X x 2011 - X = 2011 x 2009 + 2011
X x 2011-X =2011 x 2009-2011
x . 2011 - x = 2011 . 2009 - 2011
x.(2011 - 1) = 4038088
x . 2010 = 4038088
x = 4038088: 2010
x = 2008,999005
X x 2011-X = 2011 x 2009 - 2011
X x ( 2011-1) = 2011 x (2009- 1)
X x 2010 = 2011 x 2010
=> X=2011
Tim giá trị biểu thức : A = 1/4+1/12+1/24+1/40+1/60+1/84
x *2011 -x= 2011 * 2009 +2011
x *2011 -x= 2011 * 2009 +2011
=> x*(2011-1)=2011*(2009+1)
=> x*2010=2011*2010
=> x=2011
x x 2011 - x = 2011 x 2009 + 2011
x x ( 2011 - 1 ) = 2011 x ( 2009 + 1 )
x x 2010 = 2011 x 2010
x x 2010 = 4042110 : 2010
x = 2011
(2009 x 2010 + 2011 x 12 + 1998)/(2011 x 2010 - 2010 x 2009)
Tìm số tự nhiên x biết:
X×2011-x=2011×2009+2011
X x 2011-X=2011x2009+2011
Xx(2011-1)=2011x(2009+1)
Xx2010 = 2011x2010
=> X=2011
x * 2011 - x = 2011 x 2009 + 2011
x * ( 2011 - 1 ) = 2011 x ( 2009 + 1 )
x * 2010 = 2011 x 2010
x = 2011
Tìm x;
x*2011-x=2011*2009+2011
x * 2011 - x = 2011 * 2009 + 2011
x*(2011-1) = 2011*(2009 +1 )
x * 2010 = 2011 * 2010
x= 2011
\(x.2011-x=2011.2009+2011\)
\(\Leftrightarrow2010x=4042100\)
\(\Leftrightarrow x=4042100:2010\)
\(\Leftrightarrow x=\dfrac{4042100}{2010}\)
Vậy ...
x . 2011 - x = 2011 . 2009 + 2011
\(\Rightarrow\) x (2011 - 1) = 2011 (2009 + 1)
\(\Rightarrow\) x . 2010 = 2011 . 2010
\(\Rightarrow\) x = 2011
\(\frac{x-2010-2011}{2009}\)+\(\frac{x-2009-2011}{2010}\)+\(\frac{x-2009-2010}{2011}\)= 3
lấy cả 2 vế trừ đi 3
\(\frac{x-2010-2011}{2009}+\frac{x-2009-2011}{2010}+\frac{x-2009-2010}{2011}=3\)
\(\Leftrightarrow\left(\frac{x-2010-2011}{2009}-1\right)+\left(\frac{x-2009-2011}{2010}-1\right)+\left(\frac{x-2009-2010}{2011}-1\right)=0\)
\(\Leftrightarrow\frac{x-6030}{2009}+\frac{x-6030}{2010}+\frac{x-6030}{2011}=0\)
\(\Leftrightarrow\left(x-6030\right)\left(\frac{1}{2009}+\frac{1}{2010}+\frac{1}{2011}\right)\)
\(\Leftrightarrow x-6030=0\)(vì \(\frac{1}{2009}+\frac{1}{2010}+\frac{1}{2011}>0\))
\(\Leftrightarrow x=6030\)
Vậy ................
Giúp mình bài tìm X này với ạ
X x 2011 - X = 2011 + 2009 + 2011
X x 2011 - X x 1 = 2011 x 2 +2009
X x ( 2011 - 1 ) = 4022 + 2009
X x 2010 = 6031
X = 60312010
X x 2011 - X = 2011 + 2009 + 2011
X x ( 2011 - 1 ) = 2011 x ( 2009 + 1 )
X x 2010 = 2011 x 2010
X = 2011
x * 2011 - x = 2011 + 2009 + 2011
x * ( 2011 - 1 ) = 2011 * ( 2009 + 1 )
x * 2010 = 2011 x 2010
x = 2011
2011 x 2010 - 1/2009 x 2011 + 2010
`(2011xx2020-1)/(2009xx2011+2010)`
`=((2009+1)xx2011-1)/(2009xx2011+2010)`
`=(2009xx2011+2011-1)/(2009xx2011+2010)`
`=(2009xx2011+2010)/(2009xx2011+2010)`
`=1`
\(\dfrac{2011.2010-1}{2009.2011+2010}\)
= \(\dfrac{2011.2009+2011-1}{2009.2011+2010}\)
= \(\dfrac{2011.2009+2010}{2009.2011+2010}\)
= 1
Tìm x biết : 2011 + 2010+2009+...+x=2011