= (12/50+8%) + (59/100+9%)

= 8/25+17/25

= 25/25

= 1

8% đổi thành 2/25, 9% đổi thành 9/100 có mẫu chung là 100

\(24/100+8/100+59/100+9/100=100/100=1\)

\(\dfrac{12}{50}+8\%+\dfrac{59}{100}+9\%\)

\(=\dfrac{24}{100}+\dfrac{8}{100}+\dfrac{59}{100}+\dfrac{9}{100}\)

\(=\dfrac{24+8+59+9}{100}=\dfrac{100}{100}=1\)

\(\frac{12}{50}+8\%+\frac{59}{100}+9\%\)

= \(\frac{24}{100}+\frac{8}{100}+\frac{59}{100}+\frac{9}{100}\)

Sau đó tính

 6/25+2/25+59/100+9/100

=8/25+68/100

=1

= ( 12/50 + 8% ) + ( 59/100 + 9%)

= 8/25 + 17/25

= 25/25

= 1

=\(\frac{24}{100}+\frac{8}{100}+\frac{59}{100}+\frac{9}{100}\)

=1

\(\frac{12}{50}+8\%+\frac{59}{100}+0,09\)

\(=\frac{24}{100}+\frac{8}{100}+\frac{59}{100}+\frac{9}{100}\)

\(=\frac{24+8+59+9}{100}\)

\(=\frac{100}{100}\)

\(=1\)

_Chúc bạn học tốt_

minh cam ơn mình cũng chúc bạn học tốt

a: \(=\dfrac{3}{2}\cdot\dfrac{4}{3}\cdot...\cdot\dfrac{2001}{2000}=\dfrac{2001}{2}\)

b: \(=10.1\left(340+120-270\right)=10.1\cdot190=101\cdot19=1919\)

c: \(=24\%+8\%+59\%+9\%=1\)

a: \(=\dfrac{3}{2}\cdot\dfrac{4}{3}\cdot...\cdot\dfrac{2001}{2000}=\dfrac{2001}{2}\)

b: \(=101\left(34+13-27\right)=101\cdot20=2020\)

c: \(=24\%+8\%+59\%+9\%=1\)

Câu này dễ lắm

a, -(-12) + (+19) - (+12) + 8 - 19

= 12 + 19 - 12 + 8 - 19

= ( 12 - 12) + ( 19- 19) + 8

= 0 + 0 + 8

=  8

b, (59 - 78) - (42 - 78 + 59)

= 59 - 78 - 42 + 78 - 59

= (59 - 59) - 42 - ( 78 - 78)

= 0  - 42 - 0

 = -42

c, ( - 68 + 103) - (-50 - 68 + 103)

= -68 + 103 + 50 + 68 - 103

= (-68 + 68) + ( 103 - 103) + 50

= 0 + 0 + 50

= 50 

a) \(...=12+19-12+8-19=8\)

b) \(...=-19-23=-42\)

c) \(...=35-\left(-15\right)=35+15=50\)

= 33

= 69

= 69

= 91

= 59

= 69

= 98

= 70

= 95

= 100

21+12=33

56+13=69

59+10=69

50+41=91

19+40=59

57+12=69

90+8=98

50+20=70

72+23=95

50+50=100

21+12= 33

56+13=69

59+10=69

50+41=91

19+40=59

57+12=69

90+8=98

50+20=70

72+23=95

50+50=100

Dễ vầy  mà cũng hỏi