a) 2,25 : \(\frac{-6}{25}=\frac{9}{4}\cdot\frac{-25}{6}=\frac{9\cdot\left(-25\right)}{4\cdot6}=\frac{3\cdot3\cdot\left(-25\right)}{4\cdot3\cdot2}=\frac{-75}{8}\)

b) \(\frac{2^3\cdot5^2\cdot7^2\cdot3^7}{49\cdot5^3\cdot3^6\cdot11}=\frac{2^3\cdot5^2\cdot7^2\cdot3^6\cdot3}{7^2\cdot5^2\cdot5\cdot3^6\cdot11}=\frac{2^3\cdot3}{5\cdot11}=\frac{24}{55}\)

a)Ta có:

\(A=4\frac{25}{16}+25\left(\frac{9}{16}:\frac{125}{64}\right):\frac{-27}{8}\)

\(\Rightarrow A=\frac{89}{16}+25.\frac{36}{125}:\frac{-27}{8}\)

\(\Rightarrow A=\frac{89}{16}+\frac{36}{5}:\frac{-27}{8}\)

\(\Rightarrow A=\frac{89}{16}+\frac{-32}{15}\)

\(\Rightarrow A=\frac{823}{240}\)

Vậy A=.....

b)Ta có:

\(C=\frac{2^3}{3.5}+\frac{2^3}{5.7}+\frac{2^3}{7.9}+...+\frac{2^3}{101.103}\)

\(\Rightarrow C=\frac{2^2.2}{3.5}+\frac{2^2.2}{5.7}+\frac{2^2.2}{7.9}+...+\frac{2^2.2}{101.103}\)

\(\Rightarrow C=2^2\left(\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+...+\frac{2}{101.103}\right)\)

\(\Rightarrow C=4\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+....+\frac{1}{101}-\frac{1}{103}\right)\)

\(\Rightarrow C=4\left(\frac{1}{3}-\frac{1}{103}\right)\)

\(\Rightarrow C=4.\frac{100}{309}\)

\(\Rightarrow C=\frac{400}{309}\)

Vậy C=.....

B, C=2^3/3.5 + 2^3/5.7+......+2^3/101.103

C= 2^3(1/3-1/5+1/5-1/7+....+1/101-1/103)

C=8(1/3-1/103)

C=8.100/309

C=800/309

VẬY C= 800/309

a) \(...=2^{14}:\left(2^6.2^5\right)=2^{14}:2^{11}=2^3=8\)

b) \(...=5^{25}.5^2:5^{24}=5^{27}:5^{24}=5^3=125\)

c) \(...=2^{22}:2^2-2^{20}=2^{20}-2^{20}=0\)

d) \(...=3^6:3^3=3^3=27\)

a) 8

b) 125

c) 0

d) 27

\(\frac{25^4.16^3.3^7}{75^4.6^3.8^2}=\frac{5^8.4^6.3^7}{3^4.25^4.2^3.3^3.2^6}=\frac{3^7.2^{12}.5^8}{3^7.5^8.2^9}=2^3=8\)

3².5²⁰.(3³)⁹-3.(3²)¹⁵.(5²)⁹

7.3²⁹.(5³)

\(a.27.75+25.27-150\)

\(=27.\left(75+25\right)-150\)

\(=27.100-150\)

\(=2700-150\)

\(=2550\)

a, 27.75+25.27-150                b,3.5²-16:2³                                     d, 60 : {[( 12-3 ).2] +2}

= 27.(75+25)-150                    = 3.25-16:4                                = 60 : {[ 9.2] + 2

= 27.   100   - 150                    = 75 - 4                                     = 60 :   18 + 2

= 2700     -   150                      =    71                                        = 60  :   20

=       2550                                                                                 =     3

Tk mik nha

\(\frac{2}{3.5}+\frac{3}{5.8}+\frac{11}{8.19}+\frac{13}{19.32}+\frac{25}{32.57}+\frac{30}{57.87}\)

\(=\frac{5-3}{3.5}+\frac{8-5}{3}+\frac{19-8}{8.19}+\frac{32-29}{19.32}+\frac{57-32}{32.57}+\frac{87-57}{57.87}\)

\(=\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{19}+\frac{1}{19}-\frac{1}{32}+\frac{1}{32}-\frac{1}{57}+\frac{1}{57}-\frac{1}{87}\)

\(=\frac{1}{3}-\frac{1}{87}=\frac{28}{87}\)

\(\frac{4^2.5.11}{44.20}=\frac{2^4.5.11}{2^2.11.2^2.5}=\frac{2^4.5.11}{2^4.5.11}=1\)

\(\frac{13.15.6}{18.65.7}=\frac{13.3.5.2.3}{2.3^2.13.5.7}=\frac{3^2.2.5.13}{2.3^2.13.5.7}=\frac{1}{7}\)

\(\frac{4^2.5.11}{44.20};\frac{13.15.6}{18.65.7};\frac{7.2.8.5^2}{14.2.5}\)và\(\frac{2^3.3^2.5}{3.2^3.5^3}\)

Ta có : \(\frac{4^2.5.11}{44.20}=\frac{42.5.11}{4.11.4.5}=\frac{4^2.1.1}{4^2.1.1}=1\)

\(\frac{13.15.6}{18.65.7}=\frac{13.3.5.6}{3.6.15.5.7}=\frac{1.1.1.1}{1.1.1.1.7}=\frac{1}{7}\)

\(\frac{7.2.8.5}{14.2.5}=\frac{7.2.2^3.5^2}{2.7.2.5}=\frac{1.1.2^2.5}{1.1.1.1}=\frac{20}{1}\)

\(\frac{2^3.3^3.5}{3.2^3.5^3}=\frac{1.3^2.1}{1.1.5^2}=\frac{9}{25}\)

+) Ta có : \(7=7\)

\(25=5^2\)

\(MC=BCNN\left(7;25\right)=5^2.7=175\)

Khi đó : ................

p/s : kham khảo

24/55 nha

\(\frac{2^35^27^23^7}{49.5^3.3^6.11}\)

= \(\frac{2^31^21^21^7}{7.1^3.1^6.11}\)

= \(\frac{8}{77}\)