S=1.2+2.3+3.4+.....+9.10
Tinh tong: S= 1/1.2 + 1/2.3+ 1/ 3.4 ..... + 1/9.10?
S=\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+.....+\frac{1}{9.10}\)
S=\(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{9}-\frac{1}{10}\)
S=\(\frac{1}{10}-1\)
S=\(\frac{9}{10}\)
Tính tổng S=5/1.2+13/2.3+25/3.4+...+181/9.10
tính A= 1.2+2.3+3.4+4.5+...+9.10
3A=1.2.3+2.3.3+3.4.3+4.5.3+.....+9.10.3
3A=1.2.(3-0)+2.3.(4-1)+3.4.(5-2)+4.5.(6-3)+.....+9.10.(11-8)
3A=1.2.3-1.2.0+2.3.4-1.2.3+.....+9.10.11-9.10.8
3A=9.10.11
A=(9.10.11):3
A=330
CHẮC CHẮN 100% LÀ ĐÚNG
1/1.2 + 1/2.3 + 1/3.4 + ....+ 1/9.10
\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\)\(\frac{1}{9.10}\)
\(=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}\)\(...+\frac{1}{9}-\frac{1}{10}\)
\(=1-\frac{1}{10}\)
\(=\frac{9}{10}\)
ủng hộ mik nha mn
=1-1/2+1/2-1/3+1/3-1/4+....+1/9-1/10
=1-1/10
=9/10
Em chao anh anh ket ban voi em nhe
=1-1/2+1/2-1/3+1/4-1/5+1/5-1/6+....+1/9-1/10
=1-1/10=9/10
KET BAN VOI EM NHE
1/1.2+5/2.3+11/3.4+...+89/9.10
10.(1/1.2+5/2.3+11/3.4+...+89/9.10)
Tính A=1.2+2.3+3.4+4.5+...+8.9+9.10
Lời giải:
$A=1.2+2.3+3.4+...+8.9+9.10$
$3A=1.2(3-0)+2.3(4-1)+3.4(5-2)+....+8.9(10-7)+9.10(11-8)$
$=(1.2.3+2.3.4+3.4.5+...+8.9.10+9.10.11)-(0.1.2+1.2.3+2.3.4+...+8.9.10)$
$=9.10.11$
$\Rightarrow A=\frac{9.10.11}{3}=330$
2/1.2+2/2.3+2/3.4+....+2/8.9+2/9.10
ta có 2/1.2+2/2.3+2/3.4+...+2/8.9+2/9.10
=2/1-2/2+2/2-2/3+2/3-2/4+...+2/8-2/9+2/9-2/10
=2/1-2/10
=9/5
Đặt A = \(\frac{2}{1.2}+\frac{2}{2.3}+\frac{2}{3.4}+...+\frac{2}{8.9}+\frac{2}{9.10}\)
\(A\times2=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{8.9}+\frac{1}{9.10}\)
\(A\times2=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{9}-\frac{1}{10}\)
\(A\times2=\frac{1}{1}-\frac{1}{10}\)
\(A=\frac{9}{10}\times\frac{1}{2}=\frac{9}{20}\)
Tính
E= 1.2 + 2.3 + 3.4 +...+ 8.9 + 9.10
E= 1.2 + 2.3 + 3.4 +...+ 8.9 + 9.10=2+6+12+20+30+42+56+72+90=330 lộn