x + (-15) - (-12) =0
x -3 =0
x = 3

\(x-3=0\Leftrightarrow x=3\)

x +(-15)-(-12)=0

x +(-3)            =0

x                      =0 -(-3)

x                      = 3

x

Số số hạng là x-10+1=x-9(số)

Tổng là (x+10)(x-9)=9810

=>x^2+x-90=9810

=>x=99

ĐK:\(x\ge0\)

\(\left(x^2-1\right)\sqrt{x}=0\Leftrightarrow\left(x-1\right)\left(x+1\right)\sqrt{x}=0\\ \Leftrightarrow\left[{}\begin{matrix}x-1=0\\x+1=0\\\sqrt{x}=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1\left(tm\right)\\x=-1\left(ktm\right)\\x=0\left(tm\right)\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1\\x=0\end{matrix}\right.\)

Ủa lớp 7 sao học căn r nè

a)\(y=\dfrac{5}{3}-\left(\dfrac{7}{12}:\dfrac{5}{6}\right)=\dfrac{5}{3}-\dfrac{7}{10}=\dfrac{50}{30}-\dfrac{21}{30}=\dfrac{29}{30}\)

b)\(y=\dfrac{4}{15}:\left[\left(\dfrac{4}{5}+\dfrac{1}{2}\right)\times\dfrac{4}{13}\right]=\dfrac{4}{15}:\left[\left(\dfrac{8}{10}+\dfrac{5}{10}\right)\times\dfrac{4}{13}\right]\)

\(y=\dfrac{4}{15}:\left[\dfrac{13}{10}\times\dfrac{4}{13}\right]=\dfrac{4}{15}:\dfrac{2}{5}=\dfrac{2}{3}\)

a 29/30

b 20/30= 2/3

Giải:

a) \(\dfrac{-5}{8}=\dfrac{x}{16}\) 

\(\Rightarrow x=\dfrac{16.-5}{8}=-10\) 

\(\dfrac{3x}{9}=\dfrac{2}{6}\) 

\(\Rightarrow3x=\dfrac{2.9}{6}=3\) 

\(\Rightarrow x=1\)

b) \(\dfrac{x+3}{15}=\dfrac{1}{3}\)  

\(\Rightarrow x+3=\dfrac{1.15}{3}=5\) 

\(\Rightarrow x=2\)

\(\dfrac{6}{2x+1}=\dfrac{2}{7}\) 

\(\Rightarrow2x+1=\dfrac{6.7}{2}=21\) 

\(\Rightarrow x=10\)

c) \(\dfrac{4}{x-6}=\dfrac{y}{24}=\dfrac{-12}{18}\) 

\(\Rightarrow\dfrac{4}{x-6}=\dfrac{-12}{18}\) 

\(\Rightarrow x-6=\dfrac{18.4}{-12}=-6\) 

\(\Rightarrow x=0\) 

\(\Rightarrow\dfrac{y}{24}=\dfrac{-12}{18}\) 

\(\Rightarrow y=\dfrac{-12.24}{18}=-16\) 

 \(\dfrac{3-x}{-12}=\dfrac{16}{y+1}=\dfrac{192}{-72}\) 

\(\Rightarrow\dfrac{3-x}{-12}=\dfrac{192}{-72}\) 

\(\Rightarrow3-x=\dfrac{192.-12}{-72}=32\) 

\(\Rightarrow x=-29\) 

\(\Rightarrow\dfrac{16}{y+1}=\dfrac{192}{-72}\) 

\(\Rightarrow y+1=\dfrac{16.-72}{192}=-6\) 

d) \(\dfrac{-2}{3}< \dfrac{x}{5}< \dfrac{-1}{6}\) 

\(\Rightarrow\dfrac{-20}{30}< \dfrac{6x}{30}< \dfrac{-5}{30}\) 

\(\Rightarrow6x\in\left\{-18;-12;-6\right\}\) 

\(\Rightarrow x\in\left\{-3;-2;-1\right\}\) 

\(\dfrac{-1}{5}\le\dfrac{x}{8}\le\dfrac{1}{4}\) 

\(\Rightarrow\dfrac{-8}{40}\le\dfrac{5x}{40}\le\dfrac{10}{40}\) 

\(\Rightarrow5x\in\left\{-5;0;5;10\right\}\) 

\(\Rightarrow x\in\left\{-1;0;1;2\right\}\) 

e) \(\dfrac{x+46}{20}=x\dfrac{2}{5}\) 

\(\Rightarrow\dfrac{x+46}{20}=x+\dfrac{2}{5}\) 

\(\Rightarrow\dfrac{x+46}{20}=\dfrac{5x+2}{5}\) 

\(\Rightarrow5.\left(x+46\right)=20.\left(5x+2\right)\) 

\(\Rightarrow5x+230=100x+40\) 

\(\Rightarrow5x-100x=40-230\) 

\(\Rightarrow-95x=-190\) 

\(\Rightarrow x=-190:-95\) 

\(\Rightarrow x=2\) 

\(y\dfrac{5}{y}=\dfrac{86}{y}\) 

\(\Rightarrow y+\dfrac{5}{y}=\dfrac{86}{y}\) 

\(\Rightarrow\dfrac{y^2+5}{y}=\dfrac{86}{y}\) 

\(\Rightarrow y^2+5=86\) 

\(\Rightarrow y^2=86-5\) 

\(\Rightarrow y^2=81\) 

\(\Rightarrow\left[{}\begin{matrix}y=9\\y=-9\end{matrix}\right.\) 

Chúc bạn học tốt!

a, 15 - ( 4 - x ) = 6

⇒ 15 - 4 + x = 6

⇒ 11+ x = 6

⇒ x = -5

 c, x - ( 12 - 25 ) = -8

⇒ x + 13 = -8

⇒ x = -21

d, ( x - 29 ) - ( 17 - 38 ) = -9

⇒ x - 29 + 21 = -9

⇒ x - 8 = -9

⇒ x = -1

b, - 30 + ( 25 - x ) = -1

⇒ - 30 + 25 - x = -1

⇒ -5 - x = -1

⇒ x = -4

a, \(15-4+x=6\) ⇒ \(11-x=6\) ⇒ \(x=5\)

b, \(-30+25-x=-1\) ⇒ \(-5-x=-1\) ⇒ \(x=-4\)

c, \(x-12+25=-8\Rightarrow x+13=-8\) ⇒ \(x=-21\)

d, \(x-29-17+38=-9\Rightarrow x-8=-9\Rightarrow x=-1\)

a,12,5-x=4,27

x=12,5-4,27

x=8,23

vay x=8,23

b,18,2:x=5,6

x=18,2:5,6

x=3,25

vay x=3,25

18, 2 : X = 5, 6
x = 18,2 : 5,6 
x = 3,25

a) -12. (x-5) + 7. ( 3-x ) = 5

=> -12x + 60 + 21 - 7x = 5

=> -19x = -76

=> x= 4 

b) 30. (x+2) -6. (x-5 ) -24x =100

=> 30x + 60 - 6x + 30 -24x = 100

=>  0x = 10 (vô lí )

=> ko có giá trị của x

-12.(x-5)+7.(3-x)=5

(-12).x-(-12).5+7.3-7.x=5

(-12).x-(-60)+21-7.x=5

(-12).x+60+21-7.x=5

(-12).x+(60+21)-7.x=5

(-12).x+81-7.x=5

(-12).x-7.x=5-81

-19.x=-76

x=76:(-19)

x=4

a, -12(x - 5) + 7(3 - x) = 5

<=> -12x + 60 + 21 - 7x = 5

<=> -19x + 81 = 5 

<=> -19x = -76

=> x = 4

b, 30(x + 2) - 6(x - 5) - 24x = 100

<=> 30x + 60 - 6x + 30 - 24x = 100

<=> 0x + 90 = 100

<=> 0x = 10

=> x = O

\(12-x\left(x-7\right)=31-3\left(x+12\right)\)

\(\Leftrightarrow12-x^2+7x=31-3x-36\)

\(\Leftrightarrow12-x^2+7x=-5-3x\)

\(\Leftrightarrow17-x^2+10x=0\)

phương trình bậc 2 lớp 8 mới học :

( 3x - 6 ) . 3 = 18

3x - 6 = 18 : 3 = 6

3x = 6 + 6 = 12

x= 4

6x - 5 = 613

6x = 613 + 5 =618

x=103

x-36:18=12

x - 2 = 12

x= 12 + 2

x= 14

\(\left(3x-6\right).3=18\)

\(\Rightarrow3x-6=19:3=6\)

\(\Rightarrow3x=6+6=12\)

\(\Rightarrow x=12:3=4\)

\(6.x-5=613\)

\(\Rightarrow6x=613+ 5=618\)

\(\Rightarrow x=618:6=103\)

\(x-36:18=12\)

\(\Rightarrow x-2=12\)

\(\Rightarrow x=12+2=14\)

Ủng hộ nha m.n ^_^

\(\left(3x-6\right)\cdot3=18\)

\(\Rightarrow3x-6=18:3=6\)

\(\Rightarrow3x=6+6=12\)

\(\Rightarrow x=12:3=4\)

\(6\cdot x-5=613\)

\(\Rightarrow6\cdot x=613+5=618\)

\(\Rightarrow x=61=618:6=103\)

\(x-36:18=12\)

\(=x-2=12\)

\(\Rightarrow x=12+2=14\)

Ủng hộ mk nka!!!^_^^_^^_^