A=2000/2001 + 2001/2000 ; B=2000/2001+2001/2002
khong quy dong. So sanh A va B
A=2000/2001+2001/2000,B=2000/2001+2001/2002
tôi nghĩ đề thế này đúng hơn
A=2000/2001+2001/2000,B=2000+2001/2001+2002
hoặc ngược lại
ta thấy
2000/2001=2000/2001
2001/2000=2001/2002
=>2000/2001+2001/2000=2000/2001+2001/2002
=>A=B
mk nghĩ đề sai vì lớp 6 sao lại có kiểu so sánh quá dễ như vậy
A=2000/2001+2001/2002
B=2000+2001/2001+2002
ta có:\(B=\frac{2000+2001}{2001+2002}=\frac{2000}{2001+2002}+\frac{2001}{2001+2002}\)
vì \(\frac{2000}{2001}>\frac{2000}{2001+2002};\frac{2001}{2002}>\frac{2001}{2001+2002}\)
=>A>B
Ta có: B=2000/2001+2002+2001/2001+2002
vì: 2000/2001>2000/2001+2002
2001/2002>2001/2001+2002
nên 2000/2001+2001/2002>2000/2001+2002+2001/2001+2002
Vậy A>B
không quy đồng mẫu số so sánh A=2000/2001+2001/2002
B=2000/2001+2001/2002
Ta có: \(A=\dfrac{2000}{2001}+\dfrac{2001}{2002}\)và\(B=\dfrac{2000}{2001}+\dfrac{2001}{2002}\)
Mà\(\dfrac{2000}{2001}+\dfrac{2001}{2002}=\dfrac{2000}{2001}+\dfrac{2001}{2002}\)
Vậy A=B
Ta có: \(A=\dfrac{2000}{2001}+\dfrac{2001}{2002}\)
\(B=\dfrac{2000}{2001}+\dfrac{2001}{2002}\)
Do đó: A=B
So sánh A và B, biết: A= 2000/2001 + 2001/ 2002 và B= 2000 + 2001/ 2001 + 2002
ta có:\(A=\frac{2000}{2001}+\frac{2001}{2002}<\frac{2000}{2002}+\frac{2001}{2002}=\frac{2000+2001}{2002}<\frac{2000+2001}{2001+2002}=B\)
\(\Rightarrow A
ta có:\(B=\frac{2000+2001}{2001+2002}=\frac{2000}{2001+2002}+\frac{2001}{2001+2002}\)
vì \(\frac{2000}{2001}>\frac{2000}{2001+2002}và\frac{2001}{2002}>\frac{2001}{2001+2002}\)
\(\Rightarrow\frac{2000}{2001}+\frac{2001}{2002}>\frac{2000+2001}{2001+2002}\)
=>A>B
So sánh:
A= 2000/2001 + 2001/2002 với. B=2000+2001/2001+2002
So sanh
A = 2000/2001 +2001/2002
B = 2000+2001/2001+2002
Ta có:
\(A=\frac{2000}{2001}+\frac{2001}{2002}\) và \(B=\frac{2000+2001}{2001+2002}\)
\(\Rightarrow B=\frac{2000}{2001+2002}+\frac{2001}{2001+2002}\)
Ta Xét:
\(\frac{2000}{2001}>\frac{2000}{2001+2002}\)
\(\frac{2001}{2002}>\frac{2001}{2001+2002}\)
\(\Rightarrow\frac{2000}{2001}+\frac{2001}{2002}>\frac{2000}{2001+2002}+\frac{2001}{2001+2002}\)
\(\Rightarrow A>B\)
so sanh :
A=2000/2001+2001/2002
B=2000+2001/2001+2002
\(B=\frac{2000+2001}{2001+2002}=\frac{2000}{2001+2002}+\frac{2001}{2001+2002}
nguyen thieu cong thanh lm đúng rồi mà
so sánh biểu thức A và B biết rằng ;
A =2000/2001+2001/2001 B=2000+2001/2001+2002
Đề sai chỗ 2001/2001 phải là 2001/2002
\(A=\dfrac{2000}{2001}+\dfrac{2001}{2002}>\dfrac{2000}{2002}+\dfrac{2001}{2002}=\dfrac{4001}{2002}>1\)
B=\(\dfrac{2000+2001}{2001+2002}=\dfrac{4001}{4003}< 1\)
=>A>B
Ta có :
B = \(\dfrac{2000+2001}{2001+2002}\) \(=\dfrac{2000}{2001+2002}+\dfrac{2001}{2001+2002}\)
Vì \(\dfrac{2000}{2001}\) > \(\dfrac{2000}{2001+2002}\)
\(\dfrac{2001}{2002}\) \(>\dfrac{2001}{2001+2002}\)
Nên \(\dfrac{2000}{2001}+\dfrac{2001}{2002}\) \(>\dfrac{2000+2001}{2001+2002}\)
Vậy A > B
Cho A=2000/2001+2001/2002 và B=2000+2001/2001+2002
So sánh A và B
B=2000+1+2002=4003
A=2000/2001+2001/2002
=2002.(2000+2001)/2001.2002
=2000+2001/2001<1
Mà B>1 suy ra A<B