can(5x^2+5)=can(x-1)+x^2
X+2=5X-6
X CAN 2-25=0
Lời giải:
a. $x+2=5x-6$
$\Leftrightarrow 8=4x$
$\Leftrightarrow x=2$
b. $x\sqrt{2}-25=0$
$\Leftrightarrow x=\frac{25}{\sqrt{2}}=\frac{25\sqrt{2}}{2}$
gtnn cua x^2+5x+can x-2013
giai phuong trinh:
(5x+5)/(x2-4x+6)+(6x+6)/(x2-5x+7)=17/2
giup mik nha moi nguoi,minh can gap bay gio! thank you! ^_^
giai pt:
1)can(2(x+1)(x+3))+can((x+1)(x-1))=2(x+1)
2)can(x)-can(x+1)-can(x+4)+can(x+9)=0
can[x+2+3can(2x-5)]+can[x-2-can(2x-5)]=2can2
BAI 1 TINH GIA TRI CUA BTHUC
A=3PHAN 1+CAN 3 -2PHAN 1-CAN 3
B=CAN 10-CAN 5 PHAN CAN 2-1 -3CAN 5 +5PHAN CAN 5+3 +2 PHAN CAN 2
BAI 2 GIAI PT
a)CAN 49-28X+4X MU 2 -5=0
b)1PHAN 2 CAN X-2 -4 CAN 4X -8 PHAN 9 +CAN 9X+18 -5=0
MOI NGUOI GIUP MINH VS MINH CAN LUON BAY GIO
CAM ON
BAI 1 TINH
x ^ 2 . x - 2x^3
6 x^2 y . 3 xy - 2y ^2 .x +y
4x^2 + 5x -1 . 2x^3 - 3x
- 8 x^3y + 2 y^4 . 3xy^3 - 2 x^4 + 7y ^4
CAC BAN OI GIUP MINH NHE MINH DANG CAN GAP
giải phương trình
(căn( x+5)-can (x+3))(1-can(x2+8x+15))=2
Tim tat ca cac so thuc bac x thoa man
a)(2x-1)^2+(x-1)^3=3x+6
b) x+1= can bac x+3 ( ko viet dc can bac hi hi)
c)2x^2+1=5 . can bac x^2+1-4