CHUNG MINH RANG
(a+b+c)^2 >hoac=3(ab+bc+ca)
giup minh moi minh dang can gap
Cho tam giac ABC can tai B ke BH vuong goc AC ( H thuoc AC )
a) Chung minh: HA = HC
b) Ke HD vuong goc AB ( D thuoc AB ), HE vuong goc BC ( E thuoc BC ). Chung minh: HD = HE
c) Chung minh: tam giac BDE can
d) Chung minh: \(BE^2+DH^2=BC^2-HA^2\)
MINH DANG CAN GAP NHO CAC BAN GIUP CHO ( phan a, b, c cac ban co the lam hoac ko thi tuy nhung nho cac ban giup minh phan d )
CAM ON CAC BAN NHIEU
Cho a+b=c+d va a^2+b^2=c^2+d^2.Chung minh rang:a^2022+b^2022=c^2022+d^2022
Moi nguoi giup minh voi,minh dang can gap1)chung to rang so nguyen to p;p>5 khi chia cho 6 chi co the du 1 hoac 5
2)chung minh rang neu p va p+2 la so nguyen to lon hon 3 thi p+1 la mot hop so
cac an giai giup minh minh dang can gap
ai giai nhanh minh tick cho
chung minh rang A=\(7+7^2+7^3+...+7^{2016}⋮20^2\)
giup minh nhe minh dang can gap
\(A=7+7^2+7^3+........+7^{2016}\)
\(A=7\left(1+7+7^2+7^3+........+7^{2012}+7^{2013}+7^{2014}+7^{2015}\right)\)
\(A=7\left[\left(1+7+7^2+7^3\right)+........+\left(7^{2012}+7^{2013}+7^{2014}+7^{2015}\right)\right]\)
\(A=7\left[\left(1+7+7^2+7^3\right)+........+7^{2012}\left(1+7+7^2+7^3\right)\right]\)
\(A=7\left[400+........+7^{2012}.400\right]\)
\(A=7.400\left(1+7^4+7^8+7^{12}+......+7^{2012}\right)⋮400\)
Vì \(20^2=400\) nên \(A⋮20^2\left(dpcm\right)\)
Q= 1/2! + 2/3! + 3/4! + ... + n-1/n!
Chung minh rang : Q<1
Minh dang can gap. Giup minh voi!!
chung minh rang : -3x^2+6x-y^2+6y-12 nho hon hoac bang 0
(cac ban giai nhanh nhe 5 like , minh dang can gap)
-3x2 + 6x -y2 +6y -12
<=> (-3x2 +6x -3) +( -y2 + 6y - 9)
<=> -3(x2 -2x +1) - (y2 -6y +9)
<=> -3(x-1)2 - (y-3)2
mà -3(x-1)2>=0
-(y-3)2>=0
=> dpcm
= -3(x^2-2x+1)-(y^2-6y+9)
=-3(x-2)^2-(y-3)^2 nhỏ hơn hoặc bằng 0
chung to rang :a/b <1 thi a/b <a+n/b+n
giup minh voi , minh dang can gap cam on nhieu
chứng minh BĐT:
a,\(\frac{ab}{a+b}+\frac{bc}{b+c}+\frac{ca}{c+a}0\right)\)
cac ban giup minh. minh dang can rat rat gap
cho a/3 = 3/b = b/a. chung minh rang a=b
LAM GIUP MIK VS AI LM NHANH NHAT MIK TICK CHO.MIK DANG CAN GAP NOI TRONG NGAY MAI
Có: \(\frac{a}{3}=\frac{3}{b}=\frac{b}{a}\)
\(\Leftrightarrow\hept{\begin{cases}ab=9\\a^2=3b\end{cases}}\)
\(\Leftrightarrow\hept{\begin{cases}a=\frac{9}{b}\\\frac{81}{b^2}=3b\end{cases}}\)
\(\Leftrightarrow\hept{\begin{cases}a=\frac{9}{b}\\27=b^3\end{cases}}\)
\(\Leftrightarrow a=b=3\)