b: \(3x+3y-x^2-2xy-y^2\)

\(=3\left(x+y\right)-\left(x+y\right)^2\)

\(=\left(x+y\right)\left(3-x-y\right)\)

b) 3x+3y-x²-2xy-y²

=3(x+y)-(x+y)²

=(x+y)(3-x-y)

\(x^2-2xy+y^2+3x-3y-10=\left(x^2-2xy+y^2\right)+3\left(x-y\right)-10=\left(x-y\right)^2+3\left(x-y\right)-10=\left(x-y\right)^2-2\left(x-y\right)+5\left(x-y\right)-10=\left(x-y\right)\left(x-y-2\right)+5\left(x-y-2\right)=\left(x-y+5\right)\left(x-y-2\right)\)

= ( x - y)^2  - 3 ( x - y) . -10

= ( x  - y)^2 - 2.(x-y) . 3/2 +9/4 - 49/4 

= ( x - y - 3/2) ^2 - (7/2)^2 

= ( x- y - 3/2 - 7/2 )( x - y -3/2 + 7/2 )

=( x - y - 5 )( x - y + 2)

1: =3(y^2+x^2+2xy-z^2)

=3(x+y-z)(x+y+z)

2: =2(8x^3+27y^3)

=2(2x+3y)(4x^2-6xy+9y^2)

3: =(x-y)^2-25

=(x-y-5)(x-y+5)

\(x^2-2xy+y^2+3x-3y-10\)

\(=\left(y^2-xy-5y\right)-\left(xy-x^2-5x\right)+\left(2y-2x-10\right)\)

\(=y\left(y-x-5\right)-x\left(y-x-5\right)+2\left(y-x-5\right)\)

\(=\left(y-x+2\right)\left(y-x-5\right)\)

Ai trả lời mình đi cho đỡ quê 😞💔

a: \(=\left(x+2-y\right)\left(x+2+y\right)\)

c: \(=\left(x-y\right)^2\)

x²-2xy+y²-3x-3y-10=(x-y)²

=(x-y)^2-3(x-y)-10

=(x-y)(x-y-3-10)

=(x-y)(x-y-13)