Rut gon A=\(\frac{x\left(x-2\right)}{x^2+8x-20}\)
HV
Những câu hỏi liên quan
Rut gon bieu thuc:
A=\(8x^{n-1}.\left(\frac{1}{2}x^{n+1}-\frac{3}{4}x\right)\)
Rut gon : A = x|x - 2| / x^2 + 8x - 20 .
Chúc bạn học tốt!
A=\(\left(\frac{x^3+1}{x^2-1}-\frac{x^2-1}{x-1}\right):\left(x+\frac{x}{x-1}\right)\)
rut gon a
ĐKXĐ : x khác -1 và 1
A = [x^3+1-(x^2-1).(x+1)/(x-1).(x+1)] : [x.(x-1)+x/x-1]
= [-x^2+x/(x-1).(x+1)] : x^2/x-1
= -x.(x-1)/(x-1).(x+1) . (x-1)/x^2
= -(x-1)/x.(x+1)
k mk nha
Đúng 0
Bình luận (0)
Rut gon
\(A=\frac{\left(x+2017\right)^2+2\left(x+2018\right)\left(x-2018\right)+\left(x-2017\right)^2}{\left(x^2+2017\right)+\left(x^2-2018\right)}\)
Cho \(P=\left(\frac{4\sqrt{x}}{27\sqrt{x}}-\frac{8x}{4-x}\right):\left(\frac{\sqrt{x}-1}{x-2\sqrt{x}}-\frac{2}{\sqrt{x}}\right)\)
A) Rut Gon
B)tim m de \(\forall x>9\)Ta co \(m\left(\sqrt{x}-3\right)P>x+1\)
Rut gon bt
\(A=\left(\frac{2+x}{2-x}-\frac{4x^2}{x^2-4}-\frac{2-x}{2+x}\right):\left(\frac{x^2-3x}{2x^2-x^3}\right)\)
\(B=\left(\frac{\left(x-2\right)}{x+2\sqrt{x}}+\frac{1}{\sqrt{x}+2}\right).\frac{\left(\sqrt{x}+1\right)}{\sqrt{x}-1}\) rut gon
=\(\frac{x-2+\sqrt{x}}{\sqrt{x}\left(\sqrt{x}+2\right)}.\frac{\sqrt{x}+1}{\sqrt{x}-1}\)
\(=\frac{\left(\sqrt{x}-1\right)\left(\sqrt{x}+2\right)}{\sqrt{x}\left(\sqrt{x}+2\right)}.\frac{\sqrt{x}+1}{\sqrt{x}-1}\)
\(=\frac{\sqrt{x}+1}{\sqrt{x}}\)
Đúng 0
Bình luận (0)
Rut gon bt
\(\left(\frac{2+x}{2-x}-\frac{4x^2}{x^2-4}-\frac{2-x}{2+x}\right):\left(\frac{x^2-3x}{2x^2-x^3}\right)\)
rut gon phan thuc:
a, \(\frac{10x}{5x^2}\)
b,\(\frac{x\left(x^2-y^2\right)}{x^2\left(x+y\right)}\)
a/\(\frac{10x}{5x^2}=\frac{2}{x}\)
b/\(\frac{x\left(x^2-y^2\right)}{x^2\left(x+y\right)}=\frac{\left(x-y\right)\left(x+y\right)}{x\left(x+y\right)}=\frac{x-y}{x}\)
Đúng 0
Bình luận (0)