(-3)^x+2=-27×81
NT
Những câu hỏi liên quan
viết các biểu thức sau dưới dạng lũy thừa
a) 9 x 3 mũ 2 x 1/81 x 27
b) 4x32 :(2 mũ 3 x 1/16)
c)3 mũ 4 x 3 mũ 5 : 1/27
d) 81 mũ 11 x 3 mũ 17 / 27 mũ 10 x 9 mũ 15
(3/5)mũ 5 . x = (3/7)mũ 7
(-1/3)mũ 3 . x = 1/81
(x - 1/2) mũ 3 = 1/27
(3x + 1)mũ 3 = -27
(x + 1/2) mũ 4 = 16/81
(4/5) mũ 5.x = (4/5) mũ 7
Vũ Hồng Linh bạn check lại bài đầu dùm =_="
\(\left[-\frac{1}{3}\right]^3\cdot x=\frac{1}{81}\)
\(\Leftrightarrow x=\frac{1}{81}:\left[-\frac{1}{3}\right]^3\)
\(\Leftrightarrow x=\frac{1}{81}:\left[-\frac{1}{27}\right]\)
\(\Leftrightarrow x=\frac{1}{81}\cdot(-27)=-\frac{1}{3}\)
\(\left[x-\frac{1}{2}\right]^3=\frac{1}{27}\)
\(\Leftrightarrow\left[x-\frac{1}{2}\right]^3=\left[\frac{1}{3}\right]^3\)
=> Làm nốt
Mấy bài kia cũng làm tương tự
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(- \(\dfrac{1}{3}\))3.\(x\) = \(\dfrac{1}{81}\)
\(x=\dfrac{1}{81}\) : (- \(\dfrac{1}{3}\))3
\(x\) = - (\(\dfrac{1}{3}\))4 :(\(\dfrac{1}{3}\))3
\(x=-\dfrac{1}{3}\)
Vậy \(x=-\dfrac{1}{3}\)
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(3\(x\) + 1)3 = - 27
(3\(x\) + 1)3 = (-3)3
3\(x\) + 1 = -3
3\(x\) = - 3 - 1
3\(x\) = -4
\(x=-\dfrac{4}{3}\)
Vậy \(x=-\dfrac{4}{3}\)
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Xem thêm câu trả lời
(2.x+1)^3 = 81^3 : 27^3
Tìm x:
a) (3/5)^5 * x = (3/7)^7
b) (-1/3)^3 * x = 1/81
c) (x - 1/2)^3 = 1/27
d) (x+1/2)^4 = 16/81
a)\(\left(\frac{3}{5}\right)^5\times x=\left(\frac{3}{7}\right)^7\)
\(\Leftrightarrow\frac{3^5}{5^5}\times x=\frac{3^7}{7^7}\)
\(\Leftrightarrow x=\frac{3^7}{7^7}:\frac{3^5}{5^5}\)
\(\Leftrightarrow x=\frac{3^7\times5^5}{7^7\times3^5}\)
\(\Leftrightarrow x=\frac{3^2\times5^5}{7^7}\)
b)\(\left(\frac{-1}{3}\right)^3\times x=\frac{1}{81}\)
\(\Leftrightarrow\frac{\left(-1\right)^3}{3^3}\times x=\frac{1}{3^4}\)
\(\Leftrightarrow x=\frac{1}{3^4}:\frac{-1}{3^3}\)
\(\Leftrightarrow x=\frac{1\times3^3}{3^4\times\left(-1\right)}\)
\(\Leftrightarrow x=\frac{1}{-3}\)
c)\(\Leftrightarrow\left(x-\frac{1}{2}\right)^3=\left(\frac{1}{3}\right)^3\)
\(\Leftrightarrow x-\frac{1}{2}=\frac{1}{3}\)
\(\Leftrightarrow x=\frac{1}{3}+\frac{1}{2}\)
\(\Leftrightarrow x=\frac{5}{6}\)
d)\(\Leftrightarrow\left(x+\frac{1}{2}\right)^4=\left(\frac{2}{3}\right)^4\)
\(\Leftrightarrow x+\frac{1}{2}=\frac{2}{3}\)
\(\Leftrightarrow x=\frac{2}{3}-\frac{1}{2}\)
\(\Leftrightarrow x=\frac{1}{6}\)
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3 mũ 2 x3 mũ X x 81 - 27 mũ 4 = 0
\(3^2.3^x.81-27^4=0\)
\(3^2.3^x.3^4-\left(3^3\right)^4=0\)
\(3^6.3^x-3^{12}=0\)
\(3^6.3^x-3^{12}=0\)
\(3^6.3^x=0+3^{12}\)
\(3^6.3^x=3^{12}\)
\(3^{6+x}=3^{12}\)
\(\Rightarrow6+x=12\)
\(x=12-6\)
\(\Rightarrow x=6\)
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Tìm x:
a)(1/3)^x=1/729
b)(1/3-1/2)^x-1 =1/36
c)81^2x . 27^x = -27
d)(x-2)^2 =1
Tìm x,y biết:
1) 3^X-1 = 1/243
2) 81^-2X x 27^X=9^5
3) ( x-y+3)^2 + (y-1)^2=0
Tìm dư khi chia các đa thức sau
a) x^43/x^2+1
b) x^81+x^27+x^9+x^3+x/ x-1
c) x^81+x^27+x^9+x^3+x/ x^2-1
2^6 x 27^5 - 4^2 x 81^2
16 x 3^8 + 2^6 x 9^3