phan tich thanh nhan tu(bang ki nang tach hang tu)
1) 3x^2 +7x-6
2)6x^213x+6
3)8x^2+5x+3
NN
Những câu hỏi liên quan
phan tich thanh nhan tu(bang ki thuat tach hang tu)
1)-8x^2+5x+3
2)-10x^2-17x+6
\(1.-8x^2+5x+3=-8x^2+8x-3x+3=-8x\left(x-1\right)-3\left(x-1\right)=-\left(8x+3\right)\left(x-1\right)\)
\(2.-10x^2-17x+6=-10x^2-20x+3x+6=-10x\left(x+2\right)+3\left(x+2\right)=\left(x+2\right)\left(3-10x\right)\)
Phan tich thanh nhan tu ( bang ki thuat bo sung hang dang thuc )
5x^2 + 14x -3
5x^2 -18x-8
6x^2+7x-3
x^2-xy-2y^2
5x2+14x-3=(5x2+15x)-(x+3)=5x(x+3)-(x+3)=(x+3)(5x-1)
5x2-18x-8=(5x2-20x)+(2x-8)=5x(x-4)+2(x-4)=(x-4)(5x+2)
6x2+7x-3=(6x2-2x)+(9x-3)=2x(3x-1)+3(3x-1)=(3x-1)(2x+3)
x2-xy-2y2=(x2-y2)-(xy+y2)=(x-y)(x+y)-y(x+y)=(x+y)(x-y-y)=(x+y)(x-2y)
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phan tich thanh nhan tu bang cach tach hang tu
a) x3-x2-x-2
b) x3-6x2-x+30
\(x^3-x^2-x-2=x^3-2x^2+x^2-2x+x-2\) \(-2\)
\(=\) \(x^2\left(x-2\right)+x\left(x-2\right)+\left(x-2\right)\)
\(=\left(x^2+x+1\right)\left(x-2\right)\)
\(x^3-6x^2-x+30=x^3+2x^2-8x^2-16x+15x+30\)
\(=x^2\left(x+2\right)-8x\left(x+2\right)+15\left(x+2\right)\)
\(=\) \(\left(x^2-8x+15\right)\left(x+2\right)\)
\(=\left(x^2-5x-3x+15\right)\left(x+2\right)\)
\(=\left(x-5\right)\left(x-3\right)\left(x+2\right)\)
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phan tich da thuc thanh nhan tu : a) 3x^2 - 22xy + 4x + 8y + 7x^2 + 1 ; b) 12x^2 + 5x - 12y^2 + 12y - 10xy - 3 ; c)x^4 + 6x^3 + 11x^2 + 6x + 1
phan tich thanh nhan tu bang pp dung hang dang thuc 1+8x^6y^3
Phan tich thanh nhan tu ( bang ki thuat bo sung hang dang thuc):
x^2-4xy-x+3y^2+3y
x^2+4xy+2x+3y^2+6y
6x^2+xy-7x-2y^2+7y-5
6a^2-ab-2b^2+a+4b
Phan tich thanh nhan tu ( bang ki thuat no sung hang dang thuc)
6x^2-xy-y^2
2x^2+5xy+y^2
6x^2+2xy-4y^2
2x^2+2xy-4y^2
Phan tich thanh nhan tu ( bang ki thuat no sung hang dang thuc)
6x^2-xy-y^2
2x^2+5xy+y^2
6x^2+2xy-4y^2
2x^2+2xy-4y^2
a/ \(=2xy+6x^2-y^2-3xy=2x\left(y+3x\right)-y\left(y+3x\right)=\left(2x-y\right)\left(y+3x\right)\)
b/ \(=2x^2+5xy+y^2\)
c/ \(=-4y^2+6xy-4xy+6x^2=-2y\left(2y-3x\right)-2x\left(2y-3x\right)=\left(-2y-2x\right)\left(2y-3x\right)=-2\left(y+x\right)\left(2y-3x\right)\)
d/ \(=-4y^2-2xy+4xy+2x^2=-2y\left(2y+x\right)+2x\left(2y+x\right)=\left(-2y+2x\right)\left(2y+x\right)=-2\left(y-x\right)\left(2y+x\right)\)
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phan tich da thuc thanh nhan tu:
3x^2-7x-10 5x^3-5x^2y-10x^2+10xy
3x2 - 7x - 10
= 3x2 + 3x - 10x - 10
= (3x2 + 3x) - (10x + 10)
= 3x(x + 1) - 10(x + 1)
= (3x - 10)(x + 1)
5x3 - 5x2y - 10x2 + 10xy
= 5x(x2 - xy - 2x + 2y)
= 5x[(x2 - xy) - (2x - 2y)]
= 5x[x(x - y) - 2(x - y)]
= 5x(x - 2)(x - y)
chúc bn hok tốt
nhớ ủng hộ tik cho mik nhé! ko lần sau mik ko giúp đâu
có j ko hiểu thì bn cứ bình luận ở dưới nhé 
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