X+\(\frac{1}{x}\)=3 giải vs
giải jùm vs
Rút gọn Pthức:
A= \(\left(\frac{1}{x+1}-\frac{3}{x^3+1}+\frac{3}{x^2+x+1}\right)\frac{3x^2-3x+3}{\left(x+1\right)\left(x+2\right)}-\frac{2x-2}{x^2+2x}\)
Giải phương trình: \(\frac{5}{x-1}-\frac{2}{x+1}=\frac{5}{x-3}-\frac{2}{x-4}\)
Giúp mk vs !! tks nhìu T_T
rút gọn :
A = \(\left(\frac{2x+1}{\sqrt{x}^3-1}-\frac{\sqrt{x}}{x-\sqrt{x}+1}\right).\left(\frac{3\sqrt{x}+\sqrt{x}^3}{x-3x}-\sqrt{x}\right)\)mk cần gấp ai giải nhanh hộ vs thanks
\(A=\left(\frac{2x+1}{\left(\sqrt{x}-1\right).\left(x+\sqrt{x}+1\right)}-\frac{\sqrt{x}}{\left(x+\sqrt{x}+1\right)}\right).\left(\frac{\sqrt{x}.\left(3+x\right)}{-2x}-\sqrt{x}\right) \)
\(A=\left(\frac{2x+1-\sqrt{x}.\left(\sqrt{x}-1\right)}{\left(\sqrt{x}-1\right).\left(x+\sqrt{x}+1\right)}\right).\left(\frac{3+x}{-2\sqrt{x}}-\sqrt{x}\right)\)
\(A=\left(\frac{2x+1-x+\sqrt{x}}{\left(\sqrt{x}-1\right).\left(x+\sqrt{x}+1\right)}\right).\left(\frac{3+x+2x}{-2\sqrt{x}}\right)\)
\(A=\left(\frac{x+\sqrt{x}+1}{\left(\sqrt{x}-1\right).\left(x+\sqrt{x}+1\right)}\right).\left(\frac{3x+3}{-2\sqrt{x}}\right)\)
\(A=\frac{1}{\sqrt{x}-1}.\frac{3.\left(x+1\right)}{-2\sqrt{x}}\)
\(A=\frac{3x+3}{-2\sqrt{x}.\left(\sqrt{x}+1\right)}\)
P/s: hình như đề sai hay sao á, thường thì người ta không cho mẫu là 2 số trừ được như ( x - 3x ) đâu
Tìm x:
\(\frac{x+3}{x^2-1}-\frac{1}{x^2+x}\)
giải nhanh hộ mình vs!!
Giải giúp mik vs ạ
\(3\left(x-\frac{1}{2}\right)-3\left(x-\frac{1}{3}\right)=x\)
=> \(3x-\frac{3}{2}-3x+1=x\)
=> \(x=-\frac{1}{2}\)
2) \(\frac{1}{3}x+5-x=\frac{1}{2}-2x\)
=> \(\frac{1}{3}x-x+2x=-5+\frac{1}{2}\)
=> \(\frac{4}{3}x=-\frac{9}{2}\)
=> x = \(-\frac{27}{8}\)
bạn nào bt thì giải giúp mình bài này vs : rút gọn P= \(\frac{3x^2+9x-3}{x^2+x-2}-\frac{x+1}{x+2}+\frac{x-2}{1-x}\)
\(=\frac{3x^2+9x-3}{x^2+x-2}-\frac{x+1}{x+2}-\frac{x-2}{x-1}\)
\(=\frac{3x^2+9x-3}{\left(x+2\right)\left(x-1\right)}-\frac{\left(x+1\right)\left(x-1\right)}{\left(x+2\right)\left(x-1\right)}-\frac{\left(x-2\right)\left(x+2\right)}{\left(x-1\right)\left(x+2\right)}\)
\(=\frac{3x^2+9x-3-\left(x^2-1\right)-\left(x^2-4\right)}{\left(x-1\right)\left(x+2\right)}\)
\(=\frac{3x^2+9x-3-x^2+1-x^2+4}{\left(x-1\right)\left(x+2\right)}\)
\(=\frac{x^2+9x+2}{\left(x-1\right)\left(x+2\right)}\)
Tìm x:
\(\frac{3x}{x^2-x+3}-\frac{2x}{x^2-3x+3}\)=-1
Giải giùm mik vs mik tik cho
Quy đồng hết lên đi thì được:
\(x^4-3x^3+2x^2-9x+9=0\)
\(\Leftrightarrow\left(x-1\right)\left(x-3\right)\left(x^2+x+3\right)=0\)
Giải hộ vs
tìm x
\(2\left(x+\frac{1}{2}\right)-\frac{x}{3}=1\frac{1}{2}:\left(-0,25\right)\)
\(2\left(x+\frac{1}{2}\right)-\frac{x}{3}=1\frac{1}{2}:\left(-0,25\right)\)
\(=>2x+1-\frac{x}{3}=\frac{3}{2}:\left(-0,25\right)\)
\(=>\frac{5x}{3}+1=-6\)
\(=>\frac{5x}{3}=-7\)
\(=>5x=-21\)
\(=>x=-\frac{21}{5}\)
Ủng hộ nha
\(\Rightarrow2x+1-\frac{x}{3}=-6\Rightarrow2x+1-\frac{x}{3}+6=0\Rightarrow\frac{3.\left(2x+1\right)-x+6.3}{3}=0\)
\(\Rightarrow\frac{6x+3-x+18}{3}=0\Rightarrow5x+21=0\Rightarrow x=\frac{-21}{5}\)
Chúc e học tốt Chọn cho anh nha cảm ơn nhìu
Giải hộ mk vs :((\(\left\{{}\begin{matrix}\frac{3}{\sqrt{x+1}}-\frac{2}{\sqrt{y-2}}=1\\\frac{5}{\sqrt{x+1}}+\frac{3}{\sqrt{y-2}}=8\end{matrix}\right.\)