\(=x\left(3x-7y\right)-\left(3x-7y\right)=\left(x-1\right)\left(3x-7y\right)\)

   3x² - 7xy - 3x + 7y
= (3x²-3x) - (7xy-7y)
= 3x(x-1) - 7y(x-1)
= (3x-7y)(x-1)

\(3x^2+48+24x-12y^2\)

\(=-3\left(-x^2-16-8x+4y^2\right)\)

\(=-3\left[\left(-2y\right)^2-\left(x^2+8x+16\right)\right]\)

\(=-3\left[\left(2y\right)^2-\left(x+4\right)^2\right]\)

\(=-3\left(2y-x-4\right)\left(2y+x+4\right)\)

b) 3x⁴-3x³+9x³-9x²-24x²+24x-48x+48

=3x³(x-1)+9x²(x-1)-24x(x-1)-48(x-1)

=(x-1)(3x³+9x²-24x-48)

=3(x-1)(x³+3x²-8x-16)

24x³ - 3

= 24x³ - 12x² + 12x² - 6x + 6x -3 

= 12x² (2x - 1) + 6x(2x -1) + 3(2x-1)

=(2x-1)(12x² + 6x + 3)

= 3(2x-1)(4x² + 2x + 1) 

\(a,=3\left(x^2-8x+16\right)=3\left(x-4\right)^2\\ b,=5\left(x^2-1\right)=5\left(x-1\right)\left(x+1\right)\\ c,=\left(x+y\right)^2-9=\left(x+y+3\right)\left(x+y-3\right)\)

a) \(=3\left(x^2-8x+16\right)=3\left(x-4\right)^2\)

b) \(=5\left(x^2-1\right)=5\left(x-1\right)\left(x+1\right)\)

c) \(=\left(x+y\right)^2-9=\left(x+y-3\right)\left(x+y+3\right)\)

\(x^2-24x-8\)

\(x^2-2.12x+144-152\)

\(\Leftrightarrow\left(x-12\right)^2-152\)

\(\Leftrightarrow\left(x-12-\sqrt{152}\right)\left(x-12+\sqrt{152}\right)\)

P/s tham khảo nha

tên của mày nói lên tất cả , ko cần bít đề đúng hay sai , tao cứ đăng thôi :)) 

2.
a) 4x(x-1)-6x+6
= 4x(x-1)-6(x-1)
= (4x-6)(x-1)
3.
a) 6x²-24x=0
    6x(x-4)=0
TH1: 6x=0         TH2: x-4=0
           x=0                     x=4
Vậy x\(\in\){0;4}

2. a. \(4x\left(x-1\right)-6x+6\)

\(=4x\left(x-1\right)-6\left(x-1\right)\)

\(=\left(4x-6\right)\left(x-1\right)\)

3. a. \(6x^2-24x=0\)

\(\Leftrightarrow6x\left(x-4\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}6x=0\\x-4=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=4\end{matrix}\right.\)

Bài 3: 

a: \(\Leftrightarrow6x\left(x-4\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=4\end{matrix}\right.\)

\(\left(x-3\right)\left(x-10\right)\left(x-5\right)\left(x-6\right)-24x^2\)

\(=\left(x^2+30-13x\right)\left(x^2+30-11x\right)-24x^2\)

\(=\left(x^2+30x-12x-x\right)\left(x^2+30x-12x+x\right)-24x^2\)

\(=\left(x^2+30-12x\right)^2-x^2-24x^2\)

\(=\left(x^2-12x+30\right)^2-\left(5x\right)^2\)

\(=\left(x^2-12x+30+5x\right)\left(x^2-12x+30-5x\right)\)

\(=\left(x^2-7x+30\right)\left(x^2-17x+30\right)\)

Dễ mà lm cho ti ck

Dễ thì tự mà làm đi ??? ( Đừng có ném gạch )

==

#Thiên_Hy

===

\(5x+6x^2=x\left(5+6x\right)\)

\(2x+4x+24x=30x\)(bạn lộn đề thì phải)