(1) = -1 va F(-2) = 8
c, Cho F(x) =a x +b .tim a,b biet F(0) = 1 va F(-2) = -9
1, tim GTLN cua A=13/(x+5)^2+7
2, tim GTNN cua B=|x+2017|+(y+3)^2+2017
3, cho a-1/2=b+3/4=c-5/6 va 5a-3b-4c=46. Tim a,b,c.
1) Tim a, b thuoc Q biet: a-b=2(a+b)=a:b
2) Tim x thuoc Q sao cho: (x-1)(x+3)<0
Cho A = \{0; 1; 2; 4\} ; B = \{0; 2; 3; 5; 7\} . 1/ Tim A cap B A cup B: A backslash B B backslash A . 2/ Chứng tỏ: ( A backslash B) subset A; A backslash(A backslash B)=A cap B .
tim phan so a/b
1/3 -1/2 +a/b = 1/2
\(\frac{1}{3}-\frac{1}{2}+\frac{a}{b}=\frac{1}{2}\)
\(-\frac{1}{6}+\frac{a}{b}=\frac{1}{2}\)
\(\frac{a}{b}=\frac{1}{2}+\left(-\frac{1}{6}\right)\)
\(\frac{a}{b}=\frac{1}{3}\)
Vậy ...
1/a+2 + 3/b+4 <= c+1/c+3 . Tim Qmin =(a+1)(b+1)(c+1) . Tim dau bang xay ra nhu the nao ???
cho a,b > 0 va a + b = 1 . Tim GTNN của
\(\dfrac{1}{a^3}+ab+b^3+4a^2b^2+\dfrac{1}{ab}\)
cho 3 so duong a,b,c tm 1/a+1/b+1/c=3/2 tim min a/bc+b/ac+c/ab
Ta có : \(P=\dfrac{a^2+b^2+c^2}{abc}\ge\dfrac{ab+bc+ca}{abc}=\dfrac{1}{c}+\dfrac{1}{a}+\dfrac{1}{b}=\dfrac{3}{2}\)
=> Min P = 3/2 "=" khi a = b = c = 2
a, Cho ( a,b) = 1 . Chung minh rang (a.b, a+b)=1
b, Cho (a,b)= 1. Tim UCLN (11a+2b , 18a +5b)
C,, Cho A = m+n ; B=m^2+n^2.Trong do m va n la cac so tu nhien nguyen to cung nhau. Tim UCLN (A,B)
d, Tim cac so tu nhien n sao cho n^3 - n^2 + n-1la so nguyen to