\(-3^x+2=-27.81\)
<=> \(-3^x=-27.81-2=-2189\)
<=> \(3^x=2189\)
=> \(x\in\varnothing\)
\(-3^x+2=-27.81\)
<=> \(-3^x=-27.81-2=-2189\)
<=> \(3^x=2189\)
=> \(x\in\varnothing\)
viết các biểu thức sau dưới dạng lũy thừa
a) 9 x 3 mũ 2 x 1/81 x 27
b) 4x32 :(2 mũ 3 x 1/16)
c)3 mũ 4 x 3 mũ 5 : 1/27
d) 81 mũ 11 x 3 mũ 17 / 27 mũ 10 x 9 mũ 15
(3/5)mũ 5 . x = (3/7)mũ 7
(-1/3)mũ 3 . x = 1/81
(x - 1/2) mũ 3 = 1/27
(3x + 1)mũ 3 = -27
(x + 1/2) mũ 4 = 16/81
(4/5) mũ 5.x = (4/5) mũ 7
Tìm x:
a) (3/5)^5 * x = (3/7)^7
b) (-1/3)^3 * x = 1/81
c) (x - 1/2)^3 = 1/27
d) (x+1/2)^4 = 16/81
Tìm x:
a)(1/3)^x=1/729
b)(1/3-1/2)^x-1 =1/36
c)81^2x . 27^x = -27
d)(x-2)^2 =1
Tìm x,y biết:
1) 3^X-1 = 1/243
2) 81^-2X x 27^X=9^5
3) ( x-y+3)^2 + (y-1)^2=0
2^6 x 27^5 - 4^2 x 81^2
16 x 3^8 + 2^6 x 9^3
tìm x
3^x-1=1/243
81^-2x.27^x=9^5
2^x+2^x+3=144
Tìm x:
\(a\)) \(\dfrac{2}{3}+\left(x-\dfrac{1}{2}\right)^3=\dfrac{19}{27}\)
\(b\)) \(\left(\dfrac{3}{2}\right)^{2x-1}:\left(\dfrac{27}{8}\right)^3=\dfrac{81}{16}\)
\(c\)) \(\dfrac{1}{2}.2^x+4.2^x=9.2^5\)
\(d\)) \(\text{12 - (2x +1)}^2=-69\)
Tìm x
1/ (x - 1/2)^3 = 8
2/ (x - 1)^3 = 8/27
3/ (x - 2/3)^x = 1/81