\(A=\frac{4116-14}{10290-35}=\frac{14.294-14}{35.294-35}=\frac{14.\left(294-1\right)}{35\left(294-1\right)}=\frac{14}{35}=\frac{2}{5}\)

\(B=\frac{2929-101}{2.1919+404}=\frac{101\left(29-1\right)}{101\left(38+4\right)}=\frac{28}{42}=\frac{2}{3}\)

a) \(\dfrac{4116-14}{10290-35}=\dfrac{4102}{10255}=\dfrac{2051.2}{2051.5}=\dfrac{2}{5}\)

b) \(\dfrac{2929-101}{2.1919+404}=\dfrac{2929-101}{3838+404}=\dfrac{2828}{4242}=\dfrac{1414.2}{1414.3}=\dfrac{2}{3}\)

Rút gọn :

A= \(\dfrac{4116-14}{10290-35}\)= \(\dfrac{4102}{10255}=\dfrac{4102:2051}{10255:2051}=\dfrac{2}{5}\)

B=\(\dfrac{2929-101}{2.1919+404}=\dfrac{2828}{3838+404}=\dfrac{2828}{4242}=\dfrac{2828:1414}{4242:1414}=\dfrac{2}{3}\)

A=4116-14/10290-35
=[14 x ( 294 -1 )]/[35 x (294-1)]
= 14/35

B =2929-101/2.1919+404
= [101 x (291-1)] / [101 x 38 + 101 x 4)]
= [ 101x (29 -1)] / [ 101 x (38+4)
= (29-1) / (38+4)
= 28/42 = 2/3

A=4116-14/10290-35=14.294-14.1/35.294-35.1=14.(291-1)/35.(294-1)=14/35=14:7/35:7=2/5

B=2929-101/2.1919+404=101.29-101.1/2.19.101+4.101=101.(29-1)/101.(2.19+4)=28/42=28:14/42:14=2/3

de et ngu nhu bo y ko lam dc 

\(A=\frac{2}{5};B=\frac{2}{3}\)

\(A=\frac{4116-14}{10290-35}=\frac{294.14-14}{35.294-35}=\frac{293.14}{293.35}=\frac{14}{35}=\frac{2}{5}\)

\(B=\frac{2929-101}{2.1919+404}=\frac{29.101-101}{38.101+4.101}=\frac{101.28}{101.42}=\frac{28}{42}=\frac{2}{3}\) 

làm theo từng bước na các bn

làm từng bước na các bn